74HC595 Shift Register Tutorial | Arduino with 7 segment

[@jozsef_nagy]

You could reduce bouncing by running the signal through a Schmidt inverter

[@ziancatacutan1878]

Super clear explanation!!!

[@roshnivalder1394]

Real Engineer showing how the circuit works, Well done

[@electronicphilia1687]

How many digits we can control with single 74Hc595 Shift register

[@talhamanzar9992]

Thanks a lot Sir for explaining the concept of 74HC595 in full detail...Sir plz explain how to program Arduino for controlling 7segment connected to 74HC595. 🙂

[@CETech4u]

Do share the video and consider subscribing to the channel!

[@talhamanzar9992]

@@CETech4u ok Sir..👍... Subscribed..!

[@Sekhar_Home]

Best explained. Able to understand now after ao many seeing videos. Thankx. This is indian style learning process

[@embeededtinker7005]

Only an Addict can Explain like this....! 👌👌

[@CETech4u]

I'm glad you liked it. Please share the video as much as possible and do subscribe to the channel.

[@ID-TheArtist]

great 👌👌

[@Hunefsus]

Very well explained

[@rahulk04071996]

Just amazing.....best explanation..i have learnt a lot of things from your videos....

[@CETech4u]

Its folks like you who motivate me to keep going! Thanks a lot.

[@manojmaniyan9864]

Hi, I think I have an issue with the shift register. am using TPIC6C596 shift register and this register is capable of sending 8 bits. When I start sending 8 bits, I am getting only the last bit (i.e decimal point). But without the 8th bit (decimal point), my shift register can transfer whole 7 bits at a time. May i get the solution for this? When I implement in the proteus I am getting proper output. while doing the same in the hardware, I face the issue. For example, 0b00000110, I am getting the value as 1. if i do, 0b00000110 | 0b10000000, I am getting only .(dot) without 1. I should get 1.(one + dot). shiftOut(DS_pin, SHCP_pin, MSBFIRST, dec_digits[(buf[i] - 0x30)]|0x80); What will be the issue.? 0r my doubt is when supply goes to decimal point, all the other pins goes to OFF condition. When supply don’t go to the decimal point, all the other pins goes to ON condition. Is that correct?

[@TheDefpom]

Nice explanation, well done.

[@CETech4u]

Glad you liked it! Do consider sharing the video and subscribing to the channel. Also, I love your work.

[@Kanchan_Das]

Bro it's Awesome explanation 🙂

[@CETech4u]

I'm glad you liked it. Please share the video as much as possible and do subscribe to the channel.

[@sumit2k]

very well explained...Thanks

[@CETech4u]

I'm glad you liked it. Please share the video as much as possible and do subscribe to the channel.

[@ziancatacutan1878]

Super clear explanation!!!

[@CETech4u]

Thanks mate!

[@Kanchan_Das]

Need more application 🙂😇

[@CETech4u]

Publishing a project article on that soon.

[@HoXDipannew]

One of the best project in 2020