Capgemini Data Engineer Interview Question - Round 1 | Save Multiple Columns in the DataFrame |

[@kunuturuaravindreddy5879]

very good you are posting real interview questions many of them simply explain concer defentitiins

[@GeekCoders]

@@kunuturuaravindreddy5879 thanks

[@sourav_sarkar_2000]

# creating a dict of columns as to avoid checking multiple datatypes d={} for col in df.dtypes: if col[1] not in d: d[col[1]] = [col[0]] else:d[col[1]].append(col[0]) for key,val in d.items(): df.select(val).show() # write df to the location

[@myl1566]

Good problem to solve. Thanks for posting sagar!

[@GeekCoders]

Thank you

[@aamirmansuri69]

Thank you for posting this video. But, can you please post pyspark interview questions for freshers. Thank you!

[@Offical_PicturePerfect]

int_cols = [col for col, dtype in df.dtypes if dtype == 'int'] string_cols = [col for col, dtype in df.dtypes if dtype == 'string'] float_cols = [col for col, dtype in df.dtypes if dtype == 'float'] Creating DataFrames for each data type int_df = df.select(int_cols) string_df = df.select(string_cols) float_df = df.select(float_cols)

[@sourav_sarkar_2000]

# creating a dict of columns to avoid checking multiple datatypes d={} for col in df.dtypes: if col[1] not in d: d[col[1]] = [col[0]] else:d[col[1]].append(col[0]) print(d) for key,val in d.items(): df.select(val).show() # write df to the location # df.write.mode('overwrite').save(f'temp_loc/{key}')

[@Dataengineeringlearninghub]

Great problem sagar

[@vutv5742]

Completed 👏

[@rawat7203]

My Way Sir intType = [] stringType = [] floatType = [] for i in df.dtypes: if i[1] == 'int': intType.append(i[0]) elif i[1] == 'string': stringType.append(i[0]) elif i[1] == 'float': floatType.append(i[0]) dfInt = df.select(*intType) dfString = df.select(*stringType) dfFloat = df.select(*floatType)

[@GeekCoders]

Nice

[@rawat7203]

Thanks a lot Sir

[@GeekCoders]

Thank you

[@Nextgentrick]

Shouldn’t you use append instead of overwrite

[@pradishpranam6175]

cool question

[@ug1880]

Were u asked for any imocha test ?

[@GeekCoders]

No

[@ug1880]

@@GeekCoders okk...

[@pratyushkumar8567]

Hi Sagar this Capgemini Data Engineer Interview Question - Round 1 | Save Multiple Columns in the DataFrame what was the experience the candidate has ?

[@GeekCoders]

4 years

[@bhumikalalchandani321]

okay, is this internal functionality of conversion to parq format

[@rawat7203]

yes

[@2412_Sujoy_Das]

My solution is as follows: string = df integer = df float = df for i in df.dtypes: if i[1]!='string' and i[1]=='int': string = string.drop(i[0]) float = float.drop(i[0]) elif i[1]!='string' and i[1]=='float': string = string.drop(i[0]) integer = integer.drop(i[0]) elif i[1]!='int' and i[1]=='string': integer = integer.drop(i[0]) float = float.drop(i[0]) elif i[1]!='int' and i[1]=='float': integer = integer.drop(i[0]) string = string.drop(i[0]) elif i[1]!='float' and i[1]=='string': float = float.drop(i[0]) integer = integer.drop(i[0]) else: float = float.drop(i[0]) string = string.drop(i[0]) print(string) print(integer) print(float)

[@SouvikMitul]

my solution: dict={} for i in df.dtypes: if i[1] in dict.keys(): l=dict.get(i[1]) l.append(i[0]) dict.update({i[1]:l}) else: l=[] l.append(i[0]) dict.update({i[1]:l}) for i in dict.keys(): df_s=df.select(dict.get(i)) df_s.show() ##did show instead of writing