This is a very nicely structured lecture. And I'm glad to see someone cleanly explaining the requirement for bijectivity - this is very often omitted, or poorly explained.
@silentintegrals91042 жыл бұрын
yes, this is amazing ... stay curious
@FraserIland2 жыл бұрын
Congratulations! This is by far the highest quality lecture about Integration by Substitution which I have ever seen from a teacher or a book. Well done indeed.
@silentintegrals91042 жыл бұрын
agree, this is awesome ... stay curious
@sinanakhostin66042 жыл бұрын
Excellent lecture. The last example is very interesting and clarifying the backward substitution rule.
@japedr2 жыл бұрын
13:35 just a quick clarification. In general, the denominator would be equal to |cos t|, as we are taking the positive square root. But in the region of integration it is nonnegative, so the simplification is correct here.
@brightsideofmaths2 жыл бұрын
Indeed :)
@silentintegrals91042 жыл бұрын
💕💕💕💕💕 awesome, solving integrals is so much fun 💕💕💕💕💕
@kz1662 Жыл бұрын
thank you for these lectures !!
@brightsideofmaths Жыл бұрын
you are very welcome! And thanks for the support :)
@matejzadny84217 ай бұрын
great video,☝
@brightsideofmaths7 ай бұрын
Glad you enjoyed it :)
@sureacademykaklk60386 ай бұрын
Sir how can you shift dt to RHS It is not independent
@brightsideofmaths6 ай бұрын
I don't really understand your question. Can you explain more?
@tsunningwah3471 Жыл бұрын
好
@PrzemyslawSliwinski2 жыл бұрын
12:53 - if the upper limit is 10, we just can take ϕ(t) = sin(t/10) and call it a day?
@brightsideofmaths2 жыл бұрын
10 would be a problem here since the function is not defined at 1.