[ASMR] Can I Solve this Math Puzzle Before You Fall Asleep?

[@4l3kis]

My math teacher would say "well how do you know that its a square 🤓☝"

[@ComicallyStupid-t9y]

Well you see teach I actually used the "ligma equation"

[@emilstockmann5543]

Every triangle has a right angle so it has to be a square

[@cjwood9936]

@@emilstockmann5543how do you know 100% that those are right angles?

[@4l3kis]

@@emilstockmann5543 eehm no?! Tf 😂

[@amirmahadeo56]

@@emilstockmann5543 First of all, that wasnt given. second of all, it could have been a rectangle.

[@insevered2730]

You don’t even need z. Since both the yellow and blue triangles have a height of x and the yellow triangles area is 1/2 that of the blue one. We can just put the base of the yellow triangle as y/2 and then instead of x-z we put x-y/2 and then it’s all in terms of x and y instead of another term z

[@xtgamermo2859]

True

[@ASMRMaths]

That's very true! Love this alternative too. Depends what approach to take and how much you like fractions, I guess :)

[@mikivatrogasac4671]

If my middle school prof was this relaxing, I swear I would have every excellent mark...

[@Alex_O.O-uwu]

Your voice is so soft and relaxing omg

[@batesyboy321]

Pretty cool puzzle

[@BetaV3rsi0n]

This problem gets easier the more you think about it

[@WayASMR1]

Really creative idea

[@ASMRMaths]

Thank you! 😊

[@rhyswheelan4145]

Love these math videos ❤

[@cbaileyware4650]

you could have also looked at yellow triangle, 1/2ab=2 so ab=4 so the sides are either 2 and 2 or 1 and 4 but it cant be 2 and 2 as they arent equal so its 1 and 4, 4 squared is 16 and then take away the other areas

[@naoxi1]

What about fractional values like 3 and 1.333?

[@cbaileyware4650]

@@naoxi1 i dont know or care really because they arent in this specific question

[@ASMRMaths]

What Naoxi said is true, there are other values a and b could take in your explanation. But, given the simplicity of the numbers provided elsewhere it is a reasonable assumption to make of 1 and 4!

[@Vic9994546]

Presh tallwalker would approve

[@AntonioColon-rj2wo]

The center is I think 6cm

[@naoxi1]

My way: Uhhh 4 seems to fit well 4² - all the areas = 7

[@Jahaan_G]

How did u write the small 2?

[@ASMRMaths]

Proof by inspection 🤓

[@MajestoPlayZplzsubandwhatch]

²

[@MajestoPlayZplzsubandwhatch]

Hold 2 on ur keyboard

[@BetaV3rsi0n]

​@@Jahaan_GYou hold down two on your keyboard when on phone

[@Woody3687]

i got it in like 10 seconds but i probably made some assumptions

[@WayASMR1]

Yeah I looked at yellow realized it could fit twice, with common knowledge. And I’m only a 5th grader (going into 6th)

[@ASMRMaths]

Awesome!

[@dio8628]

5cm 2

[@dio8628]

Is it?

[@ASMRMaths]

Ooh, close but not quite!

[@NXS_PARADOX]

actually i heard a fart but its relaxing thnx

[@niil047]

uhh 4 seems to work for x, so 4 * 4 = 16, 16 - 2 - 3 - 4 = 7

[@user54840]

I overcomplicated this a lot but: 1/2 * sqrt17 * sqrt13 * sin(70.34617594) = 7cm^2 used pythagoras and simple trig rules for these values coulda done 4^2 - the other areas, but we don't know it's a square