[Chapter 7] #3 Zero covariance and independence

[@melvinpeymani6183]

Expectation of X^3, E[x^3] shouldn't be integral of x.(x^3) dx based on the expectation formula?

[@aryamallick5426]

no bro

[@themazeisntmeantforyou4284]

Nigga WAT

[@username32689]

X^3 = X*X*X of the random variable X. As we know, X ~ Unif(-0.5, 0.5). From the definition of the uniform distribution, we have the pdf f(x) = 1/(0.5 - (-0.5)) = 1/1 = 1, for -0.5