base 10 to base 4

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[@jobinski]

Literally the only fuckin’ video that explained how to get the remainder, thanks so much

[@pete8420]

By the words of GLaDOS the evil supercomputer, "you think you're doing some damage? 2 + 2 is... ... ... ... ten. IN BASE 4, IM FINE!

[@CornKaine]

I was waiting to find a comment exactly like this

[@nw2420]

Wow! Thank you so much for your help!!!!! I can't believe that I just learned something like this in a little over three minutes. You rock!

[@justinnanu4338]

What's the largest powers of 4 that fits into 73? 4^3 = 64, and you use 1 of them. So you have a 1 in the 4th place value column left of the decimal point. What's leftover? 9. Does 4^2 fit? No. So you have a 0 in the 3rd column. Does 4^1 fit? Yes. How many? Twice. So you have a 2 in the 2nd column. What's left over? 1. How do you make 1 from a power with base 4? 4^0. How many do you have? 1. So you have a 1 in the first column. 73 in base 10 is 1021. That's how I do it. You can do this with anything. If you think of regular base 10 place value table as 10^0 (ones), 10^1 (tens), 10^2 (hundreds) etc. and representing numbers as powers of 10, e.g. 5338 = 5x10^3 + 3x10^2 + 3x10^1 + 8x10^0 you can do the same thing with any number system. For example, 198 in base 5... "base 5" can be interpreted as (or maybe actually literally means?) a power with the base of 5. First question - what's the largest power of 5 that can fit into 198? The answer is 5^3. How many of them fit? Just 1. What's left over? 73. Does 5^2 fit into 73? Yes, two of them fit. What's left over? 23. Does 5^1 fit into 23? Yes. Four times, with three left over. So, we can represent the number 198 as 1x5^3 + 2x5^2 + 4x5^1 + 3x5^0 or 1243.

[@dieptranngocminh8886]

Thank you for your sharing!

[@premrauth8416]

Thank you so much

[@sswbrbwy171]

Thank you sweetgirl

[@maliqagrant8029]

Thanks this really helps

[@kowalski3950]

what about decimal numbers like 0.69420?

[@vanessabayardo9788]

hmm it worked for me with ur number but not with the problems on my assignment.

[@justinfrankel7475]

Thank ya

[@latifahali6070]

If 4 goes into 1 zero times how is the remainder 1 and not 4 .in my understanding when conversing to base 2 when 2going into 1 the remainder is 2 so am kind of wondering

[@audreybarto1]

Thanks for your question! I hope I am not too late with my reply. *****Some Background****** I think it might be helpful to recall that every division fact has a related multiplication fact. For example, 10 ÷ 5 = 2, because 10 = 5(2). And even division problems which don't work out "evenly," like 13 ÷ 3, have related multiplication facts. In this case, 13 = 3(4) + 2. In general, these multiplication facts come from the Division Algorithm, which guarantees that when dividing an integer a by a positive integer b, we can always write a = bq + r, where q is the quotient and r is the remainder, and where 0 ≤ r < b. This Division Algorithm is also helpful if you don't know the remainder, because there is only one way to write the equation a = bq + r with these requirements. So let's say I'm trying to find the quotient and remainder when dividing 13 by 3. I start with the Division Algorithm equation and write 13 = 3q + r. Now there should only be one solution for q and r, with the requirement that 0 ≤ r < 3. In fact, 13 = 3(4) + 2. So that tells me that 13 ÷ 3 = 4 r. 2. *******Your Question****** Now back to your question about 1 ÷ 4. Starting with the Division Algorithm, 1 = 4q + r. Solving for q and r, we can then write 1 = 4(0) + 1. So the quotient is 0 and the remainder is 1. This shows that 1 ÷ 4 = 0 r. 1. So let's look at your last statement, "2 goes into 1 the remainder is 2." For 1 ÷ 2, the division algorithm would give the equation 1 = 2(0) + 1. Or in other words, 2 goes into 1 0 times, with a remainder of 1 (not 2!).

[@MariaReyes-lj4qu]

NOt with letters

[@MariaReyes-lj4qu]

Letters I can see nothing

[@attagoat5173]

Anyone here trying to figure out the numbering System in Obduction? lol