August 2024 Digital SAT Prep: Tutor Solves the 10 Hardest Math Questions on the DSAT

Do you think you have what it takes to solve the hardest math questions on the Digital SAT? For this video, I’ve collected 10 of the hardest math questions to ever appear on the Digital SAT. These questions are drawn from various domains, from Algebra to Advanced Math to Problem Solving & Data Analysis, but all of them have been rated a 3 out of 3 out of 3 in terms of difficulty by the College Board, and I’ve seen a lot of students get them wrong in my classes. However, you don't need to be a genius to solve them. In this video, I'll show you how to use DESMOS and other shortcuts to locate the correct answer with speed and confidence. Using these methods, many of the students I teach have gone on to earn scores of 800 on the Math Section and 1600 overall. If you want to maximize your performance on the Digital SAT, this is the video for you.
Follow me on Instagram for more DSAT practice questions: @ivyleaguementorsprep
For additional resources, visit my website: ivyleaguementorsprep.com/
About Me:
My name is Nathan Greenberg. I'm a graduate of Brown University and Phillips Academy Andover, with 15 years of experience in test prep and college admissions. I've helped thousands of high school students improve their GPAs, earn high marks on standardized tests such as the SAT, ACT, and AP, and get accepted at the most prestigious and competitive universities in the world including Harvard, Yale, Princeton, Columbia, Brown, Cornell, U Penn, Dartmouth, Stanford, MIT, and more. I founded Ivy League Mentors to make my knowledge and experience with students looking to make the most of their education, wherever they may be located.
If you are interested in private tutoring via Zoom, please reach out to me directly via my website: ivyleaguementorsprep.com/cont...
#sat #digitalsat #dsat #satprep #sattips #sathacks #satstrategies #digital sat prep #satmath

[@leyla._.3257]

THIS MAN IS SO USEFUL! THANK YOU A LOT!!

[@gabrielanowicka9102]

this is so good, thank you so much!!

[@vxjaguar25]

Definitely not me reading f(-9) = f(3) as f(-9) = 3. Lol spent quite some time scratching my head on that one, silly me

[@YasminaMuzaffarova]

You're the best thanks a bunch

[@kathrinewells9072]

Thank you. Soooooooo much!!!

[@wishes2nite]

So helpful! Thank uuu

[@kiranpaudel5191]

thanks

[@LC95297]

(23;8)is the vertex.. of f(x)+4. So the vertex of f(x) is (23;4) and then f(0) is -4(-23)²+4= -2112.

[@davidkosata3051]

cool, how much time do you have for these questions on the real test?

[@alepixys9907]

32mins for 22questions each module

[@leyla._.3257]

@@alepixys9907 it is almost 35 mins, not 32)

[@ivyleaguementors]

On each module of the math section, you'll have to answer 22 questions in 35 minutes. That's a little over a minute and a half per question. However, keep in mind that the easier questions can often be answered quickly, so you'll probably have more time than that for the hard questions like these.

[@ivyleaguementors]

That's right. 35 for math, 32 for reading & writing

[@creedscorner]

For the vertex form problem, don’t you need to subtract four from all the terms since f(x) is y-4?

[@ivyleaguementors]

That's right. In this case, I just did that step at the end, but you could also do it earlier on.

[@dagmadera5810]

I still believe that the answer for question number 9 is C. I cant understand why It is B

[@mellaza]

if you assume that a=-7 and b=5 like he does in the video, when you plug those numbers in for C, you get 14/5 as the slope, which is not the negative reciprocal of -10/7 and therefore not perpendicular

[@ivyleaguementors]

Yep, that's the right explanation

[@TheSatSlayers]

6/10 ugh

[@ivyleaguementors]

That's actually not bad considering that these are among the hardest questions out there, and you'd only get a couple of questions this hard on a real test.

[@akshajv6093]

I believe for #2 it should he b-12 not b-13

[@ivyleaguementors]

I think you're forgetting the first term in the equation. When we plug in that point, we get -75/7 = -a^0 + b - 12 Since a^0 will equal 1, no matter the value of a, this can be reduced to -(1) + b - 12, or b - 13 I hope that helps.

[@VincentNguyen-ov4ox]

you talk like a preist

[@ivyleaguementors]

haha thanks