Calculate the angle X in the Circle | Learn how to Solve this Tricky Geometry problem Quickly

Learn how to find the angle X in the given diagram. Solve this tricky geometry problem by using Alternate Segment Theorem and Central Angle Theorem.
Today I will teach you basic tips and hacks to solve this tricky geometry problem in a simple and easy way. Step-by-step tutorial by PreMath.com
• Calculate the angle X ...
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Calculate the angle X in the Circle | Learn how to Solve this Tricky Geometry problem Quickly
#FindAngleX #Geometry #GeometryMath #AlternateSegmentTheorem #CircleTheorem
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#PreMath #PreMath.com #MathOlympics #HowToThinkOutsideTheBox #ThinkOutsideTheBox #HowToThinkOutsideTheBox? #SemiCircle #Radius #Radii
#PythagoreanTheorem #Pythagorean #ParallelLines
#HowtoCalculatethedistance #Findthedistanceofthelinesegment #LineSegment #length #distance #blackpenredpen #ComplementaryAngles #OlympiadMathematics
#FindtheAngleX #HowtoSolvethisTrickyGeometryProblemQuickly #IsoscelesTriangleProperty
#IsoscelesTriangle #IsoscelesTriangles #Isosceles #Triangle #Triangles #ThalesTheorem
#CongruentTriangles #CentralAngleTheorem
Olympiad Mathematics
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Po Shen Loh
Learn how to find the angle X
How to Solve this Tricky Geometry problem Quickly
Exterior Angle Theorem
Alternate interior angles
premath
premaths
circle
Radius
Diameter
Radii
Congruent Triangles
Circle theorem
Central Angle Theorem
Alternate Segment Theorem
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[@rishudubey1533]

angle b =52 thanks a lot to give interesting vdos who make my day 🙏⭐

[@PreMath]

My pleasure 😊 Thanks for your continued love and support! You are awesome. Keep it up 👍 Love and prayers from the USA! 😀

[@Jio_hot_star]

​@@PreMath love from india

[@tejastanay5691]

Simpler solution: Radius is perpendicular to tangent at point of contact Hence 52° + x = 90° Implies that, x = 38°

[@Onoofree81]

I solved this problem in the same way.

[@libertarianguy5567]

Same here

[@normanc918]

The red line is a tangent to the circle, therefore the contact point to the centre is 90°. X = 90-52=38°. I solved it in less than 15 seconds.

[@nickdsp8089]

two steps before the calculation. First connecting OA and second COA is isosceles because of the radius.

[@Copernicusfreud]

That is exactly what I did too.

[@quanhoang1671]

Simple, as the definition of the tangent, (52 + the angle CAO) = 90. So x=CAO=90-52=38 degrees

[@n.662]

This is very nice and very simple problem. Thanks!

[@HappyFamilyOnline]

Amazing👍 Thanks for sharing😊😊

[@skipmars7979]

I know you were showing a lot of useful Theorems (which I watch and learn from) but since the line is tangent it this means line OA is perpendicular (90 degrees). Therefor once you established x was congruent 2:06 then subtract 52 from 90 for the results and save some steps. I enjoy your videos.

[@arthurschwieger82]

Nice! I was wondering where you were going with the 52° and Alternate Segment Theorem. I went with a line from O to A would be 90° to the tangent line and 90°-52° = 38°.

[@murdock5537]

Awesome, many thanks! Draw radius AO → right angle to tangent → x = 90° - 52° = 38°

[@xof-woodworkinghobbyist]

I drew that OA line, then I got the isosceles triangle OAC. OA is perpendicular to the tangent, so x + 52 = 90... x = 38. Is my reasoning correct? Thanks for these exercises, our brains are appreciative!

[@Abby-hi4sf]

Great to learn about "The alternate segment theorem" Thank you

[@soniamariadasilveira7003]

I loved your explanation! Tks.

[@BKNeifert]

You can see that when the lines move on the circle, it creates that symmetry within the angles. Since the circle will limit the distances of the lines, it works that way.

[@rajeevshrotriya3614]

This problem can be also solved by tangent circle theorem. 52+x=90.Hence x=38.Since the given triangle is an isosceles triangle, hence the angle which we have to find out is 38.Angle opposite to congruent side because the congruent sides are the radii of the same circle.

[@theoyanto]

Wooo hooo , learned something new.. alternate segment theorem 👍🏻

[@arturas5313]

90 - 52 =38

[@santiagoarosam430]

Triángulo COA es isósceles → Ángulo CAO =X → Radio OA es perpendicular a la tangente en A → X=90º - 52º =38º Gracias y saludos cordiales.

[@KAvi_YA666]

Thanks for video.Good luck sir!!!!!!!!!!

[@sameerqureshi-kh7cc]

Just phenomenal! Sir PLEASE make some content on O-level mathematics 👍

[@xof-woodworkinghobbyist]

If you speak French, go to Hedacademy, a high school math teacher has exercises that are not too hard.

[@AmirgabYT2185]

x=38°

[@alexundre8745]

Good Morning MASTER Yhanks to Sir A Hug From Rio de Janeiro

[@alster724]

Tricky but helpful

[@Copernicusfreud]

Yay! I solved it.

[@yamunaravi7132]

Simply super

[@PreMath]

Thank you very much

[@pk2712]

Draw a line segment from O to A . Now segments OA and OC are equal in length because they are radii of the circle . We therefore have that triangle AOC is isosoceles.Therefore , angles OCA and OAC are equal and thus equal to x . We then have x +52 = 90 because OA is a radius and is therefore perpendicular to the tangent point of the circle . We thus have x = 90-52 =38 degrees .

[@hanimahdi7244]

I suggest making proof of the theorems used in separate videos. Thanks, and best wishes

[@jonathanjose6531]

Radius to point of tendency is 90 deg, so 90-52=38 deg, since COA is isosceles, x is 38 deg

[@spiderjump]

Angle ABC= 52 ( alternate segment theorem ) Angle AOC= 52•2( angle at center =2x angle at circumference) x =180-2•52=38

[@laxmikantbondre338]

Simple way 1. Connect Radius OA 2. Angle OAC will be 90 - 52 = 38 as Radius is Perpendicular to Tangent 3.Triangleb OAC is issoscales because its 2 sides are equal to Radius. So x is 38

[@christopherellis2663]

90-54=38. 😮 ½(180-2x)=90-x

[@mohamedgamal-ze1gb]

حل مختصرالزاويةaتساوى 90 درجة (مناسب ونصف قطر )بالطرح 90ناقص 52 يكون الناتج 38درجة وهو قياس الزاوية x وشكرا

[@amelafram9949]

the easy way is the angle of the center with tangent is 90 so 90 - 52= 38

[@rahulxbeatz7658]

It's can be solved easily bye thales theoram On angle A 90 - 52=38

[@vidyadharjoshi5714]

Angle OAC = X = 90 - 52 = 38.

[@giuseppemalaguti435]

x+52=90

[@bigm383]

❤🥂👍

[@jayeshkumar3861]

No need to calculate anything. Simply 90-52.... And it's isosceles triangle.

[@ioannismichalopoulos6936]

No need of point B: OA is perpendicular to the red line, therefore x=90-52=38

[@sybermaths]

Can you help me 🥺🙏😭 GCD(a,20)=b and GCD(b,15)=c and GCD(a,c)=5 find a,b,c

[@tumak1]

This was not a tricky problem. This solution was though. See Tejas' simple way....it takes one step and voila....38 degrees!

[@alexniklas8777]

90-52=38