Balancing Chemical Equations

[@youngmik9534]

thank you for being a real chemistry teacher, now i'm not confused

[@Edusetucbsespeedmaths]

Every Topic is equally easy when concepts gets cleared.

[@rinyeongi6322]

@@Edusetucbsespeedmaths but school system doesn't understand that :/

[@calanonash]

In 7 videos of under 5 minutes each I managed to understand chemistry better than I did in 7 years of school. Thanks, Dave.

[@darrenmeyers5271]

This teacher is brilliant, well organized and articulate! Lessons are concise and direct. Thank you Professor Dave!

[@RayaanDanish]

fr

[@psychologycontact9921]

My first time here. I am loving your channel like maaaaad! Thank you so much you real human angel.

[@idealthinker101]

I wished that my school teachers also taught me this way !

[@hanumavattem3106]

I wanna meet you and thank you for all of your videos with each and every atom in my body..

[@oregonvulture]

Holy shite, I got my associates degree 10 years ago but I failed introductory CHEM. I'm going back for a transfer degree in fall so I'm preparing for preparatory CHEM and MTH. I never understood balancing equations but I just did all of the practice questions right. Thank you, Professor Dave 😭😭

[@sharmaineizar6276]

I'm glad I found you! you explained it god damn well. I felt so dumb in my Chemistry class before, but now I get it thanks to you!

[@josephfarace6633]

i have a exam in 2 days and i just wanted to say you taught me like everything in the world and i love you so much like bro words cannot explain how happy i am right now like i feel like a whole new person the knowledge i just gained is unmatched your literally a genius

[@kayk2631]

Thank you! I missed two days of school and this helped me catch up in 4 minutes! You're a really great teacher!

[@jamesbas5209]

I haven't looked at the comprehension answers just yet because I want to workout the questions on my own before checking if I am right or wrong. My question lies with #2 AgF + CaCl sub 2 -------> AgCl + CaF sub 2 When balancing this equation, why does F fall off of Ag and become a part of Ca with two atoms?

[@ProfessorDaveExplains]

to understand this we must understand ionic bonds and ionic solids! this will all be revealed as you move forward, in the tutorials about the chemical bond, intermolecular forces, solutions, etc.

[@johnmayes9649]

The reason F falls off of Ag and becomes part of Ca is because F is more attracted to Ca than Ag. The Ca, which is Calcium, has two electrons that it gives to F. The only problem is, F would love to accept one electron from Ca but not two. The solution? F goes and gets another F to join him and the two F's each keep one electron from Ca. They now become a team of three: One Ca and two F's. This is what happens in chemical reactions, they change partners.

[@bait5257]

@@ProfessorDaveExplains how can we do the comprehension no. 4?

[@gdaymates431]

@@johnmayes9649 they sound like swingers. Haha

[@ryderb.845]

This is the only channel that doesn't feel like it just gives me a half-assed explanation, it only gives me information overload

[@julenecoetzee8748]

thank you so much!!! I had literally no idea what a balanced chemical equation was or how to do it and its really important cuz I am in grade 10

[@liquidtompls5666]

Thanks dude, I have a bad science teacher, now finding this I am finally getting it!

[@gamergirlnatalia6715]

Thank you chemistry Jesus lol

[@Claudius_Ptolemy]

I finally understand how these equations work, thank you very much for this lesson Professor! :)

[@ShutterbugVideo671]

Your explanations make a lot more sense than my chemistry classes did in high school or in college!!

[@mememe7495]

Your videos are so helpful! Thank you!!

[@jamesciava05]

thank you Jesus

[@ethangoggin9874]

fuck I'm an idiot holy fuck

[@patatatatatata]

Professor Dave thanks for the video! However, what about equations that have ions as reactives or products, how do we balance the electrical charges.

[@ProfessorDaveExplains]

check out my tutorial on balancing redox reactions

[@patatatatatata]

@@ProfessorDaveExplains thank u so much Professor 🖤

[@RapidBlindfolds]

the way the coefficients were written differently at 1:11 confused me, with one of them in front in normal text and the other behind in subscript, but now i understand its because 2Na represents 2 sodium atoms hanging out, whereas 2 chlorine atoms come together to create a covalent bond.

[@deadpiratetattoo2015]

I might be a nerd, but balanced equations and dipole moments, angstrums and the like was my favorite. But, I also like the old style chemistry names and stuff.

[@Parfaitt401]

u dropped ur crown king

[@3runjosh]

I thought I was just a stupid person with a failed brain and maybe I was but in 2 minutes I was able to learn how to do this and get them all correct except number 4. Thank you, there is hope for me. Back in 2002 when I was 13/14 years old I just couldn't understand this.

