Cable subjected to Distributed Load Example 3

[@esclipsekr]

you’re better than my static professor

[@petergeorgeednalaga2808]

is the formula same on SI system? say.. N/m..?

[@marcelo497]

I believe it's late to say it, but yes

[@ZainKhan-cy4sp]

Sir why you take left side distance x and y in F. horizontal

[@manishatiwari323]

Thank you so much sir I bow down to you🙏

[@1963rzr]

All the best

[@maskman2671]

Sir, as you said Fh will be same on both side but i calculuted Fh using right side sag and distance there was lil difference your Fh is 3790 and when i calculated using right side my Fh was 3786. I know its not much difference but its not same. Is this difference negligible. BTW THANKS for video

[@1963rzr]

Sir, Your calculations are either wrong or you didn't use all decimals...Fh is always the same

[@Tide_02]

even if you use all the decimals we not gettin 3790 for the RHS

[@_notme117]

@@Tide_02 If you use up to 4 decimals you'll get the same Fh on both sides

[@alysonmohan9855]

Hello, this video helped a lot. Which text book is this from?

[@592chris4]

Hibbeler Structural Analysis

[@NiazMdRafi]

Sir i have an one important question and it is very doubtful for me. This question is when you determine the tension of B,y then why you calculate sum of fy in whole free body? please answer this question quickly if it is possible for you.

[@ellathebully6064]

Thank you so much... Well explained.☺

[@RajivHardeo]

Why did u add 1 to 0.8165?

[@1963rzr]

hello to you too... i added because it must be added. please check the explanation again

[@hanzbobielubapis5166]

ILOVEYOU sooo muchh sir 🤩

[@1963rzr]

:)

[@高佳翰]

hi, at 6:17 you wrote x=25÷(1.08165) but I think that it must be x=25÷(1.8165)

[@1963rzr]

Thanks.... but the results is correct

[@londontimes-w4s]

This question came in my paper . I just solved it . Online examination . Thanku so much . This question contain 20 marks . So its for sure . Oh yeah .

[@1963rzr]

Just be sure that you understand it and not just copy it... You are Welcome!

[@berkexan4117]

I saw on other notes that the formula for Fh = wL²/8h instead of wL²/2h ?

[@berkexan4117]

Oh wait i think i got it,some notes would leave L representing the whole length,not the half length; w(L/2)²/2h = wL²/8h

[@ghelen5685]

Thank you so much sir, you help a lot 🥺

[@1963rzr]

You are welcome!

[@cjayson38]

How do we find the maximum tension of the cable and also the minimum?

[@1963rzr]

Hi. Hello to you too.

[@ConceptualCalculus]

Maximum tension occurs where the slope of the cable is the steepest (closest to vertical). Minimum tension occurs where the cable is horizontal.

[@Tide_02]

wish could subscribe twice lmao😁

[@jejomaec.7312]

Thank you sir! 🙌

[@stephaniemejia5840]

🤙🤙🤙🤙

[@angielicabalonzo7848]

Lifesaver 😌

[@1963rzr]

@@stephaniemejia5840 you are welcome!

[@1963rzr]

Thanks

[@1963rzr]

You are welcome

[@mdmizanurmizanur5810]

The name of this books writer?

[@saqib3s]

Thank you very much

[@1963rzr]

Glad you liked it. Remember to subscribe, like, and share,

[@athenapsychelee7803]

thank you somuchhh!!!!!

[@captainseulgi]

What if L is not given?

[@1963rzr]

hello to you too?