Calculus BC - 9.9 Finding the Area of the Region bounded by Two Polar Curves

[@zsky1543]

I had example 3 on my homework and i was confused about it until you broke it down and explained it PERFECTLY. Thank you this helped a lot with overlapping curves 👍

[@danteclark8864]

out of all the videos ive watched, this one helped me the most; tyvm.

[@piercepryce3387]

The absolute best way to learn calc, thanks algebros you guys are the best !!!!

[@mingzeshen2558]

OMG thank you so much I finally understand this, I was so confused😮‍💨

[@preparedforgaming7712]

Oh my god thank you so much I finally understand this

[@alexandercoman9685]

This is an excellent video.

[@fardinkhandaker3436]

For problem number 2, why did you go from -pi/2 to 0 and not 3pi/2 to 0?

[@ahmetselim1166]

because i think it gives negative value i dont know why but we always have to use bigger upper limit than lower limit

[@harrisonthegr8526]

the lower bound should be less than the upper bound. If we set 3pi/2 as the lower bound then the upper bound would be 2pi, other wise, we could rewrite the expression as negative 0 to 3pi/2

[@reveler9013]

10:30? wtf happened, how is it so you just decided to set zero to be in this point

[@NinH-fb1ds]

I think maybe because the function -6cosø whenø=0, r=-6?

[@Emptybook-mp5pt]

well idk but if you decide to set zero in the original way it has no difference. the integral is still pi/2 to 2pi/3

[@DarthCrustyYT]

W mans

[@adrified9352]

Fr

[@phillhernandez123]

I failed

[@chi840cken6]

you philled

[@adrified9352]

😂

[@audreydaleski1067]

Too easy.