A WEIRD VECTOR SPACE: Building a Vector Space with Symmetry | Nathan Dalaklis

  Рет қаралды 2,295

CHALK

CHALK

Күн бұрын

Пікірлер: 19
@CHALKND
@CHALKND 4 жыл бұрын
I obviously struggled with my camera here... At least the Chalkboard looks good! 😂😅
@sadface7457
@sadface7457 4 жыл бұрын
Not even 7minute in and the notion that group symmetry are permutation and these permutation can be transposed on graph is fascinating.
@CHALKND
@CHALKND 4 жыл бұрын
😀 Although I didn’t really go too far deep into the group theory stuff, I’m glad it was recognizable! Thanks!
@sadface7457
@sadface7457 4 жыл бұрын
@@CHALKND The video would have be better surved as trilogy of videos to give each concept room to breath, but excellent non-the-less.
@CHALKND
@CHALKND 4 жыл бұрын
Haha I agree! 😂 When I was drafting the boards for this the thought definitely crossed my mind, but then I realized that I hadn’t published in a few weeks 🙃
@sadface7457
@sadface7457 4 жыл бұрын
@@CHALKND I understand that a polynomial is vector space. Is symmetric polynomial just polynomial where the invatient (doesn't chanhe) if you change the variables p(x, y) = x + xy+ y is symmetric because x can become y and vice versa without changing anything. My understanding is that polynomials vectors because you can decompose then into the dot product of two vectors. The additional operation comes from it being a ring.
@CHALKND
@CHALKND 4 жыл бұрын
You’re right that function is symmetric because you can switch x and y and still have the same function. Now thinking about the dot product decomposition; Are we talking about taking the coefficients to get a vector in R^n and doing the dot product on those? Sure that works for polynomials in R[x] that are restricted to be at most degree n, but here I think you would need to do a bit more work since we have more than one variable we can’t just translate x^n to the nth position in the vector and we’re not setting a minimal degree for these symmetric polynomials. Also, vectors do not require a dot product to be vectors. In the definition we only require that they ‘play well’ with the operations of + and scalar multiplication. There are many different inner products that one could define on any given vector space, it is a different mathematical object that one can add to a vector space, although in many cases helpful, it is not required.
@samuelmat97
@samuelmat97 4 жыл бұрын
I like your videos and the way that you present. Congrats ! About the content, I've never seen it before. Interesting
@CHALKND
@CHALKND 4 жыл бұрын
Thanks! I’m glad I was able to show you something that you haven’t seen before!
@hannahmiller5515
@hannahmiller5515 2 жыл бұрын
I can't follow what you're saying at all, but I've listened to this video twice while at work because your voice is very reassuring haha!! I hope to understand what you're talking about some day
@nicholascimaszewski4453
@nicholascimaszewski4453 3 жыл бұрын
Love this video. I had a question though - I thought that function composition notation would necessitate that you write "f circle pi" rather than "pi circle f", since the rightward function gets applied first, and because pi is a permutation, it should be applied to (x1,...,xn), rather than the scalar output of f(x1,...,xn), right?
@CHALKND
@CHALKND 3 жыл бұрын
Hi Nicholas, this is a great question! In the context of this video, we are thinking of π as a function from a polynomial ring R[v_1,v_2,v_3,v_4,..., v_n] to itself. So in this context, the output of f is not a scalar. Instead f constructs an abstract polynomial that lives in the polynomial ring R[v_1,v_2,v_3,v_4,..., v_n], and that's why the parenthetical statement "(π operates on indices)" around 11:03 still makes sense with the notation of π \circ f. With this in mind, the vector space of symmetric polynomials of the polynomial ring R[v_1,v_2,v_3,v_4,..., v_n] is the subset of R[v_1,v_2,v_3,v_4,..., v_n], call it S, where every permutation of indices π just acts like the identity map when restricted to S. If you're taking the approach that f is a function from R^n -> R for example, then yes, I agree, the notation would need to be flipped.
@nicholascimaszewski4453
@nicholascimaszewski4453 3 жыл бұрын
@@CHALKND Got it, thanks. Love your channel, excited to see more videos!
@iangrant8174
@iangrant8174 4 жыл бұрын
Cool, because this whole "world is on fire thing" is _boring!_ 😀💓
@CHALKND
@CHALKND 4 жыл бұрын
😂😂😂
@iangrant8174
@iangrant8174 4 жыл бұрын
This is a really beautiful little thing!!! Here are some vague ideas for applications: logicafterthought.blogspot.com/2020/04/how-to-be-genius-part-ii.html
@iangrant8174
@iangrant8174 4 жыл бұрын
And it does sound _very weird,_ but I love _anything_ to do with cemeteries!
@iangrant8174
@iangrant8174 4 жыл бұрын
This is awfully vague, but I have a feeling that the early history of vector spaces included a (somewhat prematurely truncated) branch of development via Hamilton's ideas of quaternions, and Clifford Algebras which may turn out to be very interesting. See arxiv.org/abs/0907.5356
@CHALKND
@CHALKND 4 жыл бұрын
This looks like an interesting read. I'll definitely take a look! Thanks! 😀
Abstract vector spaces | Chapter 16, Essence of linear algebra
16:46
3Blue1Brown
Рет қаралды 1,4 МЛН
How to treat Acne💉
00:31
ISSEI / いっせい
Рет қаралды 108 МЛН
Sigma Kid Mistake #funny #sigma
00:17
CRAZY GREAPA
Рет қаралды 30 МЛН
How to Remember Everything You Read
26:12
Justin Sung
Рет қаралды 2,3 МЛН
Vector Space
18:04
Prime Newtons
Рет қаралды 100 М.
A Swift Introduction to Geometric Algebra
44:23
sudgylacmoe
Рет қаралды 898 М.
Dirac's belt trick, Topology,  and Spin ½ particles
59:43
NoahExplainsPhysics
Рет қаралды 450 М.
But what is a convolution?
23:01
3Blue1Brown
Рет қаралды 2,8 МЛН
I made maps that show time instead of space
10:44
Václav Volhejn
Рет қаралды 1 МЛН
How to treat Acne💉
00:31
ISSEI / いっせい
Рет қаралды 108 МЛН