Average Normal Stress Example 1 - Mechanics of Materials

[@brentcallender5786]

thank you so much, im usually lost in my lectures but i just watch the videos on your page and its clear

[@tomasleszczynski3877]

Awesome video. Spent 5 hours trying to figure out why my examples didn't factor in all forces on both left and right side. You made it pretty clear right off the bat. Thanks

[@UristVonUrist]

Thank you for the awesome series. Helps me a lot since I have trouble paying attention in class

[@lalitajoshi5350]

Thank you Professor!! :) from thousands of students and learners!

[@hussienheikal6761]

you are way better than my doctor , thank you

[@fung2520]

Thank u after i see the video i pass my structure exam :)

[@asb7880]

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[@structurefree]

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[@viz192]

Hi structurefree! You are my awesome virtual lecturer!

[@structurefree]

+Vinson Intar ha! thanks!

[@emmareyagudo908]

keep doing this vids man! it helps a lot thanks

[@Iamjcowell]

Thank you for your videos. They help massively!

[@popedope4842]

Wow! This really helped me a lot. Thanks man. U earned my subscribed

[@ahmedismail4743]

Shouldnt N (ab ) be the opposite side i mean opposite to the applied force?

[@tomt8691]

Where does he get (Pi/4)*d^2? Answer: We know that Area of a circle=Pi(r)^2.But in terms of diameter, Area=Pi(diameter/2)^2=Pi/4*(diameter)^2,by factoring out (1/2)^2=1/4. Proof: Using the radius: Area=Pi(r)^2=Pi(10)^2=100*Pi=314.16.(radius=diameter/2=20/2=10) Using the diameter:Area=Pi(d/2)^2=(Pi/4)*(20)^2=400/4*Pi=314.16. Make sense?

[@alifikmal4955]

can we always use this formula to solve this type of question?

[@pouchirory]

You can only use (Pi/4)*d^2 to calculate the cross sectional area if the area in question is a circle (which it won't always be)

[@zaidobaid3691]

or divide the diameter by 2 to get the radius, then use the circle area common equation which is "pi(r)^2 " @@alifikmal4955

[@ScholarStream_25]

In sectional method we have to cut the object in between (center) or any where on the object???

[@ndlovukazim318]

why does the segment BC look like the whole thing? I thought it would have the force Nab in the same direction as 20kN on the LHS instead of 5kN

[@abersuwem7449]

so i punched in the values for the stress on Nbc on my calc and did no get the same answer as you. Could there be a mistake somewhere?

[@AVtrails]

thanksssss alottt!!! uare awsm teache!!! helped a lot...will recomend to all my frnds

[@structurefree]

I appreciate the kind words and sharing.

[@andrejsgelins9296]

Where does arrow with plus sign under head, before sum of forces came from? what does it mean, and for what reason is it with plus sign, instead of, minus? Because of what is it necessary? Thank you for highly interesting resources!

[@DamianSupra]

great videos i'm going to watch them all

[@yamilethovalle5988]

how are you getting 50mm when you begin solving for segment BC

[@jacobhouston1655]

I don't understand why you made the cross section cuts in the places you made them at. Please explain why.

[@_s_p_a_r_k_e_s_7615]

Your videos are awesome mate!

[@alifikmal4955]

great video. keep it up man

[@MrAlbashiri]

thank you for the amazing video.

[@structurefree]

The area of a circle is (pi/4)*(diameter^2) = pi*r^2

[@changeyourmood8710]

Please provide other solved problems related to other Types of stresses i.e Shear , Bearing , etc . thank you !

[@structurefree]

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[@changeyourmood8710]

@@structurefree Grace !

[@urgayl0l]

are we always going to assume that "N" is in tension? how do we know when the arrow is going to tension or compression?

[@mainuddinjubair3737]

sir, in practical life how do we have to use this shear stress. I mean where it would be needed to find out and why

[@alexandrekikvidze2060]

Thank you sir you are awesome very useful

[@elta3607]

thanks it really works for me

[@naimkhannikmal9630]

great job

[@avashfulful]

Hello Sir, Can you please do a video on Shear Force, Axial Force and Bending Moment of some kinds of Frames, about 2-3.

[@Mahmood367]

why did u divide on 4 for the are isn't it suppose to be 4*pi*r(squared) the sphere area.

[@viz192]

Nope. The formula is 1/4 * pi * d^2 or pi * r^2

[@ashenediriarchchi5115]

shouldnt the mm be converted to m?

[@structurefree]

Ashen Ediriarchchi you don't have to since 1 KN/mm^2 = 1 GPa

[@ashenediriarchchi5115]

ahh got it :) thanks

[@radiusbecka1799]

Thanks! Super helpful!

[@Sea2Skyward]

great stuff man really informative

[@abdiwalihussein3466]

thanks alot man i really appreicate your help

[@yamalmansour7688]

can u Please explain how he got Nbc = 15 kn ?

[@435iak]

Thank you!!!!

[@elmiamin2166]

how did he get pi/4(d)^2

[@structurefree]

+Elmi Amin It's the area of a circle when using the diameter.

[@zedspikeful]

THank you so much

[@DushyantDeshwal]

Nice !

[@budzlight6888]

Why is it tension is it compression?..

[@jescor4459]

Don't understand how you're getting (pi/4)*diameter for the cross sectional area

[@aerostructures814]

that is great

[@DaMaestroX]

thanks thanks thanks

[@kimraehun9413]

hi.. is the forces to the right always positive?? I used ur process in one of our teacher's example and now I'm confused 😂😂😂😂

[@royglenreyes9639]

its just a standard you can set eitherway. so when you assume the direction of the internal forces and get negative values you'll know that it they should go the other direction. see that N=-5, negative means that N should go to the the other way.

[@kimraehun9413]

Roy Glen Reyes LOL. i get it now. THANKS A LOT! 😄😄😄 Ur video helped me so much durinh my midterm exam in Mechanics. 😄😄😄 Keep going. Love ya!!! 👍👍👍👍👍

[@Mahmoudnasereddin]

thanks alot

[@gopalkulkarni402]

i was wondering how the normal stress diagram would look like!?

[@AhmedMohamedP]

gopal kulkarni i think there is no normal stresses !