लोकसेवा प्रारम्भिक (GK+IQ & ENG) नमूना परीक्षा Set 8 Feedback Class- Madan Khadka & Naresh Timilsina

[@sumanadhikari1289]

Gk काे समाधान पनि राखिदिनु भए सहज हुनेथ्याे नि।

[@sujataojhaiya4592]

Thank you sir

[@nabinaprajapati6442]

Q.70 answer should be option B(65)

[@nabinaprajapati6442]

Q.71 ans C (27)

[@kamalmainali7007]

misranma dudh 35l ra pani 5l xa,aba 35/(5+x)=3/1 or,35=15+3x or, x=20/3=6.66l option(A)

[@nituyadav6778]

GK ko answer pani rakhdini hunthyo ki please sir

[@kamalmainali7007]

QN (51):2m+3w=1/8........eq(1),3m+2w=1/7........eq(2) we have,(2+3x)/(3+2x)=5/4 or,x=3.5.Multiplying eq(2) by 3.5 and adding with eq(1) we get 12.5m+10w=5/8 or,2.5(5m+4w)=5/8 or,5m+4w=1/4 So.5m+4w can finish the work in 4 days i.e.,option(c) answer QN(52):sum of all 3 digits number=sum upto 999-sum upto 99=999x1000/2-99x100/2=1000/2*(999-9.9) =1000/2*(989.1)=1000*494.55=494550 i.e.,option(C) answer

[@kamalmainali7007]

QN(54):sum of all numbers between 200 and 600 which are divisible by 16=208+224+240+........+592=16(13+14+15+.....+37) =16(37*38/2-12*13/2)=16(703-78)=16*625=10000 option (A) answer

[@krishnaprasadacharya7599]

How to join madhav sir

[@kamalmainali7007]

QN(57):here area of all triangles ACB,ADB,AEB and AFB are same since base is same and height is same for all.BUT we know that the perimeter of a triangle will be minimum if the triangle is isoscles ,so the distance AF+FB is minimum SO, option (D) is correct. EXPLANATION:we have a=2RsinA,b=2RsinB or,a+b=2R(sinA+sinB)=4RcosC/2*cos(A-B)/2 so,a+b will be minimum if cos(A-B)/2 has its maximum value i.e.1 so, A-B=0 or,A=B

[@trickloksewa5441]

Solutions ni sir

[@sanjipy]

Thank you sir