Limiting reagent🔥| Mole Concept | Physical chemistry | Class11 IIT JEE & NEET | Anushka mam

[@gamingshaming3357]

I loved the starting example that mam gave to crystal clear the topic of L.R...❤Thanks a lot maam😊😊

[@padmininaik6266]

Mam aap bahat achhe se explain karte hein jo doubt school me clear nahi ho pata wo aap kar dete hein. I am in class 10th icse course Thankyou mam.....🙏☺️

[@lostsonnet4688]

Thanks maam all the concepts are crystal clear 💕💕💕🥰

[@Dish_asharma]

Al=n=2.7/27 =0.1moles N2=n=2.8/28 =0.1 moles Al=0.1/2=0.05 N2=0.1/1=0.1 Al is limiting reagent Molecular weight of AIN =41 2moles of al gives 2 mole of ain 0.1 mole of al gives 0.1 mole of AIN AIN formed =0.1×41 =4.1 grams

[@devanshtyagi5868]

Bro why not we take 0.05 *41 ??

[@sagargabi]

because limiting reagent is Al @@devanshtyagi5868

[@pokemoner_365]

​@@devanshtyagi5868same ques?

[@GourangaDey-tt9rv]

Thank you very much brother

[@nimishgrover7637]

@@devanshtyagi5868it is done just to find the limiting reagent

[@anvitiwari3011]

Superb superb superb explanation ma'am👏👏🤘🤘😃😃💗💗you explained this topic in a very interesting way😊😊😊😊😊😊

[@PriyanshuKumar-cg7ng]

One of the best chemistry teacher on KZbin thanku so much mam

[@Buisnessjio]

Answer of last home work question is 4.1g and the limiting reagent is Al ❤️❤️ B.t.w great explanation mam

[@saisnehapujari]

Can you send a pic / solution for he question

[@thestraightboy4549]

Answer 2×2.05 gram hoga

[@ShortEditZ69]

@@thestraightboy4549 nahi 4*1.025 hoga

[@manojkumarsingh1623]

Kya difference hai ​@@ShortEditZ69

[@AvinashGupta-ln9yk]

Anushka Mam respect button for her concept and theory.❤

[@VishavnoorKaur00]

Thnkuu mam😄 I was finding this topic. Very difficult but it is very simple

[@samikshamishra3587]

Thnku so much ma'am now I get it very well☺️😍

[@ismeet_123]

4.1 gm AlN and limiting reagent is Al , you can take a feel using unitary method in reaction 2mol Al → 1mol N2 1mol Al → 0.5 mol N2 0.1 mol Al → 0.05 mol N2 But we have 0.1 mol N 2 so half of N2 will react and Al will end so limiting reagent is Al , now 2 mol Al → 2 mol AlN 1mol Al → 1mol AlN 0.1 mol Al → 0.1 mol AlN 0.1 × mass of AlN = 0.1 × 41= 4.1g . Thank you mam ❤

[@dna6869]

Thnx 😢

[@adityahonnappagol]

From my initial days of this phase I didn't have crystal clear idea of Limiting reagent and now by your wonderful way I understood completely 😊. The shortcut was also easy to remember

[@topergaming3164]

Aluminium is Limiting reagent and 4.1 g of AlN is formed

[@Myself.282]

Kya samjhati hai mam. Kisi ko bhi ekdam samjh aa jaega. So proud of you mam. We want all teachers in India like you.

[@quandledingleiv6082]

No shit

[@MILKY-it3by]

no shit #2

[@gumball-s4f]

no shit #3

[@Naina-kd4yt]

No shit#4

[@funnybhadrakiatoka1302]

No shit #5

[@Ashita7X]

Anushka mam is truly 🐐 🔥she is amazing teacher ❤️

[@Aanyei]

Ur smile makes more interesting to watch ur video 😊😅❤❤

[@yashwanthnadella]

18:11 for the hw i am getting 5.5 as the 2 in 2AlN applies to both Al and N. does the 2 only apply to Al cuz all the comments say it is 4.1. Can anyone clarifyy…

[@lakshy69x]

Yes I also think so

[@lakshy69x]

I am fully confused why

[@ashuff7209]

Thanks a lot Mam .... 😊😊

[@jiyaaaa08]

Her, "Rrrrrrightt" is so goood. Awesome lecture!

