Central Difference Approximation | Lecture 61 | Numerical Methods for Engineers

How to approximate the first and second derivatives by a central difference formula.
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[@sonukumarbhaskar8937]

THANKYOU SO MUCH SIR . I AM ABLE TO SCORE COMPLETE 6 MARKS IN MY BSC HONS MATHEMATICS EXAM OF DU ...... GOT 98 OUT OF 100

[@majormelon8855]

wow that explanation was soooooo much better than my professor. Thanks!

[@MOHAMMAD07854]

that has been amazingly helpful, thanks for the effort

[@pey3243]

how about getting the third and fourth derivative?

[@mugerashalifu9539]

I appreciate your work sir

[@mortenviersimensen4316]

great video. Thanks

[@sudhakarmathsacademy]

Great explanation sir thank u

[@rizkamilandgamilenio9806]

Great explanation sir!, but i still dont understand why its equal to O(h^2), please sir or anyone let me know the explanation

[@user-do2vu1kv2i]

because when we look at the first derivative we multiply it by h, next term (second derivative) cancels and we have next but one term that multiplies by h^3 what means h*h^2 and when we divide it by h, we have h^2

[@fuji4128]

what if I wanted a finite difference of a priorly selected Error? say the first derivative of Oh^4 Error?

[@chrisluala9937]

What about 3rd derivative sir?

[@asapglacier]

Okay I might be dumb… but is this man writing backwards or how does this work

[@ProfJeffreyChasnov]

Software

[@IonizedComa]

He probably mirrored the video in post

[@jayeshjadhav4579]

QUESTION: Does having higher Order of ERROR (here O(h^2)) mean that I can diffrentiate a Funtion Upto That order (2) without having any error OR habign the Minimum numer of Order for a Function in order to Have Maximum ACCURACY? can anyone please Explain...thank you

[@papidepiso]

Thank you 😊

[@VikkuGoyal]

Thank you

[@lovesonmukombiwa3093]

Thanks proff

[@donathakamugisha-fz7hs]

Nice

[@kaursingh637]

my lord - excellent -which country ? which university ? amarjit india

[@ProfJeffreyChasnov]

HKUST, Hong Kong

[@zbryce1106]

Elegant