3.4 Context Free Grammar Part 1 in Tamil

[@Ria-31]

Tomorrow is my toc exam ur videos are very helpful sir🙏🏻🙌🏻👏🏻

[@because2022]

All the best

[@Shadyx7]

​@@because2022sir indha sum ku alternative ah endha sum pakkalam coz indha sum enaku puriyala

[@deepalakshmi4371]

Episilon is not required because there should be condition starts with a ,but in 3 problem there is no starts with a..it's bb

[@because2022]

Yes un 3rd queston minimum bb will be there. SO epsilon is not requird.

[@deepalakshmi4371]

@@because2022 thank you sir

[@karthi4144]

sir in sixth problem, how is there epsilon. the condition m>n means that both cannot be zero right?

[@because2022]

Yes it was miss from my side. You can omit epsilon.

[@karthi4144]

@@because2022 ok sir thank you

[@arunsuresh8547]

In 17:51 6th sum, epsilon vara koodathu thana sir ? It violates m>n .. Can i write productions like this for 6th sum : S -> aSb | aA A -> aA | epsilon Is it correct sir ?

[@because2022]

No epsilon varalam, In that case S1=> AS and if you substitute a for A and epsilon for S. it will satisfy m>n

[@jiminshiiahjumma6470]

Sir as for productions . Namma own production edukalama which also satisfies the input string or Neenga edutha same than edukanuma?

[@because2022]

You can take other productions too but it should accept all strings of the language and should reject those which are not part of language.

[@BayanFahim]

Epsilon is not required because of the n=0 has the valve of bb Am I right sir?

[@because2022]

In which question?

[@sumithamurthikg2856]

Hello sir. Romba nallaa nadathureenga, but enakku 5th xum sariya puriyala. episilon invlove aaga koodathu thaana sir?

[@because2022]

What is the doubt? Epsilon wont be part of language. Because minimum it will have 3 a's

[@D-here-88]

Sir ..15:30 la ..m should be greater than ... N nu soltanga...aprm epdi sir ..m kum n kum ..same value 0 nu potu ... Epsilon poduringa ? .... N 0 va iridha ... M 1ah thana sir irukanum? ....epdi rendum same nu vachu Epsilon podringa sir .. please clarify sir?

[@because2022]

Epsilon wont be part of language. It will have atleast a when n =0

[@D-here-88]

@@because2022 thank you sir

[@vsvicky5448]

5:08 sir why u put ab after "/"

[@because2022]

Because we are moving to next possiblity

[@wssgaming7050]

12:52 n>=1 ku answer ena varum sir ??? Orea confused ahh eiruku 😵

[@because2022]

I want you to try and if you are struck, you can mail to [e-mail]. Because in exam you wont get same questions.

[@preethisv-s8c]

Sir , 6th sum answer la (epsilon E) varakoodadhu dhana sir instead ,s--->asb/A A-->aA/a indha ans crct dhana sir?

[@because2022]

m,n should be >=0 right. So epsilon will be there.

[@Monika-jc3wl]

Sir, a^m b^n condition m>n thana sir eruku but m,n 0 kuduthaa condition fail aiduthee sir.

[@because2022]

Why monika it is failing? For m,n=0, we get S->epsilon directly right?

[@Monika-jc3wl]

Sir condition m>n thanaa sir but we r assigning both to 0

[@because2022]

@@Monika-jc3wl sorry monika. It was my mistake. Basically m>n and n>=0 than condition. So basically when n is 0 we should have atleast one a.

[@Monika-jc3wl]

TQ for the reply sir✨

[@Tharik8456]

@@because2022 so there is no epsilon in this prblm right sir?

[@ChandruD-p8o]

Sir for the 6th sum We can write production rule as S->aaSb/€ Is this possible ?

[@because2022]

It wont accept aaab.

[@wssgaming7050]

​@@because2022 S->aSb/aS/a

[@nihethane]

For 6 eg exact ans is S1->AS Ah? Sir

[@because2022]

Yes. You need to write all three productions together.

[@Usadreamerok]

Sir i know 1st and 2nd unit completlely can i go to 4th unit sir??

[@because2022]

No.

[@Usadreamerok]

@@because2022 ok sir

[@arunsuresh8547]

Sir , oru cfl ku neraiya production iruka lama ? Eg: L={a^m*b^n , m>n , n>=0} CFG production 1 : S -> aSb|a CFG production 2 : S -> aSb | aA A -> aA | epsilon

[@because2022]

Yes we can write in many forms

[@iccreations2534]

S->aaaSb/aa is wrong? Then why sir?

[@because2022]

For which question?

[@Mahi-de3cl]

​@@because2022 5th question sir

[@Syntaxsago]

in 5th sum s---->aaaaaSb s---->aaaaab s----->epsilon its correct answera sir...

[@because2022]

No when n=0, the language should accept aaa. But it doesnt.

[@Usadreamerok]

Sir if you put n =1 then its aaaaab sir

[@marliyabegam-sn6eu]

Mam normal cfg sum nadathuga

[@because2022]

Wt do u mean by normal cfg??

[@trending_video0037]

Thanks sir

[@because2022]

Welcome

[@_MIRANSS]

Sir, 6th sum a^mb^n A->aA/epsillon ( is possible )

[@because2022]

No then m wont be greater than n when A is epsilon.

[@Santhosh_0042]

Sir, 6th sum answer ippudi varuma sir S-->aaSb/ab

[@because2022]

No because it wont accept aab.

[@SyedRasheed-rc6zp]

4th purila sir

[@because2022]

Plz watch few more examples and check 4th. Then you might understand. If you dont let me know.