[@vinaysingh-yd4vr]

This mam is my favourite mam and I like her teaching so much .

[@Hi0865]

Ma'am yrr tussi great ho.🥲khushi ke aasu. Apne Mera doubt clear kardiya

[@monikajangid1326]

Mujhe limiting reasent concept hi weak tha...vo bhi aapne pdaya to....strong bn gya..😍😍😍😘😘😘

[@Subhrajyoti-pm3wt]

The ans of the home work is.. 4 . 1 Th L.R. is Al in this question. ... & thank u so much madam... wonderful explanation. .. nw I've no doubt in this part...

[@yaminikushwaha8599]

In homework limiting reagent is Al and AlN is formed 4.1 gm.

[@manishkr278]

The way you taught this topic really awesome. Thanks for such kind of short video for single concept this helps a lot students like me.❤

[@rashidafarooqui8748]

Perfect lecture for limiting reagent I understand this concept ❤️

[@WakeAfghan]

Very Conceptual Example Great.

[@princeshokel1995]

mam 4.1 is the answer of homework question u r teaching very nice keep it up

[@sahilopkhurdi2786]

2.05

[@smutipalai5550]

Nice teach mam I love u mam and love ur teaching tq so much mam for clarification all the subject clearly ❤️❤️❤️

[@atpstarphysics]

It's my pleasure

[@Samridhiverma-n9n]

Thanks a lot ma'am for making our concept clear. Now I will struggle with the questions of limiting reagent

[@pwian2144]

The Answer is 4.1 gram of ALN....😊 Very good session mam.... CRYSTAL CLEAR 👍😘

[@adarsh_0724]

4.1 aayega ya phir 8.2

[@BijayaaPokhrell]

@@adarsh_0724 8.2

[@ZeeshanAli-ll7ur]

8.2​@@adarsh_0724

[@BleshavarSingh-jv4pc]

Nice explanation maam ❤😊😊

[@dhvanitkapadiya1849]

The answer to H.W's question is 4.1 grams... BTW, amazing explanation ma'am. All my doubts are cleared. Thanks..

[@gamerrider3878]

How?? Mine was 4g

[@dipaliprakashahire3684]

Mine also 4g!!!

[@Jaybharate]

How my answer is 0.82

[@sam_2579]

Same.. 4.1 grams

[@AsifHussain-sj4qy]

My answer. 2 grams

[@Commited_Swara]

Now I am getting why Anushka ma'am is famous 🎉

[@niyatithakkar2293]

For me , you are best chemistry ⚗️⚗️ teacher ♾️ forever'

[@SAINA_PARKASH]

Mam answer is 2.05gm ir 4.1 gm

[@pokemoner_365]

Same

[@asgaming3542]

Home work question ka ans 4g AlN formed and Al is the limiting reagent

[@codingpoint7253]

The best explaination video of limiting reagent...i had not understand from any of the teacher the limiting reagents concept...but here i understood all the things ..thankyou so much MAM 👑THE CHEMISTRY QUEEN👑

[@prashantkhatiwada9666]

mam..I searched many vedios but...now my obstacles are clear about limiting reagent..thank u taught nicely with good example at first

[@atpstarphysics]

You are welcome 😊

[@aadityaV13]

"Vedio"? "Obstacles"?

[@sakshitayade2591]

@@aadityaV13 🤣🤣

[@omgggwowow276]

@@aadityaV13 The spelling of obstacles is correct tho lol

[@unlimitedstudyandcraft9990]

@@omgggwowow276 spelling of tha is incorrect....lol😂

[@user-re5yo9dg1k]

mam i love your teaching method 🥰😍

[@Ksharma_Tv]

[18:11] is it *4.1g* ? 🙂 too helpful ty Anushka Ma’am!

