‪@btechmathshub7050‬

[@babby3819]

Really nice mam Way of presenting the problem and solution is excellent madam Thanks 🙂

[@nukamjagadeesh1662]

Mam answer lo A value full ga ledhu

[@someoneelse-vv1zh]

Thank u madam , your videos was very helpful to my supply exams. Do more videos for students❤🎉

[@btechmathshub7050]

All the best🏆✨

[@RUOK123_]

The Final Answer Was Wrong When You're Writing Yp=A.U(x)+B.V(x) You Have Written Only Half Off The Value Of A.U(x) You Skipped To Write (1/a^)sinax The Final Answer Will Be: Y=C1Cosax+C2Sinax-(1/a^)Log(secax+tanax).

[@btechmathshub7050]

Ok...plz continue ..

[@bitupankalita2833]

Bro final answer is : y=c1cosax+c2sinax-(1/a^2) log(secax+tanax) cosax.

[@srinithchary5012]

@@bitupankalita2833 where is 1/a^2 sinax went

[@shrawaniimendkee7762]

@@srinithchary5012 yes same question

[@InfantArunKumarS]

Clear explanation mam thank you ❤️

[@btechmathshub7050]

🎉🎉

[@bhanuprasanth2885]

Thanks for this video mam I am satisfied 💯

[@btechmathshub7050]

🎉🎉

[@CharanCharan-ke8go]

Super thanks for the explanation madam

[@kantamaniharshitha]

Thank you so much for explanation mam❤❤

[@btechmathshub7050]

Happy to help💝

[@edictboy2311]

Thank u mam

[@btechmathshub7050]

🎉💐🎉💐

[@srinithchary5012]

Where the 1/a^2sinax?

[@vaishnavisharma4158]

Thanqq so muchh mam .😇

[@btechmathshub7050]

✨🎉✨🎉

[@brokenbets4369]

Very good 🎉🎉🙏teaching Medam.... 🎉🎉

[@btechmathshub7050]

Satish..It's wonderful to see you in this channel🎉🎉

[@brokenbets4369]

@@btechmathshub7050 wonderful teaching Medam.. I don't see this type of teaching 🎉🎉👍👍👍👍🙏🙏

[@brokenbets4369]

Very useful

[@jayrajtagaram4010]

Super mam awesome

[@azharnafis3914]

Thank-you so much mam

[@btechmathshub7050]

Keep watching plz..✨✨

[@rajeshrangari3479]

very nicely explained

[@btechmathshub7050]

🎖️💐💐

[@mollisatyanarayana9824]

Tqq mam

[@gugunkhongsai13]

Maam at 7:32 you missed to write the second term for A which is 1/a^2 cosax sinax…..Therefore the last term you wrote at 8:18 should be cancelled and should not be there

[@btechmathshub7050]

👍👍

[@princeprajapati3441]

Love you mam

[@btechmathshub7050]

🎉❤️

[@tinku.k8079]

Nailed it madam 🙌

[@btechmathshub7050]

Tinku💐

[@vicky9856]

Thank you mam 💙

[@rajeshkethavath8131]

Nice 👍 explanation

[@btechmathshub7050]

Tq..🎉🎉

[@rajeshkethavath8131]

We love your teaching mam

[@VasiTech]

Thanks you very much mam 💐

[@tadivalasaachyuth5485]

Thanks madam

[@btechmathshub7050]

🎉🎉

[@SuryanarayanaGopaluni]

Mam solve (d^2+4^2)y=tan2x by the method of parameters how to solve mam

[@btechmathshub7050]

In place of a put 2 and proceed same method

[@abhilashabhi1709]

Mam your way of explanation is good but need to slowdown a bit not even giving a second to note it down and also explain it on board then it will be clear to understand

[@btechmathshub7050]

Abhi...definitely I'll follow✨

[@iruvadaganesh9250]

Mam I wil be the producer for ur stationary mostly on papers 😁😁

[@btechmathshub7050]

Ganesh....I need best score from you💯💯✨✨

[@manojkumar.routhu3554]

Can you explain about curve tracing and function of several variable

[@praneeth4813]

Nice mam

[@srinivasneelapala1491]

Mam make a video on CAUCHY- EULER EQUATION

[@btechmathshub7050]

tomorrow...

[@btechmathshub7050]

Srinivas...posted videos! Practice n definitely you will feel easy.

[@N_Hareesha]

Madam ... I have one doubt.. in A value, Last +1/a square.sinax mam but at the end Au(x)+B(v)x U didn't written Last value mam...Y???

[@btechmathshub7050]

AU+BV=-1/a²log(secax-tanax).cosax+1/a²sinax.cosax -1/a2.cosax.sinax see last two terms got cancelled

[@Shaikkhan2021]

Mam u don't cancel B value in Y at last

[@Shaikkhan2021]

Mam please solve my doubt , you have told" A " value to be substitute in general solution" y " in this Yc is not substitute completely why

[@btechmathshub7050]

yp=AU+BV

[@saikiran3434]

pls keep a link for working rule of this method variation of parameters

[@btechmathshub7050]

1.Calculate yc for example yc=C1cosα+C2sinβ Now take U=Cosα V=sinβ 2.Calculate UV¹+U¹V 3.yp=AU+BV 4.A=-VR/UV¹+U¹V B=UR/UV¹+U¹V 5.General Solution y=yc+yp

[@aquavlogs..]

Last step totally confused pls explain clearly

[@konintiteja7438]

Please improve the handwriting madam .. some words / letters are so hard To understand

[@btechmathshub7050]

Certainly ✨

[@BadamAnirudh]

Bro madam hand writing is good bro

[@rohith18]

Excellent explanation ❤️

[@btechmathshub7050]

Rohith..tq🎉

[@karthikbandi1849]

Super explanation

[@Lucifer64722]

Total simple substitution mistakes

[@btechmathshub7050]

Mention the minutes where you found mistake I will clarify