Calculus BC - 10.9 Determining Absolute or Conditional Convergence

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[@darcash1738]

useful tip for speed on some mcqs: approaching infinity, n^c < c^n < n! (c is a constant not in [-1, 1] bc otherwise it'd be getting smaller approaching infinity).

[@mozazoom2751]

Thank you for this helpful video, I'm wondering when you will upload the next lesseon video?

[@Puss1man]

Algebros

[@lwcky8929]

I was sick during the day we covered this and could not figure out for the life of me how to do problems like 4 & 5. finally decided to look into it before the test and finally understand it better.

[@ethanwho_]

how come in problem 2 you negated the (-1)^n+1 for alternating series test when taking the limit but in problem 3 you added the (-1)^n when u took the limit? i thought you said you suppose to leave out the alternating part. maybe in problem 3 u arent using alternating test and im just mistaking it but then what test are u using if ur taking the limit of that entire alternating series?

[@m.al7arbi465]

In the last question which is 5 , isn’t it supposed to be ( conditionally converges ) at x=2 since the series diverges there ? Why did you choose x=0 although it converges there .

[@JorgeHernandez-fi2lc]

The series is absolutely convergent from (0,2) but that does not include the endpoints 0 and 2 because the limit in the ratio test converges when its less than 1 (not less than or equal to). The endpoints would technically be divergent. That's why when he plugs in 0 it is conditionally convergent and when he plugs in 2 it is fully divergent. Hope that made sense

[@CoreFlax]

Algebros