[@sanjayg6264]

Kahi se bhi prr lo.. jo dhyan se padta hai usko sab jagah samjh aa jaata hai.. Dhyan se padne se hi sab kuch samjh aata hai... Thank u mam for best explanation...

[@atpstarphysics]

Keep watching

[@Pqrs..54]

I read in aakash kota mam waha se padha but aap unse kafi accha padhate ho.

[@dakshsingh8592]

There’s no other way that can be simple than this one...... You are the right teacher for chemistry ❤❤❤thank you

[@MahipalPanghal-y2k]

Mam this is the best way in whole world to know the mole-concept ❤❤❤❤

[@AadarshDhruv-gf3zn]

Thank you for making my study easy ❤❤❤❤❤❤❤

[@badlainsane8650]

This mam is crystal clear thank you for explaining us

[@AnjaliKumari-gu2fx]

Perfect 👍👍

[@facts..8652]

😊 very best explanation nice mam😅❤

[@PrashantKumar-dd1ev]

4.1 answer of AIN and also thanku mam

[@shaistaparveen5473]

Mam bahut acche se samjh àaya😊

[@Queenrutu03]

Ans of homework: limiting reagent is Al and mass of AlN formed is 4.1gm

[@Anand-ih8vz]

Anyone pls explain... In other problems, we take no of moles of AL as 2 - as 2Al is given. But here we take this 2 as stoich.coeff. it is confusing...

[@Mr_Pinder]

15:47 (half) use earphones

[@azaharuddin8515]

So pretty mam❤❤❤

[@englishmovies5854]

Thank u for such a great concept

[@chahat4340]

Best teacher 👏❤️

[@atpstarphysics]

Thank you! 😃

[@anshika-wf2dp]

Thankyou mam❤❤❤❤

[@GudduKumar-wx6kn]

Its limiting will be Aluminium and the mass of ALN is 4.1gm

[@zzfd-b9i]

🎉🎉 it help me lot thanku 💫

[@lokesh12]

Mam , Plz tell work is extensive or intensive

[@rynongamerz8179]

Mam u r so cute and you explanation is excellent ☺️☺️

[@rynongamerz8179]

Mam can u send ur no...

[@mahimagupta8605]

Mine ans is 2.05 gm Unitary method se 4.1 gm

[@ashishsingerkotarajesthan2905]

Bro not 2.o5 g its 20.5 g 😂

[@Iamathiestexmuslim]

Crystal clear ma'am

[@ankitkumarjha1947]

Thanks ma'am 🥰🤩 aapne Mera concept clear kar diya

[@suhanimodi3899]

fantastic explanation 😊😊😊😊😊

[@princeprincesharma9240]

Your explanation is so good

[@admiregirl..7297]

AL is the limitting reagent...... And mass of ALN formed .....4.1 g💕 Thank you for making it easy 😇

[@safafatima5535]

Kesa aaya answer

[@farwakhan9155]

Exactly and moles of AlN is 0.1 as. 0.1 moles of Al and then to find the mass of Aln we'll multiply 0.1 with 41=4.1g

[@PramodKumar-mm3un]

Hello

[@explosivesky3368]

@@farwakhan9155 can u pls tell me full on insta? Pls?

[@priyankadev8834]

noh answer is 4.1g but limiting reagent is nitrogen

[@discription5991]

Very good explanation 👏 thanku ma'am

[@atpstarphysics]

Always welcome

[@mamtayadav3045]

Now..... new class,new josh , new teacher,new masti but old we 😅😅 Best of luck for every jee/neet aspirants 🌚

[@deepanshi2367]

Crystal clear💖

[@renukasahoopatra4426]

2024 25 batch attendance 😂😊

[@missqueen_29]

Present 👋🏻

[@OHMICFACTORY]

Very fast and efficient with quality content

[@rishalo7246]

Mam ap kitna accha padati hoo....🤭🤭🤭😊😊

[@anshu1815]

Thnq so much ma'am ur vdo is really vry hlpful for me...🙂 Also tomorrow is my chemistry exam😄

[@namankumar8100]

Mam I searched many videos but now my obstacles are clear about limiting raegent thanks a taughty nice alay

