C_72 Pointers in C- part 2 |Address of(&) and Indirection (*) operator in Pointers I C Programming

[@Chris-vt6nl]

Today is March 1st which is your birthday wish your a very happy birthday🎂🎂the best programming teacher on youtube

[@Masti.Wallah]

Ur birthday is also come on 1st March!

[@mdparvezquraishi8412]

Mam you deserve the word "Teacher" !!!!

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@abishekhrajendhran8157]

Perfectnaa!

[@RAHULRAJ-nq8mw]

world teacher not word

[@meme_Overflow]

She is a teacher indeed lol!

[@dornalameghana1972]

yes

[@chinweokwugiftchiedozie1587]

c = *q; *p = 20; Output would be c = 9 and a = 20. While p = the address of a in a hexadecimal form

[@SandipBhattacharya]

Great video, thanks, Jenny. So, there are two pointer operators: * and &. The & is a unary operator, called “Address of” or “Reference operator” that returns the memory address of its operand. For example, j = &i; assigns the address of i into j. This address is the computer's internal location of the variable in memory. It has nothing to do with the value of i. You can think of & as returning "the address of". Therefore, the above assignment statement can be expressed as "j receives the address of i". The second pointer operator, *, called “Value at address” or “Dereference operator” or "Indirection operator" is the complement of &. It returns the value located at the address that follows. For example, if j contains the memory address of the variable i, k = *j; copies the value of i into k. Hope that was helpful. :)

[@chidiebereemereuwa9306]

Excellent explanation

[@sparkx18]

Yes Thank You 🙏❤️ Nice Explanation 🙏❤️👏

[@SumitKumarofficial36]

C= 9 a= 20 p=ADDRESS OF A IN HEX FORM

[@herohera3497]

you summed it perfectly...but why have to written c

[@universe449]

Here value of a is incorrect

[@sakibishraq221]

@@universe449 why??

[@jayaramkumar5148]

They didn't declare a value of C then how will you assign the value of C is 9?

[@ny_reve]

Could you please explain to me, why p will be the address of a (in hex form)? why specifically in hex format?

[@19_jothikams23]

Ans C=9 a=20 P= address of a in hexadecimal format

[@anuragmalviya2397]

Value of a might be 10 only as ma'am has written %d then a and in the starting of prog value of a is 10.

[@praveensamuel8083]

here a=*p, so the value of a is 20 only here we are assigning new value to *p so the value of a is 20 ... correct me if I'm wrong 😶

[@keenkumar5134]

*p= 20; i.e value at address of a(here 1000) so *(1000) = 20 or simply a= 20

[@neelirahul7892]

@@praveensamuel8083 bro a=*p is not declared at all How can you say that it's out put is 20 . It's 10 for sure

[@juryrigging]

​@@neelirahul7892 Nope, a = 20. Look again at the second original printf statement: printf ("a = %d", *p) , 10 It's an instruction to print "a =" value of *p. It was written to show you that this is so, even though it isn't formally declared. a = *p is inferred from p = &a: a = 10, p = &a p points to the address of a (&a). *p points to the value held at &a. &a is the location that holds the value of a. *p points to the value of a. a = *p *p = 10 Both a and *p are the same data stored in memory at &a, so cannot be two different values. As long as p = &a, for *p = 20 to be true it must override a = 10. If you don't understand this you can accidentally overwrite your variables when using pointers.

[@Unknown-cc6wc]

Best teacher of computer ever. Keep it up👍

[@shinyrao2786]

As we taken c=*q which means *q gives the value of b. Because q=&b; *q = value of b. Therefore the c=b; C= 9.

[@741ibrahim2]

shiny rao u rocked !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[@mukeshjaiswal8079]

Right

[@AkashDixitShorts]

Yes

[@bibeksingh2105]

Yes

[@saifshamsi4065]

You are wrong

[@udaysinghrana5725]

c=&q which means c=*(&b) value at memory location of variable b. *p = 20 this means *(&a) value 20 will be stored at variable a and will pointer will point to address of memory a

[@bisusiddharth6942]

Absolutely, if we use *p or *(&a).

[@lokeswaripanchireddi-z6l]

Mam I like your way of explaining the subject to students 👌, you are the best programming languages teacher for me......

[@suryakant7977]

Best teacher of computer ever.

[@AyushSharma-li1kn]

Best teacher I have ever seen in my life😃😃🙏

[@_kucial_]

Kaha se ho??

