Carnot Engine Efficiency and Carnot's Theorem

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[@presentlymine]

I would have never been able to understand so many topics, if it was not for your videos. Each time here on KZbin, I type the topic with your name, and always am happy to know that you have made a video on it. Thankyou so very much! Keep posting videos.

[@sirmichael5429]

Excellent and well-coordinated. I hope some professors might learn from this clear exposition of such a complex idea. Bravo.

[@altafansari4205]

Q=U+W , process 1to 2 is isothermal hence temperature is constant hence internal energy is zero , U=0 from the above Q=W this is right

[@oneofyk]

great set of lectures

[@plyedness]

Thank you so much for explaining this! It's so clear

[@AKLECTURES]

plyedness you're very welcome!

[@J.Gaytan]

Thank you for being so succinct, unlike Khan academy this is easy to follow. thank you sir!

[@fahmylina123]

There is an error at min 1:34 when you said "adiabatic process and so temperature decreases"; in fact it increases by adiabatic compression from point 3 to point 4 to become T subscript H.

[@SarthakChaturvedi1009]

AK LECTURES I LOVE YOU!!!!!

[@AKLECTURES]

[@kittenluv17]

you are amazing. thank you so much.

[@India_that_is_Bhart]

thank !!!!!!....we hope u always help me ...

[@altafansari4205]

but if we take the sign convesion then we can write U= Q+w ( here teacher take heat is given to system is negative and workdone by the system is also negative but we can also take the oposit sign convesion)

[@rampanta3491]

What is your favourite movie?

[@gagannrao]

superb explanation .thank you

[@AKLECTURES]

Thanks! Glad to hear it!

[@gagannrao]

you are welcome

[@irnssmomgreatindiaindia1880]

Thanks Andrey Sir, Can you please discussion about how to improve the efficiency of Rankine cycle.

[@Nawazkhan-bj6me]

'eudjfjjd

[@hemanthkumar8796]

PIEASE PERFECT

[@oscarrodriguez4021]

My physics book states that carnot's theorem states that "no cyclical heat engine has a greater efficiency than a reversible engine operating between the same two temperatures"... What does this mean?

[@ZoyaKhan-we8zi]

means efficiency depends upon the difference of temperature it does not depend upon same temperature for better and maximum efficiency a difference of temperature is required

[@yuhaooo8143]

sorry. I think Ql/QH = Tl/TH is reasonable not only in carnot cycle but also in other engines. because Q=cnT

[@davidolaussen2748]

Thanks man! :-)

[@ahmedel-kholy8992]

doctor thank you , i have a question about process c : work is poistive and Q is negative so Q = - nRTLln(v3/v4) is this right or not thank you ...

[@tejakatepalli101]

u're patly right but Q in this case goes line.....Q= -nrtL ln(v4/v3) when we inverse the volumes fraction of logarithm the sign inverses

[@oscarrodriguez4021]

I haven't watch the video, but I have been reading the physics chapters thouroughly so I hope this answers your question appropriately: you're given the fact that |Qc| = nRTcln(Vc/Vd) right? (I hope this [and more] is relevent.) Well when "the heat is discharged into the cold reservoir." (University Physics 423) I'm assuming you must make the assumption that |Qh|=0. Now "the net work done BY the gas[(system)] on the piston [(surrounding)] is equal to the heat input:W=|Qh|-|Qc|... This work is represented by the area enclosed within the cycle abcd...." (University Physics 423). If |Qh|=0 then W=> -|Qc|. -|Qc|=nRTcln(Vd/Vc) so +|Qc|=-nRTcln(Vd/Vc)=nRTcln[(Vd/Vc)^(-1)]=nRTcln[(Vc/Vd)^(+1)]... Now this is is important to know -- by-the-way |Qh|=nRThln(Vb/Va) --- because it helps to reinforce the idea of thermal equilibrium. Khan from Khan Academy has a video explaining how Vb/Va=Vc/Vd. I Hope that helped you and anyone who read this far! :)

[@oscarrodriguez4021]

Sorry for the crossed out equations. "KZbin" does this when characters are embedded in hypens (-).

[@temitopeadeyemi7393]

what is the difference between the carrot and Otto cycle

[@aswinm7355]

Eunice Adeyemi carrot?????!!!

[@ZoyaKhan-we8zi]

U=Q-W but u wrote this wrong equation U=Q+W

[@jauharzahari9309]

yes, i wonder why others does not point this out. sample of exercises in Principles of Physics also uses u= q+w, which i wonder if its just a simple mistake, or is it actually not?

[@ameenkishta5534]

The reason why it is okay for him to write it as U = Q + W is because he explains that "W" is the work being done BY the system, which by default is a negative value. Therefore, making it U = Q - W anyway after inputing any work value.