I LOVE YOU,MAN. I was desperate to find someone who could explain the process, a lot of videos define without detailing it. it's easier for me to learn about this knowing what is the reason why,THANK YOU.
@sengsavang64994 жыл бұрын
Woww, a 6 min video is ways better than my whole week at school, thank you very much, sir
@david722011 жыл бұрын
I really love these videos, it helps me a lot ! Thank you for your clear speaking, as a non native english speaker i really liked it !
@argamaneric85019 жыл бұрын
Odds are slim but I really wish my son would encounter a teacher like you.
@ryuranzou10 жыл бұрын
Very helpful video! This had me stumped for a while and gives me the questions I wanted to ask myself next.
@Dini30607 жыл бұрын
Thanks alot for helping me right an essay. Felt so grateful that i logged in to youtube just to like and thank you. Keep doing vids.
@CharlesMarzzacco11 жыл бұрын
I am a big fan of your videos. I think the product of the acid catalyzed reaction is isoheptane not isooctane.
@darksamurai33311 жыл бұрын
It's an isomer of heptane, but it's not isoheptane. The molecule in the drawing is 2,4-dimethylpentane. Isoheptane is 2-methylhexane.
@nathankwan31087 ай бұрын
Thank you for the information! :)
@harisaisenthilkumar28802 жыл бұрын
that you mr bozeman. thanks from india
@jferro968 жыл бұрын
explained it better than my book, thanks!
@Polarcupcheck9 жыл бұрын
When I was taking early general chemistry, nobody covered surface catalysts. Wonder why.
@Nikolabo444 жыл бұрын
Helped me a lot!
@skylens864 жыл бұрын
Please do a vidro in detail on surface catalysts
@kirolosyassa57986 жыл бұрын
It was Helpful Video ..
@riyahalder92312 жыл бұрын
Congratulations
@milkywayandbeyond9 жыл бұрын
If a proton is added by the catalyst, doesn't it change during the reaction (it is partially used), thus not making it a catalyst?
@Turplemaple63184 жыл бұрын
Thanks brother
@Nomamegoogle5 жыл бұрын
Can i use to reduce the pressure inside a high pressure tank?
@3agamygabr5635 жыл бұрын
hello, I want to make Al2O3 Supported Au-Pd Catalyst to make Hydrogen Peroxide , any help?
@gibbs-1311 жыл бұрын
Why Fritz Haber is notorious? is it just because he looks like Yul Brynner?
@vykylam787811 жыл бұрын
the model should be named isoheptane instead of isooctane... I only see 7 carbons.
@seagul3489 жыл бұрын
thanks
@WorthlessWinner11 жыл бұрын
Aren't most enzymes acid base catalysts?
@ProdigiousMike8 жыл бұрын
Isn't that an isoheptane? 2:35
@charmncute36493 жыл бұрын
yes.it is an isoheptane. He needs a butene instead of propene.
@xiiixiiih.162 жыл бұрын
Ah bugs and proteins are cute. How do the bugs make a metal catlists
@benbrak37137 жыл бұрын
great
@mikepict90112 жыл бұрын
I really wish i was Canadian
@waterlilly61111 жыл бұрын
Haber it also known as the father of chemical warfare
@jessiegirl41310 жыл бұрын
Why do teachers say "add a proton"? Do they really mean "removing an electron, thus making it more positive"? Because protons aren't moving from atom to atom in these types of reactions.
@95dagreen10 жыл бұрын
Perhaps she meant that a hydrogen ion (a proton) is added.
@jessiegirl41310 жыл бұрын
Ok I figured it out. Yes you're right. They mean adding a hydrogen! =)
@sidewaysfcs07189 жыл бұрын
+jessiegirl413 no, a proton is temporarily added, not a hydrogen, you don't just add hydrogen in chemical reactions like that. the only situation in which you actually add hydrogen is during hydrogenation, or during reduction of organic molecules in the presence of atomic hydrogen, adding a proton is protonation.
@chiakimakovics39416 жыл бұрын
:)
@nicklasebbe81783 жыл бұрын
Kinda trash tbh :(
@sidewaysfcs07189 жыл бұрын
several mistakes with this video 1. that is not isooctane, it's an isomer of isoheptane 2. you just said that the product willl NOT form on its own, which is false, any reaction that takes place in the presence of a catalyst can take place without it as well, but reaching the equilibrium of that reaction is much slower, catalysts cannot change the equillibrium, they only change the rate at which you can reach it , even if this difference is huge, the reaction can still take place, especially in this case. even in the Haber process you're kinda of suggesting that this equillibrium is impossible on it's own, which is false, every step of that equillibrium is possible on it's own, but it's much slower and regularily we are not at equillibrium to notice it. these videos would be much more helpful without the dumbing down