[@john_avernia]

I'm in the middle of doing my CS course, and this helps me a lot on understanding pointers (which apparently is a very hard subject that even the veterans hates). She's a great teacher.

[@beneelohimhub]

The printf("C = %d, c) will give us 9, the printf("a = %d", a) will give us 20 and the printf("%x", p) will give us 0x8000.

[@heysuraj-ik1rd]

correct

[@beneelohimhub]

@@heysuraj-ik1rd Thank you...

[@nandinil8723]

How pls explain a and p values

[@beneelohimhub]

​@@nandinil8723 p is storing the address of a, that is it has a direct access to whatsoever value that is stored in a, so when you dereference p, what you get is the direct value of a, so dereferencing p and giving it a value of 20 is the same as updating the value stored at the address of a, which initially was 10 to the new value, which is now 20. I believe you understand it now?

[@beneelohimhub]

@@nandinil8723 While p is the hexa-decimal value of p, that's the hexa-decimal value of 20.

[@Vikram-b]

Thanks mam me 5 din se smjh nhi pa rha tha pointer apka video dekha smjh agya

[@helloworld2054]

For second question it's not clear whether ma'am had declared the value of a as 10 or 20. If you declare value of a as 10 then the output will be 10, if you declare it as 20, output will be 20. (run the code on your PC to verify)So value of a cannot be updated using *p. Whatever the value of a is declared first that will be printed. And for the third one it will print address of a in hexadecimal form

[@chidiebereemereuwa9306]

according to the above block of code: int a =10, b = 9; int c; int *p,*q; p=&a; q=&b; // the pointer 'q' declaration here means that the address-of 'b' is assigned as // the value of q c = *q; // here is the declaration of c to *q or &b. This means that using the indirection // operator or dereferencing * operator: the value of the variable is accessed. // in this case the variable is 'b' *p = 20; // this will manipulate the value of the variable which p points to: 'a' // 'a' variable was initially 10 now value will be '20' printf("c = %d",c) // the output will be exactly the value at variable 'b' printf("a = %d",a) // the output will be the current assigned value to *p which is 20 🏑🏑i hope this was helpful to someone to understand better the output of c.

[@swapnapanuganty3489]

Nice explanation, Just wanted to add in the line c = *q; it basically means that c = 9; because dereferenced q is pointing to the value of b which is 9.

[@chidiebereemereuwa9306]

Yea: exactly.. thank you. c = 9

[@PaulineR-xs3kx]

understood . thanks

[@Aditya-sn4le]

Ma'am you are literally the best teacher ever!!!!

[@Aditya-sn4le]

No one can beat u in being the best teacher ever for C programming.

[@jxtin1007]

very beautiful teacher.

[@GEORGESTEPHENTHARAKANB23CS212]

truely. that itself keeps us hooked 😅

[@theshashankgaming1231]

mam thanks lot your teaching style is very awesome slowly slowly helps me to understand all the topics thanks a lot mam you are best

[@kocengineering769]

Mam c=9 only As you told us to comment on C=*q So it must be 9 In the program while you were running you have given C=*p Which will give a value 10 I got it mam Thanks

[@Pavansgame]

C=*q That means it should print value of 'C' but where Is C value

[@nasirkhatib3836]

Best teacher of computer in india

[@PavaniTirumani-p7i]

C=*q ,*q represents the address of b in which b value is present and print the value c= 9

[@ChillOutinLove]

a) c = *q , then value of c is 9 b) *p = 20 means value at (&a) is 20. c) value of p is address of 'a' in hexadecimal form.

[@tomcruise4293]

Thanks bro for this easy way

[@alaharianuhya9523]

Can you pls tell me how the value of a is 20

[@ummesalma6669]

@@alaharianuhya9523 we used there indirectional operator that is * which prints the value of 'a' at address of 'a' (As we already declared above that 'p' stores the address of the variable 'a')

[@iAmAjayTeli]

Mam you are amazing I always watch only your video when i don't understand in my college You are better than my college teacher

[@moizawan1807]

1-- c=*q; this will assign value of memory address that is stored in q so c will become 9 2-- a=10; *p=&a; *p=20; this time value 20 is assigned to a variable and its orignal value is overwritten by this

[@ronycb7168]

c will be 9 and a will be 20 and p will store the base address 3046

[@ayyoubezzouine]

best teacher ever !thank you so much

[@suvashreepriyadarshinibisw8017]

C = 9 A= 20 P = hexadecimal number

[@limitess9539]

if you suddenly open 15:38 it looks like b=a lol, in that case value of C would be 10 which I thought, because it looked like that to me lmao

[@maradanavivek]

9

[@Games_with_Aryan365]

Answer C=9 a=20 P=it store the address of other variable in hexa decimal form...

