Binary Eutectic Systems & Eutectic Isotherms

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These slides and the way they are explained give me a way better understanding that my professor could ever give me. Thank you Dr. Coffey

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thank you very much Tonya Coffey ,you have saved someone from materials misery.stay blessed

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With less than 12hrs before my final, now I understand.

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Tiffany Chau mechanical engineering

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[@srivani540]

Thanks a lot...finally could interpret and analyse phase diagram🤕

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[@wanahmadfadhli7914]

thank you madam. it really helped me understand this topic

[@mubashirshoukat8463]

This is gold!

[@omarnabet7979]

at 23:45 what if the concentration is below 18.3% at a temperature of 150 would the calculations of W(alpha) and W(beta) be the same or would it be different?

[@Harpreetsingh-bb6vf]

thanks

[@eduardoschiavon5652]

At 25:37 shouldn't the concentration of Tin in the liquid phase be 61.9 wt% Sn? So, 18.3 wt% Sn would be the concentration in the alpha-phase right?

[@githukujohn1917]

Thanks it really helped

[@user-on4yf8tj1c]

Hi, I just don't understand this problem at 2:10. Let's say I had 2% Ag, so at 600 - 1100 T(c) I have only alpha - Cu. What happened to my 2% silver as I increased the temperature? How did the system turn completely into Cu / Alpha? Thank you.

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[@arinoba492]

7:24 Nice

[@radubotogan3524]

If we are in L + α , it means [(liquid=α+β) + solid α ) ] ?

[@eduardoschiavon5652]

α, β and L are used to represent the different phases of the system. α, and β represent solid solutions of Sn into Pb and Pb into Sn, respectively. With that in mind, I don't think it's right to say that the α+β phases are present in the liquid phase. Moreover, in the liquid phase, there are both Sn and Pb, but as liquids, and not as α, β solids. Therefore, within the L+α region we have a liquid phase (L) and an solid phase (α), and both of them are solutions of Sn and Pb.

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i understood shit