Linear Algebra 6 | Linear Subspaces

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The Bright Side of Mathematics

The Bright Side of Mathematics

Күн бұрын

Пікірлер: 23
@hopelesssuprem1867
@hopelesssuprem1867 2 жыл бұрын
This is the best explanation of linear algebra I've ever seen. By the way english is not my native language but I understand everything
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
Thank you very much :)
@AJ-et3vf
@AJ-et3vf 2 жыл бұрын
Great video! Thank you! This reminds me of powerful numerical method used to solve large sparse systems of linear equations: Krylov subspace methods.
@itscristianodasilva
@itscristianodasilva 2 ай бұрын
thank you!! i needed these videos, you're doing great work
@brightsideofmaths
@brightsideofmaths 2 ай бұрын
Glad you like them! And thanks for your support :)
@Stefan-dg2js
@Stefan-dg2js 2 жыл бұрын
Thanks, your explanations are so much better then the ones from my unmotivated math prof
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
Glad you like them!
@malawigw
@malawigw 2 жыл бұрын
Finally!
@legasalehlogonolo
@legasalehlogonolo 10 ай бұрын
the only reason i failed linear algebra last year was that i didnt met your youtube channel. thank you very much for your explanations, this year i feel distinction 🎉✨❤‍🔥❤‍🔥❤‍🔥
@brightsideofmaths
@brightsideofmaths 10 ай бұрын
Happy to help! :)
@mastershooter64
@mastershooter64 2 жыл бұрын
ayyyy linear algebra is back! hello! up to what topics are you going to cover?
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
All of them :D
@mastershooter64
@mastershooter64 2 жыл бұрын
@@brightsideofmaths awesome :D
@oni8337
@oni8337 2 жыл бұрын
@@brightsideofmaths hoping for a rank nullity video :)
@ichkaodko7020
@ichkaodko7020 2 жыл бұрын
I am wondering if affine subspace is indeed a subspace? I mean, by the characterisation for subspaces, no zero vector is in affine subspace right?
@brightsideofmaths
@brightsideofmaths 2 жыл бұрын
Affine subspaces are not linear subspaces in general.
@ichkaodko7020
@ichkaodko7020 2 жыл бұрын
@@brightsideofmaths ah thank you. that's why affine subspace has no zero vector in it hence it is not linear.
@VolumetricTerrain-hz7ci
@VolumetricTerrain-hz7ci 6 ай бұрын
There are unknown way to visualize subspace, or vector spaces. You can stretching the width of the x axis, for example, in the right line of a 3d stereo image, and also get depth, as shown below. L R |____| |______| TIP: To get the 3d depth, close one eye and focus on either left or right line, and then open it. This because the z axis uses x to get depth. Which means that you can get double depth to the image.... 4d depth??? :O p.s You're good teacher!
@malawigw
@malawigw 2 жыл бұрын
If I have a subspace, I will get a vector in you
@narendraparmar1631
@narendraparmar1631 10 ай бұрын
Thanks
@brightsideofmaths
@brightsideofmaths 10 ай бұрын
Nice :)
@DOROnoDORO
@DOROnoDORO 2 жыл бұрын
I thought of an interesting example: is {(x, y) | xy ≥ 0} a subspace of R²? It's the union of the first and third quadrant. edit: nope, (1, 3) + (-2, -1) = (-1, 2) which is not in that set. rip
@L23K
@L23K 2 жыл бұрын
Warum nach meiner mathematischen Grundlagen Klausur :((
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