B. M-arrays | Codeforces Round 708 | MATHS | CODEFORCES | CODE EXPLAINER

[@kunalsingh6961]

Awesome explanation 🙌

[@prasadpatil9105]

This is the best explaination i have ever seen

[@codeExplainer]

welcome. Keep coding and keep learning.

[@saurabh.gupta22]

best Explanation👏

[@codeExplainer]

Glad you liked it

[@GauravDuseja-t6q]

Nice explanation

[@codeExplainer]

Keep watching

[@bhargavannem3960]

I watched a lot of other videos on this and your explanation is the clearest and helped me a lot. Thank you so much!

[@valeesi]

Completely agree. Very well explained. Thank you!

[@codeExplainer]

Great to hear! . Keep supporting and keep learning.

[@shreyasingh1258]

@@codeExplainer trulyy! you have a way with explaining things and simplifying them! helping us a lot

[@akashjain4281]

Precise explanation!✌

[@codeExplainer]

Glad it was helpful!

[@prateeksomani5803]

Why we are choosing counterpart of x as m-x. For example if x = 13 and m=5 then m-x = -8 but 13%5 = 3 so we need 2 but m-c gives -7 . So it should be m-(x%m) or m-x is correct ?? Please tell if I'm wrong

[@NNELATURIASHOKKUMAR]

Nice explanation sir waiting for upcoming contests videos too.

[@codeExplainer]

sure, more videos are coming soon.

[@nidhishprasad2506]

Why we are not checking m-i.first

[@AnkitKumar-sz5wu]

If we do so then we would calculate the same values twice. Let m = 8 , i.first = 2 then we would do the calculation once for (m - i.first) = 6 but if we calculate for (m - i.first < i.first) then we would do the same calculation when i.first = 6 since then (m - i.first) would become 2. This happens because he is updating the value of references a and b but not the actual values in the map.

[@nidhishprasad2506]

@@AnkitKumar-sz5wu Thanks for clarifying.

[@UMEMrinalAnand]

1491 C pekora and trampoline

[@sohanursohan2426]

would u please provide the solution of E1 of these contest.

[@Anonymous-pj2mv]

Is there any use of second condition

[@codeExplainer]

ya maybe it is not required, u are right.. thanks

[@Anonymous-pj2mv]

@@codeExplainer thx bro for confirmation :}

[@satyamsrivastava9034]

your code is only self explainatory...

[@codeExplainer]

thanks brother..

[@harshgupta3301]

bhaiya ek doubt hai ki a=a-(b+1)kaise likha aapne ?? ,usme thoda confusion hai :(

[@codeExplainer]

a=a-(b+1) ka reason hai , i have first check which is bigger a or b , and if found out a is bigger , which means occurrence of a is large , and thus we can form an array with alternative a and b, and because a is larger we can put the numbers like abababa.. and so on , so in that array which we will form by alternative a and b, so for lets assume we have 3 b's we can put abababa , and thus we have used b+1 a's , and thus this number of a's are used in the original array , and the rest of a's which are left , have to be inserted in separate array , and thus how much a's are left a=a-(b+1) , i hope this helps.

[@harshgupta3301]

@@codeExplainer ohhh ,bilkul clear ho gaya ab , thanks a lot bhaiya :)