BIBO Stable and BIBO Unstable System (Signals and Systems, Lecture-16) by SAHAV SINGH YADAV

[@GATECRACKERSbySAHAVSINGHYADAV]

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[@mahakhan9762]

this is one of the times where i'm thankful that i can understand hindi

[@lakshaya]

Bhut bhut dhanywaad sir 2 subject complete ho gye EDC AND SAS. Sir ek doubt bta dijiye plzz.... Sir kya playlist completed h signal system and edc ki ki ya kch left h Mtlb aap bta dijie kyoki sir only aapke channel ko follow kr rha hoon and only self study kr rha hoon

[@AjayKumar-ul2dg]

heartly thnks sir. Happiiee New year.

[@avinashingle5491]

Sir can u pls.. Provide the core subject.. As I am just following u..u not only the best teacher but also the great motivator..

[@kaushikmondal3005]

One more exciting session. 👍👍👍👍

[@kuchalag3621]

sir at 6.27 , cos^2 theta = (1+cos2theta)/2 ,

[@Narendra_live]

Nice lecture sir...

[@parmeshgupta6346]

Sir your videos are awesome

[@sangitakumari6364]

Thank you sir.

[@utkarshpant5297]

Sir please start Communication Systems.

[@bhawanishankar13]

really amazing sir

[@RajiSuresh-Spiritual-Talks]

Thank you sir

[@adarshkasera8172]

Please add lecture on power electronics

[@swatiyp6502]

Sir, Need lectures on power systems also.

[@RJ-bd3ww]

Sir is from ECE

[@ranitmandal5959]

great job sir.

[@pavleenkaur8498]

Consider a system with input x(t) and output y(t) related as follows y(t)=d/dt {e^-1 x(t) } Which of the following statements is TRUE A)the system is non linear B)the system is time invariant C)the system is stable D)the system has memory Sir please help me solve this

[@kshtriyesingh5488]

2or 3 but mostly system is stable

[@arjunfitness3836]

Cos^2x=1+cos 2x/2

[@myravaldez8376]

Sir, please help with this question Determine if the system is stable or unstable 𝒚(𝒏) = 𝒚^2 (𝒏 − 𝟏) + 𝒙(𝒏), for the bounded input 𝒙(𝒏) = 𝒖(𝒏) + 𝒖(𝒏 − 𝟐)

[@kshtriyesingh5488]

Input is not bounded as summation goes infinite hence output always unbound..

[@riteshkumar476]

sir plzz make a new whatsapp grp so that we can ask the doubts plzz sir will be very thankfull to you

[@TheKingmalik007]

@ 8:46 if we put x(t)=k=infinite, then 2x(t)=infinite will come.. that will be unstable and you've said that the system is stable. How.? Please explain

[@mohduzair6392]

Sir at 7:00 , y(t) = ∫x(τ)cos(τ)dτ yahan pe integration -∞ se t tak hai , agar yahan pe x(t) ki jagah u(t) rakh de to integration 0 se t tak ho jayega aur integrate karne pe answer ayega sin(t) jo bounded signal hai to ye to BIBO stable ho jayega is hisab se . Is it correct or am i wrong somwhere ?

[@krupakararroju9015]

Brother,We have to check for every signal not only unit step

[@mohduzair6392]

@@krupakararroju9015 oh ok , thanks man 🙏

[@edutechpathsala4850]

Cosine's formula is +..

[@a2a708]

Power system lecture daliye

[@vvsr100]

sir at 22.27 if a>1 then area is negative by integration and infinite from graph i am confused here

[@siddhant-x8k]

Sir delta(0) ki value to infinite hoti hai na? for direc delta fxn. Area 1 aata hai. but value to infinite hoti hai @29:01

[@tusharsrivastava4364]

Funcn discrete tha

[@apoorvagarwal796]

Wow

[@dinkarjha8821]

At 29.06 aap h(n)=0 for n

[@amulyaputtapaka1480]

Sir,I didn't understand how ten pi by 2 becomes unstable and infinite. Please explain sir

[@ajitsikdar7613]

tan(π÷2) value is infinity

[@thedopegamer313]

sir if there is y=x(t+1)+x(t) then how to keep k in this equation

[@GATECRACKERSbySAHAVSINGHYADAV]

K1 and k2 in place of x(t) and x(t+1)

[@shahnaz1981fat]

Y(n)= exp[x(n)] is it stable sir?

[@GATECRACKERSbySAHAVSINGHYADAV]

Yes...it will give finite y for finite x...

[@shahnaz1981fat]

Nice content in your videos sir

[@vishalkunyal7698]

Sir online course nikalo koi paid

[@sajalbarsainya7037]

Y(t)=x(sint) sir..this system is stable or not..?

[@GATECRACKERSbySAHAVSINGHYADAV]

Stable

[@sajalbarsainya7037]

@@GATECRACKERSbySAHAVSINGHYADAV Thank you sir

[@prayasjakhar5207]

sir tx(t) m infinte put kra aap n but sin(x(t)) m infinte put nhi kyia aisa ku at 9:34

[@GATECRACKERSbySAHAVSINGHYADAV]

Sin{x(t)} me x ki infinite value rakhne p sin ki value -1 se 1 k beech me hi ayegi... Because Sint will range -1 to 1 hoti h

[@vishalsagade]

Sir y(n)=cos[x(n)]....?

[@towardstosuccess3944]

Stable

[@punityadav5545]

sir y(t)=x(t)/sint is this system stable or not answer given as unstable how sir please send me the group information so that i could join your group

[@GATECRACKERSbySAHAVSINGHYADAV]

Unstable... Because Sint will be zero for any integer multiple of Pi.. Hence y(t) will be infinite for finite value of x(t) at those values

[@Rahulkumar-mu2qd]

Sir samaj n ya raha hai ya baa

[@ktk3228]

sir i want to join the group

[@meenazsaiyed4833]

e^[-(1-2j)t] u(t) is stable??....e^(-t) cos2t u(t) is stable ??

[@mukeshjadon8017]

meenaz saiyed may be both stable

[@biuhalchatterjee2775]

Thank you sir