Blocked Rotor Test on Induction Motor (Practical) Part 2: Calculations | AC Electrical Machines

[@TurdBoi666]

Thanks so much

[@MojeebAl-Hazmy]

Dear Prof. Jimit Shukla, Let me first thank you for the good content of the videos you posted on your KZbin channelز I followed the published videos to explain induction motors, including the two experiments of the no-load test and the locked-rotor test, and my question is the following: In the two tests that were done, the two-wattmeters method was used, and according to what is known [that in the event that the power factor is less than 0.5, the small reading of the wattmeter must be subtracted from the large reading, and this is what was applied in the no-load test, where the total power was 157-86.5=70.5Watt while in the test locked-rotor test Although the power factor is less than 0.5 (it was 0.394), you have obtained the total power by adding the two readings instead of subtracting (Pt=86+82=168Watt). Please clarify this point for me. Appreciating your reply in return.

[@gamaksaraswat7589]

Thank you very much, this proves to be of great help.

[@jimitkshukla]

Most welcome. Happy that its helpful.

[@anubhavsingh4985]

Sir why you take line voltage to calculate Z equivalent

[@sandeepkhanduri9054]

Sir wattmeter ki reading me multiplying factor ka multiply nhi krenge

[@brightthoughtsp.a.r6320]

what is referred to primary side means

[@badrbenbouziane6757]

good joob

[@alexanderkl2146]

Blocked rotor test of induction motor should show phase power factor in excess of 0.5. These measurements and all subsequent calculations are wrong.