[@hariparuchuru3858]

what I understood I if we initialize int a=10; int *p; p=&a; *p=44; printf("%d", a); then it will print a=44; i think here we are changing the value stored in a through pointers i.e if p is having address of a the *p says value stored at the address means if we initialze *p =44; means we are initializing value to a.

[@archismanghosh7283]

my favourite teacher and first choose of CS

[@melthabah1158]

The value of a now is override by 20 output is 20 for a value mam

[@Sunil-zo3bh]

As *q=*(&b) And b is having value 9. So asterisk operator will fetch value inside address of b. Ie. 9

[@kwameanati]

Value of c is 9 Value of a is 10 Value of p is &a in hexadecimal

[@vaibhavsinhbihola1]

15:29 answer is 9 16:18 for value of a answer is 20 and for value of p answer is 1000

[@praveensamuel8083]

exactly hexadecimal value of p is 1000 only.... y bcoz here p have address of variable 'a'... condition: P=&a

[@manojrajput9930]

a = 10 P = 1000EF( in hexadecimal form) C = 9

[@kushpreetbakshi4828]

A will be 20 bro change kar di hai val. A ki pointer se

[@soulfulhuman8724]

@@kushpreetbakshi4828 hello. Value is coming out to be 10 when I run it in VS code. And after this I also print Printf("%d", *p) ; So value is coming 20 there. How come?

[@totoplopp6630]

She got me through my bachelor in computer science more than any teacher at Uni

[@vickyvignesh3844]

mam waited for pointers for a long time thanks for start uploading mam!!.please post all videos as soon as possible mam.please try to upload 2 videos per day mam.Thank you mam.

[@harshpandey3500]

It's very useful mam thanks for this information

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@codeMantra272]

Thanks ma'am your video clear my all doubt ☺️

[@tanish_ot7]

Mam aap bhout acha padhate hoo

[@timjoyalle318]

New to the channel. I like your style of teaching. Keep up the good work!

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@laxmanpabbathi9268]

Nice teaching

[@sairamkumaremani2485]

Thank you very much mam now concept is very much clear.

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@shinyrao2786]

*p=20; which means value of a will be overwritten by 20.a=20;

[@eshuvgautam3186]

Mam whenever you teach us everything is FINE!

[@maryannemuthoni5388]

Value of c is 9 Value of a is 20 Value of p is the address of a which in our case it's 1000 but will actually be in hexadecimal form

[@heroicme6982]

Best teacher in the world❤🩷💛

[@nextzen9550]

very very thank you so much ma'am

[@Mehedihasan-rahat]

Thanks 4 your outstanding explanation but a single query was what is the purpose of using pointer???😮😮

[@jayalakshmilbhat125]

Best lecture ever seen.. Happy Birthday mam ❤

[@nextzen9550]

i like your video...thx ma'am

[@bathureddy4456]

hyderabad secunderabad jenny madam zindabad...

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@yashichauhan316]

in case of printf("c= %d", c); the address of pointer q is printed in integer format. next incase of printf("a= %d ",a); value of a willl be printed that is 10.

[@yashichauhan316]

@sampath sam hey

[@priyanshusaraswat8892]

Thank you for lecture

[@faithfullyfactual]

value of c = 9 because c is initialised to hold the value of the pointer q(which houses the address of b), which turns out to be 9. Hence, value of c printed would be 9. In case 2, the value of the address p holds (*p) is modified in memory to 20. The address p holds is of variable and since *p is modified, it means a has been modified (or corrupted). Hence the value of a printed would be 20. In the last case, p would print the address of the variable a, didn't change throughout the program.

