CAIE AS Physics 9702 OCTOBER/NOVEMBER 2023 Paper 12 solved MCQs

You will get a clear explanation to the October/November series [9702/12/O/N/23] in this video with more alternative examples. Simply obtain the question paper and follow the videos

[@dylangabriel2703]

Thank you

[@darkmartian3673]

in question 37 why cant we switch the terminals around?

[@an5i910]

57:12 I don't understand how its A, shouldn't it be "both decreases" i.e D. I put it in a simulation as well and the voltmeter reading decreases. Shouldn't Rt increases so that it takes more potential and so R1 gets less potential & R(ldr) increase so that potential across it increases and so this leads to R2 getting less potential drop. Hence, both Rldr and Rt must increases meaning temp and luminance must decrease? Please correct me wherever I went wrong. Thank you

[@danthemanlol]

Im getting the same answer D, Rt should be less than R2 for their to be a positive potential difference, but the marking scheme says its the answer A

[@user-ox6ky1gq5p]

thanks so much! your explanations are good

[@-omar-4214]

in q33. why is Rt>R2? i cant understand it.

[@learnPHYSICSwithIBM]

current flows from side of high potential to low potential, and this will only be seen if Rt> R2

[@-omar-4214]

Ahhh i got it. What i understood is for R1 has to consume less voltage than R ldr for there to be higher voltage on the left side at the junction So if r1 loses less from the 6v than the ldr then yeah Rt>R2.

[@Hallucinates05]

For qn 31, why cant I find voltage using p = Iv, then use the voltage to calculate the new current

[@ipfocusx2646]

because voltage of x is not constant

[@shayanbintariq2219]

@@ipfocusx2646 and where does it say that?

[@ipfocusx2646]

@@shayanbintariq2219 when resistance in variable resistor changes, pd also changes, so bcs of this pd of fixed resistor changes

[@manahiljavaid]

16:15 isn't the velocity supposed to be negative for the second ball?

[@ayrio844]

assuming you're talking about the energy calculation, the minus does not matter as velocity is squared either way. During conservation of momentum however, the minus must be taken into account.

[@jtj3112]

in q11 cos 45 is radical 2 over 2, how is the answer something else

[@learnPHYSICSwithIBM]

root 2 over 2 is same as 1 over root 2 please

[@asankacosta9120]

That’s denominator rationalized. Cut numerator and denominator by root two.

[@hamidSohail-vy3ei]

28:12 u took energy as work done which is force * distance but why didn't u include the time cuz the expression for energy is power which is work done * time?

[@learnPHYSICSwithIBM]

we dont have power in the question. Energy is equal to work done or energy is equal to power x time,. Power is equal to workdone divide by time

[@Subayyal-ro2ir]

Bro, Cos(45)= 2/(2^-2), you have taken the wrong value in question# 9

[@learnPHYSICSwithIBM]

question 9????, i dont see cos anywhere in qn 9 unless u meant qn 6