[@jhelseaamarixe4475]

Hi. I find #4 in comprehension confusing. Is there a trick for that?

[@devikagopakumar8906]

Did you get it? Hope you did but I am showing you anyways(there is no trick btw) H3PO4 + KOH ----> K3PO4 + H2O H - 4 | H - 2 P - 1 | P - 1 O - 5 | O - 5 K - 1 | K - 3 ( have this in your mind or jot it down , you don't have to correct anything in the main equation yet, first we are gonna figure out the numbers to be written in the eqn.) 1. H first. Not balanced. 2. Then P . Its 1 on both sides. Balanced. 3. O. Okay.... 4. Finally K . It is 3 on the product side. We have to make the reactant side also 3. There is only one way. We write 3 on the reactant side. ( KOH changes to 3KOH) Current eqn : H3PO4 + 3KOH -----> K3PO4 + 3H2O 5. Okay..now return to H. (See the current eqn)We've got total six H in the reactant side( Three H of H3PO4 and 3KOH) And also six H in the product side..... 3H2O (3×2) H balanced:)) 6. Now we have O. There are seven O in the reactant side ( four in H3PO4 and three in 3KOH .. 4+3). And also seven in product side.( four in K3PO4 and 3 in 3H2O....4+3) O is balanced. [ Just like that . You don't have to write the figures at first, estimate them and keep looking ] Therefore balanced eqn:)) #4)H3PO4 + KOH ----> K3PO4 + H2O H3PO4 + 3KOH -----> K3PO4 + 3H2O

[@-_wkwyy]

@@devikagopakumar8906 Thank you man

[@devikagopakumar8906]

@@-_wkwyy You're welcome bro...

[@12bucklemysh0e]

no one: me, dancing to the music at 3:29: 💃💃

[@shashwatsrivastava5348]

I just love ur videos professor

[@stackattack7]

C3H8 + O2->3CO2 + 4H20 dealing with oxygen there will be 2 on the left and (3×2=6 + 4×2=8 so 14 not 10) or am i missing something because when you said 4×1 i was confused where you got the 1?

[@stackattack7]

Nevermind...... i realized i was looking at hydrogen not oxygen haha

[@thaddeusgroup3655]

Wow! professor Dave, you are a life saver. I understand balancing equation for the first time in my life. God bless you.

[@DemonCici]

HE TAUGHT IT IN 3 MINS!?!?!? dude this took like 2 weeks in high school... thank you so much!

[@FrancesObeleEbubechukwu-yz7po]

Thanks soo much professor Dave🥰🥰 I cannot believe that I can now solve and understand Balancing Equation Thanks you soo much,am forever grateful God bless you 🙏🙏🙏🙏

[@eelio8469]

...I don’t get it. How do you expect us to know what you just unbalanced if your not going to immediately check on it? I need to do that or I’m going to forget. If I unbalance something I will immediately fix it idk what I’m doing wrong

[@carultch]

I recommend a linear algebra approach. Assign a variable as the coefficient of each molecule. Go in alphabetical order, and use lowercase letters. Set up a system of linear equations to equate the population of each element's atoms on both sides of the equation, and solve by your algebraic method of choice. Assume the first coefficient a=1, so that your number of equations matches your number of unknowns. From time to time, you will get fractional coefficients with the above method. This is not acceptable as an answer in Chemistry, because you can't react a fraction of a molecule. Therefore, you then have to multiply through to clear all the fraction denominators. Find the least common multiple of all the fraction denominators, and multiply through by that number. You will then have the smallest possible group of whole number coefficients that balance the chemical equation.

[@fabriziom2661]

What would be the best way to balance longer chemical equations? Is it just seeing the needed number with more practice?

[@ProfessorDaveExplains]

yes i think just repetition! you start to get an intuition for which element to balance first and what not. also check for polyatomic ions, those can be balanced as a whole, without having to split them up into elements.

[@carultch]

I recommend up setting up a system of linear equations to do it. Assign a lowercase letter as a placeholder for each coefficient, and go in alphabetical order for each molecule you have. Tally up the number of atoms for each elemental species, in terms of your coefficients. Assume the first coefficient a=1. Then solve the system of linear equations, just like it were a math problem. Matrices can help when you have numerous equations. It is likely that you will get fractional coefficients, and when you do, this just means you need to multiply a by the least common multiple of all the denominators, so that every coefficient becomes an integer. For instance, given the burning of Isopropyl alcohol: C3H8O + O2 -> CO2 + H2O Assign lowercase letters as coefficients: a C3H8O + b O2 -> c CO2 + d H2O Equate counts of each elemental species on each side: Carbon: 3*a = c Hydrogen: 8*a = 2*d Oxygen: a + 2*b = 2*c + d Assume a = 1 Solve for our unknowns: a=1 b=9/2 c=3 d=4 Because we got a fractional result for b, i.e. 9/2, we have to multiply all of the above numbers by 2, to make them all whole numbers. Our balanced equation becomes: 2 C3H8O + 2 O2 -> 6 CO2 + 8 H2O

[@tlhe_ovIyloS]

In case you don’t know, CxHy+(x+y/4)O2=xCO2+(y/2)H2O

[@lakishaberry7250]

Thank you professor Dave! You are the best teacher for everything.

