Calculate When New Years Occurs (The Day Of The Week) Until 2099!

[@csbkoool]

Hey love your videos ...The pace at which your coming up with content is outstanding ...great stuff and wish you loads of luck!!

[@MothaLuva]

What’s there to calculate? They occur on every January 1st each year.

[@Sant7anuKabiraj]

Hi Presh the trick is too good but I've some questions. what will be the trick if the year is in 1947, or 1987, or 1960 i mean what will be the process if the year is back from 2000. Could you help me out of this? Thank You.

[@albodios8732]

Year : 6 + 1 + (Year Code) Leap Year : 5 + 1 + (Year Code(Leap Year))

[@वैभवशर्मा-श2च]

hey what about the 2007! why you add 2 days more

[@Kino-Imsureq]

5:02 "When we divide 70 by 7 we get 0"

[@TheEgglet]

Kino -Imsure1200q facepalm

[@MothaLuva]

It’s actually when we subtract 7 from the 70, then we get 0.

[@Kino-Imsureq]

I was looking at my calendar to check; noticed octoer started on a sunday lol

[@DanielGutschik]

This makes no sense. 28 divided by 7 is 4. Please help me.

[@MonkeyAmmo]

+Danny5641 Exactly. It is asking for mod 7. a = b mod 7 is the same as saying a = b - 7m where m is an integer. Thus, 7m is a multiple of 7. So, if we are asked a = 28 mod 7 we must then look for a number m which when multiplied by 7 doesn't exceed 28. => m=4 a= 28-28 => a = 0

[@IS-py3dk]

Why doesnt this work for year 2021

[@8b15sanjaisudharsun.g7]

Can you do it for 2023

[@Kino-Imsureq]

should be wolfram alpha beta gamma delta epsilon zeta ahh iota eta uhhh

[@BlueAcidball]

Or you can just look at a calendar

[@albodios8732]

How about other centuries?

[@mihaelaivanova2419]

wait 18/7 has a remainder of 5.....

[@mihaelaivanova2419]

mihaela ivanova nvm :D

[@jamesdrinkwater3176]

u mean 4

[@rith359]

Math is fun

[@seanordonez9208]

sans day lol

[@freddisreyes5665]

this is not the best way

[@awawpogi3036]

Freddis Reyes did he said it was the best?