C_114 Unions in C | C Language Tutorials

[@hariparuchuru3858]

if we dont initialize c value then the last entered value char b as 97. this means the combined memory allocation for union will store the last entered value 97 which int a also can access so the output will be a value is 97 b value is a

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Start from 2:24

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You make it easy to grasp some concepts in C that i thought difficult beforehand. Thank you very much

[@archanafugare6895]

At 6.19 memory will be 12 bytes not 9 bytes as structure padding. If char is last var of structure then 9 bytes will be allocated

[@leo5457]

Structure padding means!?

[@qazicode4467]

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[@asadjan1001]

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[@Byndhrzns]

The answer to your assignment is --For u.a is some garbage value,and --for u.b is 97;

[@dasadiamukeshbhai6100]

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[@JennyslecturesCSIT]

Okiee

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[@saibanali9515]

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[@18fatima15]

11:39 It should be struct demo *ptr = &s 17:07 #include union abc { int a;char b; float c; }; int main() { union abc u; union abc *ptr=&u; u.a=1; u.b=97; printf("a=%d",ptr->a); printf(" b=%c",ptr->b); return 0; } OUTPUT: a=97 b=a

[@Cutestthing4707]

Can u explain me how

[@Cutestthing4707]

Why a=97

[@nishasiddu5487]

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[@luckyscreation7396]

12bytes allocated in struct mam, because there is no #pragma pack(1).

[@saradiwan6734]

ma'am it will print a as the ASCII value of 97 is a

[@smartboysai930]

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[@azannasir8895]

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[@kothamachusupriya9590]

it gives lowercase a as output because 97 is its ascii value and u declared b as charecter

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[@nandhagopal9304]

Mam explain structure padding and structure packing

[@MadhuKarampudi]

a value will become the b values if we enter any integers(1 byte integers) b will be any garbage value

[@30amankaushik29]

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[@linceesen1086]

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[@Bornkill-jq7ts]

Mam we can use methametical expressions in union

[@AnkitThakur-dp8gx]

Tmare padhaane ke tarikhe se pyaar hogya h mjhe or tumse bhi

[@SaraswotiKhadka]

a= garbage value, b = 97.(last value)

[@xylonature7787]

Bro.... That's a char data type but the initialized value is of int

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[@soniasonia4292]

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[@aryantripathi5574]

Mam int is 2 byte of memory location.

[@leeparrr]

in some compilers its 4bytes

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[@machanisomu]

Nice explanation

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[@deganath106]

mam a small correction at 9;15 - u.a is not garbage value it is 9.2

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[@sumitbhoi4070]

Jhand

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[@nagarjuna4541]

Madam int size is 2bytes

[@satyajitmanna8501]

print a= garvag value and b = 97

[@more-omkar]

No it prints a=97 and b=a.

[@qazicode4467]

Mam Please make a tutorial on "Enumeration"

[@IntellectualWarfare441]

Practical on Laptop vs Blackboard

[@divya-hj7xh]

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[@pranav-wi5uf]

No mam size of the structure is not directly calculated. Its wrong data padding will there in structure for processors optimization and also how you are declearing.

[@ankammaraochintala2509]

Thank you madam

[@meghapriya7641]

Mam please make videos on Compiler Design as well.

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[@beniematoka]

In the struct memory allocation, why did you not take the padding into account. I am a bit confused.

[@zaydaofficial699]

Hello

[@joebosah2727]

Totally understood Thanks, Jenny

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[@anujeetkunturkar780]

1st it will print a=97 and b = garbage value or Nothing ........!!

[@Honey-j5n]

Please explain java also ur teaching is very good

[@sumanthb178]

Mam structure padding will not be applicable to all compilers?

[@Raam1827]

Is it need to if struct student s1; struct student *ptr; ptr = & s1; or simply we can assign ptr = s1; because s1 holds base address

[@leeparrr]

yes if u meant to say s1 holds it's own address then u can do so...

[@a.t7119]

Size of the structure is 12 not 9

[@TheLinKueiWarrior]

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Thank You

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[@FrameCyborg402]

Depends on what language you are learning

[@A1Tech6111]

Thanks medam

[@NivedithaSonule]

Mam what is the memory bytes of the int

[@pritmonpara406]

C++ start karo

[@abdulbasit6618]

can anyone please tell me , if I want to know the size why there only format specifier (%d) is used, cannot I use the format specifier of any other data type available in the union or struct member to know the size. please let me know.🤔🤔🤔

[@aparnamane4899]

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