[@redness4815]

My chemistry professor made this sound so confusing. I completely understand the concept thanks to you!

[@KanoBoom]

0:50 Correction: NaCl is a ionic 'compound', not a molecule

[@ahmedshamree677]

Prof What about the hydrogen produced by OH- and H+

[@euphoria_iq]

can someone exlpain number 4 of the end checking comprehension questions bc i do not understand that one

[@cozypunk2613]

i'm love u,saved mi life

[@kelman9192]

truly sent from heaven

[@gabrielmcpherson5756]

Professor I still don't understand. Can you please explain more in depth

[@carultch]

You cannot create or destroy atoms, by ordinary chemical means. You also cannot change the elemental species of any given atom. What we do is tally up each element's atom on each side of the chemical equation, and apply coefficients to the front of each chemical formula, indicating that we need at least that many of that molecule, in order to get a full reaction. Consider the burning of octane gasoline in oxygen. C8H18 + O2 => CO2 + H2O We apply placeholder letters as coefficients to each formula: a C8H18 + b O2 => c CO2 + d H2O Set up a system of equations to solve for a, b, c, and d. Assume a to equal 1. We'll scale up the coefficients if we get fractional values. Carbon: 8*a = c Hydrogen: 18*a = 2*d Oxygen: 2*b = 2*c + d Set a=1, and solve for b, c, and d: b=12.5 c=8 d=9 Since we end up with a fractional value for b, this means we need to set a=2, and double each of the remaining coefficients. All the coefficients need to end up as a whole number, so it has a real life significance, since you can't react half of a molecule. a = 2 b = 25 c = 16 d = 18 This means our balanced equation is: 2 C8H18 + 25 O2 => 16 CO2 + 18 H2O In English, this would be read aloud as: "Two molecules of octane react with 25 molecules of oxygen gas. The reaction yields 16 molecules of carbon dioxide and 18 molecules of water vapor."

[@gabrielmcpherson5756]

@@carultch thanks it is s much clearer now.

[@cinammonrollss]

Short videos and meaningful loved them

[@bogboyz]

idk if you still answer questions on these but how come in the last example you only used the coefficient of water molecules (the 4 in 4H2O) and multiplied by 1, when you used the coefficient and exponent for carbon dioxide (3•2)??

[@HyperTheKappa]

Not to be a nerd but balancing equations was some of the most fun I had in school

[@lochanshivaram6079]

How do you even approach the 4th problem?

[@Calviinx]

Science is traumazing

[@ZallyAimro]

No, it's beautiful

[@Juandraym1]

I think I've figured out my problem. What is the meaning/purpose behind this balancing? In regular math you have an equation you figure its sum at the end; or you're solving for a specific variable. What the hell am I doing this "BALANCING" for?

[@ProfessorDaveExplains]

conservation of matter

[@0hajar]

Thank you for every think 💛 really you are great teacher...

[@OfentseKhoza-vp9go]

Thanks now I can balance chemical equations

[@emily-le6tv]

Explains sooo much better than mrs charlesworth. Are you a teacher at school?

[@ProfessorDaveExplains]

not anymore, focusing on science communication!

[@rochelroma180]

thank you po! 😊😊❤️

[@triple_gem_shining]

balancing chem equations is fun! neat littlte puzzle

[@Rico-Suave_]

luv your videos, you did a great job of organizing the topics, had a question, I never understood why does burning(fire) only involve oxygen and not nitrogen which is also in the air ? I guess I don't understand fire

[@carultch]

The triple bond of nitrogen is a lot more energy intensive to break, that most of the nitrogen gas in the air is just a spectator gas to the fire. There is about as much nitrogen in the exhaust as there is in the original air. Some of it is consumed to make unintended products of combustion like NO and NO2, but most of it remains in its original compound of elemental nitrogen N2. The nitrogen gas might as well be an inert gas, for most chemical reactions.

[@jamesbas5209]

Nevermind. That's the chemical reaction, right? I'm just not fully understanding how to balance these equations. I'm going to keep replaying the video.

[@codieanneedwards]

Yes I keep replaying too, and I’m still confused

[@angelicamaymartinez990]

Thanks for this! I easily understand our lesson now

[@oliverlopez4236]

Why when balancing some polyatomic ions, they disassemble ?

