Plzz note that at the end it's actually canonical transformation of x & y with respect to p & q but its not canonical transformation of p & q
@preetikumari1184 жыл бұрын
Hey why stopped making video this is really helpful pleaseeeee continue or start making video csir net this is really usefull for us who need some good one who explain these topics in very easy way please
@kaursingh6374 жыл бұрын
very good --please solve one example
@tayyabanawaz52654 жыл бұрын
This was not enough...
@sharontirkey5445 жыл бұрын
What is that difference between old and new Co ordinate?
@tayyabanawaz52654 жыл бұрын
Before transformation the coordinates are old one and after transformation they are known as new one. Old ones are those from which you want to transform into other ones.
@tanujavashistha82266 жыл бұрын
Can u cover all syllabus of net physics plz
@kevinfung66976 жыл бұрын
Thank you very much for clearing my doubt through this great video!!! Keep it up!!!
@account13076 жыл бұрын
Is this a transformation between reference frames, or is this a transformation of the Hamiltonian from one point in time to another?
@jatinbhatt78266 жыл бұрын
Thank you sooooo muchh bro. I was looking for it since 2 years but no one gave me satisfactory explanation but you did. Keep it up bro you are doing a noble job. God bless you ☺
@93katwal6 жыл бұрын
Plz a video on phase space dynamic
@Abhikumari176 жыл бұрын
Given that the linear transformation of a generalized coordinate q and the corresponding momentun p,. Q= p +4ap, P=q+2p. It is canonical then find the value of the constant "a". Plz sir solve this quest( msc physics previous ques..)
@ajphysicsdomain54297 жыл бұрын
Sahi h bro..
@ravibbnagar6 жыл бұрын
sir plzz aap csir net ke liye kon kon si books follow karni chaiye
@dm32486 жыл бұрын
thanks!!
@Matchless_gift6 жыл бұрын
Helpful
@account13076 жыл бұрын
I this applies to trajectories AND frame transformations :)
@Guptaamanraj6 жыл бұрын
👍👍👍👍☺️
@mfoucault19846 жыл бұрын
in minute 7:01 its a total derivative.. d/dt the rest of the video is good.