Bulk Modulus of Elasticity and Compressibility - Fluid Mechanics

  Рет қаралды 21,897

Learn Civil Engineering

Learn Civil Engineering

Күн бұрын

Пікірлер: 26
@sumitkumarsahoo7601
@sumitkumarsahoo7601 3 жыл бұрын
you cleared my concept, thanks a lot, love from India
@Learn_Civil_Engineering
@Learn_Civil_Engineering 3 жыл бұрын
I'm very glad to hear that! And thanks for the comment 🙂
@sumitkumarsahoo7601
@sumitkumarsahoo7601 3 жыл бұрын
@@Learn_Civil_Engineering you are creating a great change in students' life, have a great go for this great work.
@Ahelot
@Ahelot 2 жыл бұрын
Thank you ♥️ your videos should be used on facultys, great job 👍
@Learn_Civil_Engineering
@Learn_Civil_Engineering 2 жыл бұрын
Thank you 😊 your support is much appreciated!!
@suyashsharnagat2912
@suyashsharnagat2912 3 жыл бұрын
Keep posting videos It helped a lot Thanks man !!!
@Learn_Civil_Engineering
@Learn_Civil_Engineering 2 жыл бұрын
I'm glad to hear they are helping! Thank you for the support 😀
@Learn_Civil_Engineering
@Learn_Civil_Engineering 3 жыл бұрын
Subscribe to the channel to stay up to date with a new video released every Wednesday!
@Kurosaka
@Kurosaka 3 жыл бұрын
can you make a vid about gases? for bulk modulus?
@xavierhenriques1116
@xavierhenriques1116 3 жыл бұрын
Very well done Thank you
@Learn_Civil_Engineering
@Learn_Civil_Engineering 3 жыл бұрын
Thanks for the support Xavier!
@tuyishimealexis4306
@tuyishimealexis4306 3 жыл бұрын
Thanks for your video ,but try to use Standard camera
@manuelseque8055
@manuelseque8055 3 жыл бұрын
nice video. good work
@Learn_Civil_Engineering
@Learn_Civil_Engineering 3 жыл бұрын
Thank you for your comment Manuel Seque
@manuelseque8055
@manuelseque8055 3 жыл бұрын
is it possible to prepare video with shear modulus too
@Learn_Civil_Engineering
@Learn_Civil_Engineering 3 жыл бұрын
Hi there, yes I will try to post a video on shear modulus as soon as possible.
@isharauditha4257
@isharauditha4257 4 жыл бұрын
How did you assume this ^v/v=^raw/raw
@ken-cf7tf
@ken-cf7tf 4 жыл бұрын
its actually -dV/V = dρ/ρ , you can derive this by differentiation of ρ=m/v ρV=m ρdV+Vdρ = 0 Vdρ=-ρdV dρ/ρ = -dV/V
@Learn_Civil_Engineering
@Learn_Civil_Engineering 4 жыл бұрын
It's not actually an assumption, delta Rho is equal to (delta V / V) times Rho due to the fluid's mass being the same before an after the compression. Therefore, as there is a decrease in volume, there must be a corresponding increase in fluid density. So the the above is an expression representing this.
@isharauditha4257
@isharauditha4257 4 жыл бұрын
@@ken-cf7tf thanks
@isharauditha4257
@isharauditha4257 4 жыл бұрын
@@Learn_Civil_Engineering thanks
@orkungoksel5346
@orkungoksel5346 2 жыл бұрын
Thanks
@malumognekusangeloc.7374
@malumognekusangeloc.7374 2 жыл бұрын
How did the change of Rho (0.1) turned to 0.001?
@wildankoso
@wildankoso Жыл бұрын
By converting the percentage into a number; multiplying it by 100
@arashmokhtarbaf5826
@arashmokhtarbaf5826 2 жыл бұрын
Why v or change in v? Why not change in V over V?
@Derimmerjung
@Derimmerjung Жыл бұрын
If I use the water density = 1000 kg/m3. The change in pressure would be 2.1x10 exp 3. It´s logical?
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