[@ProfessorDaveExplains]

not sure what you mean!

[@gamerdonuts5633]

what is going on i need therpy plz help me

[@undefined888]

Can you call sodium chloride a molecule? Im confused - thought they were ionic bonds

[@setonix9151]

Uhm is this a joke or your actually wondering. I'm uncertain because of your profile picture.

[@setonix9151]

I'm assuming you should already know because of your profile picture, but to still answer the question : no. I wouldn't call NaCl a molecule.

[@undefined888]

@@setonix9151 sodium chloride is not a molecule, It is an ionic crystal. We write it as NaCl because they bond together 1:1. I am pretty sure that this video is wrong about that.

[@undefined888]

@@setonix9151 it is a joke lol

[@setonix9151]

@@undefined888 i did just say I wouldn't call it a molecule Edit : and I used NaCl because I'm lazy

[@pljeskavica13]

well thanks dave

[@atoz4399]

This is a great channel.

[@vamp5417]

Thx for the help man 😇

[@hanzsintim]

This is so easy when you explained it

[@josefonseca6772]

Thank you chemistry jesus

[@borttorbbq2556]

Immediately to something I have no idea magnificent

[@borttorbbq2556]

Okay scratch that I am familiar with it. But still better understanding is better regardless

[@amukelanimoema5117]

thank you professor Dave u saved me thank u thank u thank u ❤❤❤❤❤❤

[@TYD20]

Thanks Professor Dave

[@genevieveschmitt6304]

hey shorty how old are you?

[@Yasumui]

15

[@sidepocketjonas]

162

[@cbmobile1797]

95,587 hailed from the Mesopotamia lands

[@organic_angel]

Thank you

[@kiancanale3449]

Thank you, Sir Dave!

[@genevieveschmitt6304]

one more button please

[@Jnrlionndogg]

it kinda looks like he is reading off of something lol but he is great

[@Sorrytosay792]

that's good explaination

[@thesandwich7151]

Thank you so much professor Dave.

[@amani5953]

your explanation is amazing وفالعربي يجنننن مرهه

[@scottflix6466]

Thanks Sir

[@TonyWoodstock-bz6gl]

THANKS!!

[@venkateshp.5232]

Hey thanks buddy!

[@thelastdemonicwolf7989]

thanks, Dave

[@sandramichelsen6315]

THANKS. GREAT EXPLANATION. I LOVE IT

[@user-vs5cq2xf9k]

Thanks professor dave🎉

[@goose66666]

i love you so much you're a life saver

[@jrposadas2753]

what does the song at the start of the video say?

[@ProfessorDaveExplains]

"He knows a lot about the science stuff, Professor Dave explains!"

[@Jnrlionndogg]

@@ProfessorDaveExplains he realy does reply

[@Jnrlionndogg]

@@ProfessorDaveExplains that means he is a true teacher

[@ahyeah7943]

I SOOOOOOO LOVEEEEEE YOUUUU PROFESSOR DAVEEEEE... EXPLAINS ❤❤❤❤❤❤❤❤❤❤

[@ellaaaaa3453]

Thanks man. Very helpful! 👍

[@lemn9365]

Perhaps you should show a method to solving this, just talking about it doesn't make it very clear

[@ProfessorDaveExplains]

You mean the method that I totally do show in this video?

[@lemn9365]

@@ProfessorDaveExplains I mean like which elements you should do first not "lets do carbon first"

[@ProfessorDaveExplains]

Elements present in elemental form are done last. Otherwise, just pick one and go. It's very straightforward.

[@veryhealthy9962]

Ooff..I took a full on 45 mins to understand this. (I am however, not learning from school and using P.Dave entirely to self learn supplemented with physical textbook

[@adityashankar5267]

Wow...now i can understand this topic

[@daviddaman38]

this is a big w

[@toro_maine6599]

I love you Dave

[@minsuga1015]

Omg thank you soo much may Allah bless you 💜💜

[@gnation855]

Thanks teacher

[@sambhavpathak473]

Aacha padhate ho sir sabash

[@Omgitsover1552]

"Next, lets do hydrogen. Theres 8 on the left, and 2 on the right. That means we will make 4 waters." I'm obviously missing something. I have no idea where the 4 comes from or how it got there. This idea seems conceptual and i just cant see it.

[@Omgitsover1552]

Took me several times and videos to get this, but it makes sense to me now, thanks.

[@KD-vg2yn]

I freaking love you

[@mehakverma7043]

2:13 I cannot take the word "propane" seriously.

[@MukeshKumar-gj5cz]

Thank u professor

[@ryedeligero5511]

life saver!!!!!!

[@volarre450]

thanks chemistry Jesus