[@Ruinveil23]

Abey kya kya bole ja rha hai😅

[@NishantYadav-lc8jy]

Mam you are a good teacher and also very beautiful

[@Smiley.S69]

respect 4mam❤❤❤

[@payalsingh9268]

Thanks ma'am only you have cleared my concept. Thanks alot

[@satyajit260]

Concept crystal clear

[@hemabhatt9623]

Mam can we use this trick in half yearly exam for class 11

[@atpstarphysics]

yes Hema

[@Prakhar_Mahale]

HW ans-4.1g AlN

[@manasvivarada7642]

Tq so much ma'am our school teacher doesn't teach us well but after watching this video all my concepts are crystal clear

[@kuntalsardar8477]

Very helpful.

[@tapanbera590]

Likin ma'am yeha par to hum pehle "B" se bhi suruaat kar sakte hai. I mean 3 mol B jab lagte hai tabh 2 mol A lagte hai. aise??

[@Miss_sharma_here]

Bohot aacha laga

[@VishalChauhan-zl9ff]

Mind blowing mam🙏💥💥

[@tahashaikh5727]

A very good session of physics, I wasn't distracted even for a second

[@sastikanandi1063]

it was chemistry friend.

[@namanjasrotia2911]

@@sastikanandi1063 😂

[@comedyvideos8346]

It's chemistry.....😒

[@atpstarphysics]

Keep Loving Btw it was chemistry 😁

[@tahashaikh5727]

@@atpstarphysics Oh, was it? Sorry I was lost in your eyes

[@harishchandra973]

Thanku so much mam Aapney jo car se start kiya vo bhaut hi accha tha thanku so much mam

[@editz_kishor-3]

AlN :- 41×0.1 = 4.1g ans

[@priyanshukumarthakur2965]

Mam the answer I am getting is 2.05 gram, coz I took stoichiometric coeffient =2, how everyone is getting 4.1 gm, why we need to took 1 value for SC,?? Can anyone explain pls?

[@abhisheksangwan1066]

Finding limiting reagent - For Al 2.7/27×2= 0.05 For N2 2.8/28 = 0.1 Hence Al is limiting reagent. If 2 moles of Al gives 2 moles of AlN than 0.1 moles will give 0.1 mole of AlN. 0.1 ×(41)=4.1

[@priyanshukumarthakur2965]

@@abhisheksangwan1066 tysm bro 🙏💯❤️ Understood

[@namitrai4154]

Thankyou so much maam for explanation ...

[@atpstarphysics]

Most welcome 😊

[@FactifyAkash]

Amazing 😍 mam

[@pratyashasahoo3080]

I am preparing for NEET in Aakash institute.But I can't understand this concept.This video is really very helpful for me.Thank you so much ❣️

[@SahilSingh-jx7lc]

Aapka AIATS hoga isliye aap ise dekh rhe ho

[@AIIMSdr-u4y]

Same

[@AnuragTiwari-qb4ft]

Same

[@muskanchaudhary7234]

I am also preparing for NEET in Aakash Institute

[@muskanchaudhary7234]

In which branch are you studying in Aakash institute

[@prashantstreamrs]

Mam what is answer of that given questions Please send me the answer

[@tanvirewatkar8565]

Answer is 4.1 as lr is al and mass of aln is 0.05×82👍🏻💯

[@sahibakhan1311]

Can we calculate the amount of moles from the mass in kgs too ?

[@livinglegendwr8618]

no actually

[@anjalirao5928]

Ma'am lm science and fun ashuu sir student and I love you sooooooooooooooooooooooooooo muchhhhhhhhhh ma'am ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉 really mam ....anushka mam ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ Exam are near Nothing is clear Students is fear I have not fear Because...our chemistry queen is here ❤❤❤❤❤❤❤ANUSHKA MAM ❤❤❤❤❤❤❤❤❤❤❤❤❤

[@Kanishk_singh258]

Shut up man

[@deepaknavik1441]

Limiting reagent is (Al) and mass of AlN is 4g

[@azizkhanwazir3187]

Mam amazing teachs the chemistry ❤