Structural Theory 1 Conjugate Beam Method Problem 2 (PH)

[@theblackkaiser5748]

Pagkuha nung reactions sa moment diagram. By(12)=1/2(24x12)(8)--1/2(3x24)(9+2)

[@The_game4060]

Please how to solve the reaction

[@cebox]

Check this playlist, lahat ng problem dito, sinolve namin ang reaction sa conjugate beam. Link: kzbin.info/aero/PL5-rj23AEMNhFxt9SdSMvt6KPJ3jnnYev

[@RichmondSalamanque]

same question po.

[@motsky516]

Sorry sir pero i think positive yung reaction sa A

[@anshiii3443]

Hello po, bakit po kaya naging 1000^4 yung pag convert ng m to mm? Kasi parang magigibg mm² po ang matitira sa unit? Ty po

[@cedrixsumande2035]

bali po, ung units sa Mmax = kn-m^3 convert sa N-m: kN to N (1000) tapos m^3 to mm = (1000^3) overall po 4 na beses natin e multiply kay Mmax

[@cebox]

@cedrixsumande2035: Thank you po for clarifying his/her concern po! God bless po! 😊😇

[@jayrbendicion5118]

Bat po downward ung 45/EI positive po nakukuha kk

[@cebox]

Ano po ba engr assumed direction mo? Downward o Upward?

[@yvettecastillo-tc7je]

Hindi po ba talaga icoconsider pa ung Beam CB?

[@shinko-shi7383]

Bakit 2x po yung sa 1/2(x)(2x)?

[@cebox]

Yung sinolve na "a", engr. (Sorry for the very late reply as we are too busy finishing our master's degree thesis. Thank you for understanding and God bless you!)

[@n0rth_219]

Paano po sir if may nag overlap na area ng triangles sa pagkuha mo ng moment sa conjugate? Paano po makuha ang area at centroid distance?

[@cebox]

Have you watched all the videos po sa playlist ng CE Box - Conjugate Beam Method? Ito po yung link ng playlist: kzbin.info/aero/PL5-rj23AEMNil2eBCeM2ywA7Kj5vU16S3 May example po kami rito na, no need naman po na magoverlap yung mga drawings sa moment diagram. (Sorry for the very, very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@sisyphusishappy9925]

Sir pano naman po yung moment ng 6kn bat hindi isinama sa moment diagram?

[@cebox]

Nagmoment po ako sa B, andun po ang 6kN. M = F(d) where d is moment arm. Ano po ang moment arm ng 6kN sa B? It is zero, right? So, no moment effect para sa 6kN at B. (Hello! It's been a while since we check comments on our channel. It just happen na abala kami sa work and pagcheck ng mga papers ng mga student namin. So, we want to apologize for a very late reply and want also to greet you a very happy new year!)

[@nicoouano7942]

good day sir, bakit kN-m^3 ang unit sa Mmax? di naman same ang exponent sa equation

[@cebox]

1. Sa M/EI, Moment po yun. So, kN-m po yun. 2. Nagmoment tayo sa M/Ei diagram sa point a, so, kN-m(m) - this is a force based sa M = Force (distance). So, we need distance para maging moment. So, kN-m(m) - force multiply by distance (m) = kN-m^3. (Sorry for the very, very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@adrianmonteclaro4785]

Saan galing yung 24 ???

[@cebox]

2 (9+3) = 24. (Sorry for the very late reply. Abala lang sa masteral, work, and life. God bless po!)

[@bensauquillo7056]

Sir, hindi na po ba kailangan i draw pa ang shear and moment diagram sa conjugate beam?

[@cebox]

Hi. Sa akin kasi, hindi ko na nirerequire e, depende sa professor e. P.S. Sorry for the very late reply. Abala sa Masteral and work.

[@ashhao2657]

Pano po pag may binigay sa problem na E at I pero may given din na EI=constant?

[@cebox]

Meaning, constant ang EI all throughout the span. (Sorry for the very late reply. Abala po sa life and work stuff. God bless! 😇)

[@geraldabarca3107]

sir pano po naging downward ang 45 po?, thank you po.

[@nikobaclayo6878]

Ray(12) = -576 + 36 = -45 or 45 downward

[@rosenalzaro7889]

san po galing ang 45?