[@MadhuKarampudi]

value of c == value of b and a becomes variable so it leaves 10 value and it will get new value that is 20 a=20 and p=20

[@shinyrao2786]

Printf ("%x",p) gives adress of p in hexa decimal form

[@abdulrahimjalloh363]

Assignment: printf("c=%d",c)...............it will print 9 printf("a=%d",a)..............it will print 10 printf("%x",p)..................it will print 10

[@iasaspirant1441]

superb explanation madam

[@hustlewithnik]

a= 20 p= address of a in hexadecimal form c=9

[@Romantic._Songs]

Hi nikita❣️❤️

[@FunandLearn2512]

I am already a software developer. I don't know what I am doing here . I just came to see you everyday .

[@timjoyalle318]

I know what you are doing here...

[@FunandLearn2512]

@@timjoyalle318 please enlighten me 😀

[@timjoyalle318]

@@FunandLearn2512 You're here for her beautiful mind!

[@FunandLearn2512]

@@timjoyalle318 yes correct .

[@dompelkmoviereview]

C = 9 a = 20 p = address of a ( hexadecimal number )

[@ramu6313]

q contains the address of b(q=&b) *q contains the value of b=9 So c=9(c=*q(

[@BiswajitMaharana1]

Thank you mam for uploading this.

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@thedata-ist]

Since, q is carrying the address of b, so *(&b) = b. So, the output will be 9.

[@taniyahettiarachchi6674]

Thank u very much mam.💪💪👍👍🙏🙏❤❤

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@williemungai1954]

c outputs 9 the value of a is 20 p prints the memory address of a in hexadecimal

[@sairampolisetty2059]

Thank you soo much mam ❤️😀 I have understood clearly.

[@atharvabadgujar9868]

value of a will get printed the adress of p will get printed in another case

[@sauravjaiswal5970]

c=*q; since q stores address of b so the value at that address will be stored in c i.e 9

[@jayprakashmahakud9150]

9 20 Address of a which is hexadecimal

[@harshini.m3327]

Haappyyy Birthday Mam!🎉 Grateful for ur videos❤

[@GaganGarg-pt6bg]

Now i can understand pointers

[@asmarubiya5214]

Better than our academic lectures..

[@mohithar1110]

hey army ..!

[@asmarubiya5214]

@@mohithar1110 hiiiii💜💜

[@mohithar1110]

Wow I can see army's every where 💜🥰

[@vrengineers2462]

ankit and pulkit will remember forever

[@onlynoone6512]

15:28 *q=&b; here *q=9; then c=*q; so c will equal to 9

[@mukbanggie3375]

Example of beauty with brain 🥰🥰

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@misturaojulari9707]

Thanks a lot! Your class is helping me achieve the impossible

[@prassyam]

Namaste ji, can u pl provide tutorial on Oracle 10g...in Hindi

[@chandananonymus3563]

thnks mam it was exam.time you cleared me before going to exam......and the exam was practical exam.🥲

[@techienomadiso8970]

Why can't Lecturers teach with passion like this? 🤦

[@sauravjaiswal5970]

*p=20; *(&a) = 20; //overwrites the value of a so a=20

[@Palash-vm4mo]

Today is mam interview and these video is so beneficial for me💜

[@JackCoderr]

Thank you so much mam 🏵️🏵️🏵️... really greatful to you mam

[@phanimanojoleti6606]

your classes are awesome 😎😎😎 mam

[@muhammedjasil1701]

One of the great gift for Indian students..

[@devSackey]

The value of c is 9; a = 9; p = The address of a(in hexadecimal);

[@YashwanthCheerla]

Happy Birthday 🎉

[@shraddhapawar5674]

Ma'am if possible, upload video fast. Nice lecture 👍

[@leharaoshan7764]

thank you soo much jenny madam❤

[@itsmearun7388]

And also u should declare. All the value in printf in single line.. Like... Printf ("%x%d%d%x", a, pa, &pa, *pa) ; I'm just telling... That's also okay.. Know...

[@alyanaly9069]

Answer C=9 a=20 P= address of a in hexadecimal form

[@ASRCreations]

Completed the course in 1 day for exam

[@viratkohli5368]

madam plz make a video on dangling pointer and null pointer

[@ahmadcomputers2291]

Madam |G Thank You ""Good Job

[@coding1415]

kzbin.info/www/bejne/pYjXmq2lrL-MeMU

[@soumadeepdas7610]

best mam ever.❤❤

[@invincible9971]

printf("c=%d",c); output is: 9

[@megh5013]

Thanks a lot Mam for this lecture!!!

[@benjimen05]

Megh I love tou

[@preethipalanisamy8946]

c=9, a=20,p=addressof(a)