Calculus: Differentiation of natural log functions : ExamSolutions

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Are the maths videos of 2009 really helping? Yes.

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IKR? and some people expect you to pay...

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*What?* Still searching youtube for maths help?

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wel..-skip

[@ExamSolutions_Maths]

Thanks - comments like this always give me encouragement to continue with the project

[@ExamSolutions_Maths]

@Jessycar1BrumBeep From the teaching point of view, it is important to understand where the formula dy/dx = (f '(x)) / (f(x)) comes from. I often find a lot of people do not know this and this was the point of the exercise. Thanks for your comment though.

[@ExamSolutions_Maths]

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[@meetkofi]

Excellent explanation. Thank you.

[@ExamSolutions_Maths]

I, (we) use the standard results when we differentiate a single term, such as ln x, ln t, ln p, ln q etc. So the chain rule is used when we have ln (several terms). Making y=ln(t) allows us to find dy/dt and then this is used to find dy/dx via the chain rule.

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By far, one of the best maths channel on the net.

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Thankyou dearly for the clear, concise and informative explanations:)

[@ExamSolutions_Maths]

+poino11 I appreciate your comment. Thank you.

[@alextheshark1]

Cannot thank you enough, finally beginning to understand this.

[@ExamSolutions_Maths]

Alexis Quintana Good

[@rogemai]

i'm really struggling on my integral calculus.. lucky i found this video saves my day.. thank you soooooo much. :)

[@ExamSolutions_Maths]

Stick at it and you will get there - good luck.

[@ExamSolutions_Maths]

The standard results are used. Differential of ln x with respect to x is 1/x. The differencial of ln z with respect to z would be 1/z, the differential of ln t with respect to t would be 1/t and so on.

[@ExamSolutions_Maths]

@sweetrawker You are welcome

[@frhanklin.]

you were more informative than my math teacher that took 2 hours to explain this concept

[@lovelessperformance4457]

Wow! everyone else made this sound way more complicated than it truly is. Thanks! Aaron

[@IAmIbanezJoel]

I have watched numerous of videos on youtube about math, and this was the first one I actually came away totally understanding it

[@kingpew]

year 12 student, understood it very well, ty for the help

[@KnowledgeUpdated]

Ur Tutorials are great..Great Work..

[@ExamSolutions_Maths]

@pimpmymail No it applies to any composite function f[g(x)]

[@wendy_nf4778]

I got an A in maths thanks to you. Thank you!!!

[@ExamSolutions_Maths]

Congratulations and thanks for any support you give to help me keep this going.

[@ExtremeTG]

+Wendy Ydnew hey i wanna get an a just like u, i just want to know ur revision routine, what u did, it will be really helpful

[@wendy_nf4778]

+ExtremeTG I watched these KZbin videos and may a few notes.. did a load of pastpapers

[@ExtremeTG]

Wendy Ydnew and what do you think would had help you move up to an A*

[@wendy_nf4778]

+ExtremeTG To get A* you need 90%+ in Core 3 and 4. I think I should of done more work in applying my knowledge rather than learning facts. Definitely dont just do AQA past papers, but also try Edexcel and Ocr

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Thank you so much in helping us to learn maths for free. Thank you very very very x100000 much !!

[@ExamSolutions_Maths]

Herwin Ng You're welcome

[@1029Memory]

Took Calculus I last semester. My Business Calculus final is in 2 hours. Thanks for refreshing my memory. :)

[@edmosss]

This is so awesome..Thanks. I've been trying to understand this for days but this video simplified all that in minutes.....ha.haa N the acsent too is clear which improves concentration

[@RShahProductions]

Thank you! Need to rewrite my notes now but I've finished C3... that's 1 out of 7 exams I'm sitting this Jan I've covered the unit entirely for. And 1 out of 7 I can start past papers on :) Owe it to you!

[@JackJX]

So easy to understand.. Thx for the help!

[@calumyoung7172]

very helpful explanation. just what I was after. thank you.

[@mahabubadaigy4241]

U r one of the best maths teacher so far.thank you so much for clearing out my confusion.I hope u keep going.

[@ExamSolutions_Maths]

I hope to keep this going. Thank you for any support

[@BintuHurairah]

Thank You for making this! it's brilliant, because now i am able to understand it better. :)

[@ikn0y0u]

could you show how to differentiate 2^(cotx) and x(5^(3x))

[@Lewie4]

how would I workout f(x)=7x-4 where f(x)=x I know the answer is 2/3 but how do i get to that answer?

[@milaad123]

brilliant explanation Sir

[@UgoPS]

@MrValzen when you have a log function to the power of something you take the power and multiply it by the log. e.g. y=ln(x^2-1)^1/2=1/2ln(x^2-1) dy/dx=x/(x^2-1)

[@virajpatel3246]

Lovely explanation, went right over what I needed.

[@THEAPEXACADEMYOFMATHEMATICS]

I dont know how these video havent gone viral

[@ExamSolutions_Maths]

@awesomelydee Hopefully but please remember that this is all done in some of my spare time and so I cannot guarantee this.

[@only_m7md]

very good teaching thankyou

[@kiatravis976]

Bruhhhhh you made this seem sooooo easy!!!!!