[@cebox]

Reaction po yun sa support sa conjugate beam, you should solve for the reactions po sa mga support sa conjugate beam using the equilibrium condition such as ∑Fv, ∑Fh, and ∑M.

[@tatinabad223]

Pano niyo po nakuha yung Ra = 45, and Rb = 63.

[@Unfilteredjeni]

Summation of moment po sa B, lalabas po si Ay which is -45. Pag summation of moment @A naman po lalabas po si By which us -63.

[@junmarkberroya9351]

Paano po e solve yung reaction?

[@junmarkberroya9351]

Bat nakuha niyo po yung 45 at 63?

[@iamloser3367]

sample po ng may dalawa or 3 na force at paano po yun e moment

[@cebox]

Have you checked Prob 3, 4, and 5?

[@johncarlodablo3908]

Paano po naging 45? Hehe

[@cebox]

Solving of reaction na lang po ityon. Reaction po yun sa support sa conjugate beam, you should solve for the reactions po sa mga support sa conjugate beam using the equilibrium condition such as ∑Fv, ∑Fh, and ∑M. (Sorry for the very late reply as CE Box is very busy with his Master's Degree, Accreditation, Work Stuff, and Life. Thank you for understanding. Keep in touch with CE Box as we plan to do more video tutorials.)

[@angelikagonzalgo1327]

46 po Ang nakuha ko na reaction huhu hndi 45

[@chrishnajoylinga6651]

Summation of Fy=0 Ra+1/2(24)(12)-1/2(24)(3)-63=0 Ra= -45 (downward)

[@cebox]

@@chrishnajoylinga6651 Thanks for this po!

[@salvabenzmarcl.9376]

@@chrishnajoylinga6651 san po nanggaling ung negative 63

[@receeva9985]

​@@salvabenzmarcl.9376 Pwede ka kahit saan mag moment para makuha si reaction A and B, para makuha si By = -63kN kay, Summation of Moment of A = 0 counterclockwise positive (assumed direction (+)): By(12)+ (½(24)(12))(⅔(12))-(½(24)(3))(⅔(3)+9)=0 Tapos shift solve, ang answer would be By = -63kN or 63kN ↓ (downward)

[@camilledelacruz4761]

nakakahilo😵‍💫

[@cebox]

Kaya pa po yan!!! (Sorry for the very late reply. Abala sa life and work stuff. God bless po! 😇)

[@jeffhenrygan2371]

Di sana nag shortcut

[@cebox]

Ano po yung shortcut na tinutukoy po ninyo?

[@rolansaladaga8228]

@@cebox in geeting the reaction sir sa conjugate beam yung 45kn hehe

[@cebox]

@@rolansaladaga8228 Yes. We know po. But we do not consider that as shortcut. Solving the reaction is a basic concept na lang po under sa Conjugate Beam Method. Una pa pong naaral at naituro ang pagkuha ng reaction from Statics of Rigid Bodies pa. Our topic here is Conjugate Beam Method, not on How to Solve the Reaction in the Conjugate Beam. So we didn't do anything that is shortcut under conjugate beam method. Ang shortcut po is yung magpupunta ang student sa mga problem without even watching the introduction to gain the knowledge or concept na need nila for understanding on how to solve such problems po. We hope you understand that po. And we all know na hindi po ninyo kasalanan na hindi magets ang pagsolve ng reaction, pero it doesn't mean na hindi ito kakulangan sa student, so student must know "how to solve the reaction of a basic simply supported beam" bago po muna sana magpunta sa mga ganitong klase ng topic.

[@cebox]

@@rolansaladaga8228 Not unless if complicated po ang conjugate beam, pwede pa po namin itong isama sa discussion. Pero nakakalungkot po yatang malaman na simply supported na lamang po ito, and then nasa Conjugate Beam Method na po ang ilang students (which is very far topic from Statics of Rigid Bodies Chapter 3 Equilibrium of Force System), samantalang hindi pa rin po alam magsolve ng reaction...

[@HashemAljifri515]

I don't understand do you speak English?

[@cebox]

Hello! Unfortunately, we don't have much time or free time to make and add subtitles on our videos due to heavy schedule and currently finishing our master degree thesis. But once we have enough time to do so, we will start making and addig subtitles. Sorry for the inconvenience. (Sorry for the very late reply as we are too busy finishing our master's degree thesis. Thank you for understanding and God bless you!)