It's literally the same proof as the one shown here.
@sub2jkoozi820 Жыл бұрын
Just wanted to say how great your videos are! You are a great help to many, thanks :)
@sounakroy193323 күн бұрын
how does divergence to infinity mean that the set has not accumulation values?
@brightsideofmaths23 күн бұрын
"Divergent to infinity" essentially means "convergent to infinity"
@sounakroy193323 күн бұрын
@@brightsideofmaths i am confused with the part where you say since |an| > n for all n in N for some sequence (an) in A it then imples that A has no accumulation values.
@brightsideofmaths23 күн бұрын
@@sounakroy1933 What does accumulation value mean?
@sounakroy193323 күн бұрын
@@brightsideofmaths Accumulation values are generalisation of limits. A point a in R us called accumulation value of sequence (an) if there is a subsequence (ank) with limit a. If this arbitrary sequence is a convergent sequence then we know that limit f sequence and subsequence both converge to a. Right?
@sounakroy193323 күн бұрын
@@brightsideofmaths so an unbounded sequence will diverge to infinity or - infinity. And terms of any subsequence won't converge right?