[@thedankside2552]

Great explanation, struggled with this in class

[@ExamSolutions_Maths]

Pleased it helped. Best wishes

[@barkthedog]

Excellent explanation. Thank you for your videos.

[@jasonstewart6641]

You are a god send man!

[@sami-samim]

Where does the ln go?

[@faroukhassan7615]

this is very in valuable. thanks man

[@MAI-1244]

OMG!! thaank youuu sooo much i understand it from your explanation

[@xwwz4wnn]

it's an amazing video it really helped me

[@ExamSolutions_Maths]

@TimothyGregoryMusic Pleasure

[@MrValzen]

y=ln(x^2-1)^1/2 Really helped on others, but then i came across these

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I have donated a small amount (tbh, not as much as the site is worth at all), but believe me I'll donate again in future.

[@menak9929]

the derivitive of sin x is cos x

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This is Super Good!

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thankyou so much , you're an amazing human!!

[@ExamSolutions_Maths]

Pleasure

[@thewhowhatwherewhyho]

Can you simplify the derivative for the third question (dy/dx = cos x / sin x) to cot x?

[@ExamSolutions_Maths]

+mmmmmmmmmmnmnnnnnnnn Yes.

[@thewhowhatwherewhyho]

+ExamSolutions Thank you!!

[@nanopug7252]

cos(x)/sin(x) = 1/tan(x) = cot(x)

[@nazifarahmanadhora635]

what do we get if we differentiate -ln(ln cosx)

[@siiriinkoffee1580]

(1/cosx) x (-sinx) =-sinx/cosx =-tanx

[@gideonbreytenbach8728]

Thanks you helped alot!

[@laurence0492]

Cracking video Jeff

[@ExamSolutions_Maths]

@BintuHurairah Cheers. good news.♠

[@96wanny]

Hi .Ive been figured out quite long time to solve it . do you know how to do it . e^3ln x = 27 /8 can you show the workinng to get the answer

[@ollietheowner]

x=3/2 i think Use log rules to bring the 3 into the lnx giving e^ln x^3=27/3 then since e to the power of the natural log of anything equals the thing inside the natural log (in this case the x^3) you'd get x^3=27/8 then cube root to get x=3/2

[@AniqPirzada]

0:26- equation 1 is different to 2:25.

[@shafeekafadlikhzamri7068]

u are very good in teaching! keep it up! love ur videos :)

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make dua.

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thank you very much sir

[@ExamSolutions_Maths]

@milaad123 Thank you

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Thanks! Really helped me out

[@ExamSolutions_Maths]

Good to hear

[@humeranoor362]

very helpful but I have a problem for determining the derivative of y= Sin4xCos5x

[@nanopug7252]

(4sin(4x))(-5sin(5x))

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Most if the comments are from years ago. i hope you are all doing great!

[@ExamSolutions_Maths]

Yep, and I am doing great.

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Thank you!

[@ExamSolutions_Maths]

@kiogeedwardkaranja Pleasure

[@iamsopoor9]

the last minute in the video scared me for next term..

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Fab !! tysm :)

[@AboDa7mUK]

cooooooooool thanxx a lot

[@qiwelfng13]

thank you so much! it helped me a lot =)

[@sahar1usa]

I dont understand if u suppose to multiply dy/dt by dt/dx, then 1/(3x^2-1) should be multiplied to same thing 1/(3x^2-1) not 6!

[@ExamSolutions_Maths]

Sorry but I don't understand your question. Maybe someone else can offer help.

[@zohanaitor5]

multiplying dy/dt by dt/dx does not mean you do that. dy/dt is 1/(3x^2-1) and dt/dx is the differential of (3x^2-1), as we replaced the (3x^2-1) by t. Therefore it should be 1/(3x^2-1) multiplied by 6x. Hope that made sense.

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Cos 32°40' tan9°44} √sin20°19

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@manaphy490 A2

[@ExamSolutions_Maths]

@1029Memory Good luck

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love it.....

[@fjelimfiels.6954]

dy/xdx= 1/lnx

[@MultiApodyopsis]

pretty much dy/dx=g'(x)/g(x)

[@boonkeatwong4243]

damn nice! u helped me a lot!

[@ExamSolutions_Maths]

Cheers

[@RShahProductions]

Found this was great but didn't understand why the differential of ln types are 1 over, so checked out this video here: /watch?v=fmKqJ69YaTk

[@shafeekafadlikhzamri7068]

what about this qustion --> y = ln ( 1 / x )

[@ExamSolutions_Maths]

re-write as y=ln(x^-1) which then is y= -1 ln(x) So differentiating is -1/x

[@shafeekafadlikhzamri7068]

Ohh I see.. Thanks btw!

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Thaaaaaaaaaank you so much

[@ExamSolutions_Maths]

Not that I am aware of. There are no common factors.

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You are a goddamn mathmatical god

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saved my ass cheers

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1 person missed the like button and pressed dislike!! :(

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Old KZbin videos are more helpful than my maths lecturer 😪

[@ExamSolutions_Maths]

Glad you like them!

[@milaad123]

brilliant explanation sir

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Thank you so much

[@ExamSolutions_Maths]

You're welcome, thanks for watching and supporting this work.