Capacitor Charging (Full Lecture)

[@evanbyrne7020]

Thank you so much for this. Was really struggling to understand the ramblings of my very intelligent professor (however not gifted with teaching ability). Really helped me nail down the concepts I was misunderstanding.

[@mdmroni7269]

It was very helpful💝

[@burakayan3360]

Thank you so much for this.

[@dixierebel8422]

Great review info!

[@tylere7313]

13:30 When your finding the voltage drop @t=15ms vr(t)=12e^-15E-3/3E-3 your answer is 0volts. Which intuitively makes sense I follow what your saying and all. But when I’m putting the expression into my calculator I’m just not getting the right answer. e^-15E-3/3E-3=6.738E-3 12V•6.738E-3=80.855-3V

[@bigbadtech]

Remember 5 time constants is an approximation of a full discharge. For all intents and purposes 80.9mV equals 0V when compared to 12V.