Super Trick : Optically Active / chiral compounds in Organic Chemistry | IIT JEE & NEET

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ATP STAR

ATP STAR

Күн бұрын

Пікірлер: 24
@Shivkumarivishwakarma91
@Shivkumarivishwakarma91 5 ай бұрын
1st & 2nd are optically active compound. 3rd is optically inactive compound.
@Padmag3832
@Padmag3832 5 күн бұрын
Thank you sir ❤ thank you so much
@Its1only
@Its1only 3 ай бұрын
1 st and 2nd are chiral and 3rd is achiral
@JAAT_YTofficial
@JAAT_YTofficial Ай бұрын
1 is optically inactive bcoz pos is present and 2 nd 3 are optically active bcoz in 2nd chiral C present and in 3rd no pos and cos.... Kya ye shi h sir.. Plzz btana
@kshipramalav2047
@kshipramalav2047 5 ай бұрын
Love you sir❤
@RichaRaj-nj6tr
@RichaRaj-nj6tr 5 ай бұрын
Sir 11th or 12th me puche jne wale formula bataye All subject ka
@pawarrishikesh620
@pawarrishikesh620 Ай бұрын
in 3 rd as there is consecutive double bonds so they should not line on same plane so it is optically active ???
@anchitvlogs4738
@anchitvlogs4738 14 күн бұрын
Good question
@Ahmadkhan-uc8jv
@Ahmadkhan-uc8jv 3 ай бұрын
Sir in 1st there is no chiral carbon because there is no different group
@zeenatunnisa632
@zeenatunnisa632 10 күн бұрын
But both c atoms are sp2 and hence planar....tht means plane of symmetry is there
@UnderratedGamer-b5d
@UnderratedGamer-b5d 23 күн бұрын
Thank you sir❤
@atpstarkota
@atpstarkota 22 күн бұрын
Most welcome
@HarshilJain15
@HarshilJain15 19 күн бұрын
1 is optically active, 2 is optically inactive, 3 optically inactive
@aayushixi
@aayushixi Ай бұрын
Please tell why is the first homework compound optically active
@PradhyumnaSi
@PradhyumnaSi Ай бұрын
The compound does not contain pos and cos but here E-Z notation is possible so.........
@pushkargond7407
@pushkargond7407 2 ай бұрын
9th comment is mine
@NaitikJain-mi3tc
@NaitikJain-mi3tc 4 күн бұрын
🐴🐓🐴🐓🥴💩🥱🚻🥺 Samaj Gye
@zeenatunnisa632
@zeenatunnisa632 10 күн бұрын
Ist optimally inactive..coz comp itself is planer. 2nd inactive coz..exactly 1 chiral centre 3rd op active cozin case of mutual double bonds,groups attcahed to c1 and c3 lie perpendicular to one anothet hence no pos and cos.
@AsmaKhatun-t7r
@AsmaKhatun-t7r 2 ай бұрын
1&2 Are optically active...
@aayushixi
@aayushixi Ай бұрын
Why is 1 optically active 🙏
@AJITSihag-s2e
@AJITSihag-s2e 5 ай бұрын
first viewer 😅😅
@SalmonBhaoii
@SalmonBhaoii 3 ай бұрын
😑
@iamahacker2238
@iamahacker2238 2 ай бұрын
111th like 😅
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