Average Rate of Reaction

How to calculate the average rate of reaction from a graph or molar relationships. Examples included.
Instagram: Lean.Think
Website: LeanThink.org

[@mbuc4498]

I have my chem 2 exam tonight I almost failed chem 1 but these KZbin videos saved me Thank you!!

[@OldSchoolChemistry]

Hi mbuc, I am SO proud of your extra effort and work to learn and succeed in chemistry. Great job watching extra videos. I hope you ace chem 2!! :)

[@megandaly6970]

your videos are AMAZING! Coming from someone who is retaking chem II right now. THANK YOU!!!!

[@OldSchoolChemistry]

Hi Megan, I’m glad they are helpful. I’m so proud of you for retaking the class. Good luck!😊

[@nidhinair5227]

Thank you for this. The playlist for rates is an absolute gift :) I'm really enjoying chem because of you so thanks!!

[@OldSchoolChemistry]

Hi Nidhinair, that makes me so happy! Thank you for letting me know. I am proud of your extra efforts. Well done!

[@mitsu7737]

currently self-studying chem. very helpful video!!

[@OldSchoolChemistry]

Hi Mitsu, I am so glad. I am proud of your for self-studying chemistry! :)

[@MelissaVelez-i5z]

Your teaching methods are excellent. You make sure to provide information on any possible gaps people might be confused with. AMAZING!!!!

[@OldSchoolChemistry]

Thanks Melissa:)

[@MelissaVelez-i5z]

Do you have videos with reaction order questions involving percentages? Again, Thank you soo soo much!@@OldSchoolChemistry

[@kylealfonso8396]

thank you sooooo much for this. this whole play list actually

[@OldSchoolChemistry]

Hi Kyle, I’m so glad it was helpful. I hope your class goes well!!😊

[@kylealfonso8396]

@@OldSchoolChemistry I really seem to understand your work and explanations. Thanks a million

[@DJDelf_]

THANK YOU for condensing my 2 hour class into 12 minutes! 🙏

[@OldSchoolChemistry]

Hi Danny, that makes me so happy. I hope the class goes well:)

[@emanmustafa6351]

Thank you from Egypt ❤❤❤❤

[@OldSchoolChemistry]

Hi Eman, You are very welcome. Many blessings to you in Egypt!!

[@camilamolina499]

I was slightly confused on why the rate at which N2O5 is consumed is equal to the rate of oxygen and NO being formed and why you used the reciprocal too. In addition, I was wondering if we are also supposed to use the reciprocal coefficient if there is one ( I know though in this case the coefficient was 1 but I wanted to know what would happened if lets say it was 2 or something else. )I also wanted to double check that the reason why you have added a minus sign is to make the negative rate of N2O5 positive. Is that correct?

[@OldSchoolChemistry]

Yes, to your last question. If the coefficient is 2 then you put a 1/2 in front of the rate. I hope that helps. Thanks Camila!

[@زهرهبركة]

Thank you

[@OldSchoolChemistry]

You are very welcome:) I hope your class goes well!

[@Adventure_fuel]

What are the assumptions about the way these reactant are in contact with each other?

[@OldSchoolChemistry]

Hi Yosef, it is assumed the reactants follow the collision theory. I hope that helps. Thanks:)

[@isabellamt4]

Thank you!!!

[@OldSchoolChemistry]

Hi Izz, you are welcome! I hope your class goes well:)

[@harryblu1375]

You are so cute . I am 17 but i feel like ❤❤❤ and it was help ful thank you

[@ayandankosi5702]

how did you get the 1/2 ( half) for oxygen when you were balancing the equation?

[@OldSchoolChemistry]

Hi Ayanda, There are 5 oxygens on the reactants side and 2NO2 had 4 oxygens on the product side. 1/2 times O2 gives 1 oxygen. So 4 oxygens + 1 oxygen on the product side equals 5 oxygens total on the product side to balance the reaction. I hope that helps! Thanks:) Please subscribe if have not already!

[@ayandankosi5702]

@@OldSchoolChemistry Thank you very much. It makes sense now😁

[@sammieloney2162]

you slay

[@OldSchoolChemistry]

High praise indeed - thank you;)