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Check for Stability of Signals

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TutorialsPoint

TutorialsPoint

Күн бұрын

Check for Stability of Signals
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Lecture By: Ms. Gowthami Swarna, Tutorials Point India Private Limited

Пікірлер: 57
@TutorialsPoint_
@TutorialsPoint_ Жыл бұрын
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@mahakhan9762
@mahakhan9762 4 жыл бұрын
this is such a tough topic in my signals class, thank you for going over every single example possible!!
@geovannyferrera5430
@geovannyferrera5430 3 жыл бұрын
Cute :)
@geovannyferrera5430
@geovannyferrera5430 3 жыл бұрын
@Calvin Calvin 🤔 yeah sure like if I am going to do something. Just let it be 😂. It was a comment that if it is true you can just forget about it.
@vedantparte4462
@vedantparte4462 4 жыл бұрын
Trust me guys shirft playback speed to 1.25 👌. Thank me later
@karuppasamykk7404
@karuppasamykk7404 4 жыл бұрын
Thank u man!!
@harishkumar-ws2ec
@harishkumar-ws2ec 4 жыл бұрын
I set my playback speed at 1.75
@-AbimanyuM
@-AbimanyuM 4 жыл бұрын
Thanks
@liounique1177
@liounique1177 4 жыл бұрын
@@-AbimanyuM Welcome.
@user-bd8ee5dd6x
@user-bd8ee5dd6x 2 жыл бұрын
Thanks dude
@AbhishekKumar-yv6ih
@AbhishekKumar-yv6ih 4 жыл бұрын
An ideal impulse function is a function that is zero everywhere but at the origin, where it is infinitely high. However, the area of the impulse is finite.
@ImamulHasan717
@ImamulHasan717 2 жыл бұрын
How a impulse function is unbound function?
@user-jz7vf6hd4m
@user-jz7vf6hd4m 8 ай бұрын
Thanks 😊 a lot, you have helped me about this subject signal
@ahmedzolali2808
@ahmedzolali2808 2 жыл бұрын
Thanks lady, it was a helpful video to solve my assignment😁
@sobangaming1881
@sobangaming1881 6 жыл бұрын
nice mam. I understood all problems. Thanks
@kumarnripendra2666
@kumarnripendra2666 5 жыл бұрын
In Vth problem, if we put some finite value at place of x(t), y(t) comes as zero and it should not be considered unbounded. So there is some confusion.
@Wheelie1999
@Wheelie1999 3 жыл бұрын
The definition of the dirac delta function states that when it's argument is equal to zero, it's amplitude is infinite. Therefore it is not bounded for all t and is unstable.
@xoxnerd
@xoxnerd 7 ай бұрын
very clear teaching!!
@sakthimathi1964
@sakthimathi1964 4 жыл бұрын
Thanks mam
@devkumar9889
@devkumar9889 Жыл бұрын
Why u haven't used Impulse response method ?
@vanisood3140
@vanisood3140 6 жыл бұрын
How is an impulse function an unbounded function?
@akshaysachan6029
@akshaysachan6029 6 жыл бұрын
Impulse function gives the slope of unit step function so it is zero at all points except at t=0. At t=0, the step function suddenly changes it's value from 0 to 1 so the rate of change is infinite as the change is instantaneous and therefore the impulse function is unbound.
@sruthitnair3199
@sruthitnair3199 4 жыл бұрын
Impulse signal have value only at orgin and that value will be infinity .if it's specified as unit impulse then it's value will be 1
@sravanigopisetti2179
@sravanigopisetti2179 4 жыл бұрын
y(n)=ne^|x(n)| is stable or not
@nareshbhatta8207
@nareshbhatta8207 2 жыл бұрын
Hats off mam. 👏
@shreyasingh5750
@shreyasingh5750 4 жыл бұрын
how impulse function is unbounded signal? Its value is 1 at t=0.
@neerajpiparia7199
@neerajpiparia7199 4 жыл бұрын
The value of unit impulse function is 1 at t=0 but the value of impulse is infinity at t=0
@shreyasingh5750
@shreyasingh5750 4 жыл бұрын
@@neerajpiparia7199 ok, got it
@aksharaviju6624
@aksharaviju6624 4 жыл бұрын
@@neerajpiparia7199 you just cleared a major doubt of mine.. Tysm!
@sibanisasmal6405
@sibanisasmal6405 4 жыл бұрын
but if we consider cos wt infinite then it will be undefined then it will not be stable in 2 question
@prakharn11
@prakharn11 3 жыл бұрын
Ma'am plz explain why Impulse signal is Unbounded.
@sowmiyar1547
@sowmiyar1547 5 жыл бұрын
How impulse function is unbounded signal??
@tusharsharma-jq6hx
@tusharsharma-jq6hx 5 жыл бұрын
at n=0 the output shoots up to infinity, thereby making it unbounded.
@shreyasingh5750
@shreyasingh5750 4 жыл бұрын
@@tusharsharma-jq6hx as show in just previous video, at t=0 impulse function has value=1.
@himanshuverma2586
@himanshuverma2586 4 жыл бұрын
@@shreyasingh5750 we are just taking the amp of impulse as unity
@edwinmbung7268
@edwinmbung7268 3 жыл бұрын
YOU ARE A STAR
@shafagh_projects
@shafagh_projects 4 жыл бұрын
simply great tutorial
@NikhilSwamiExperimental
@NikhilSwamiExperimental 4 жыл бұрын
with practice mam became a great teacher!
@shyamreddy6337
@shyamreddy6337 4 жыл бұрын
akkaa thanks i used watch every topic
@johnhosannav4704
@johnhosannav4704 3 жыл бұрын
Mawa akka super mawa ,nanu kuda follow avutha akka ni
@shreyap337
@shreyap337 3 жыл бұрын
Plz explain me ,how we get 4 in the last prblm, that is while explaining discrete function in graph u say 4 why???
@MarinikiPnevmatikou
@MarinikiPnevmatikou 3 жыл бұрын
Because they get added from 0 and on.
@rishabhkumar1050
@rishabhkumar1050 2 жыл бұрын
stablity of systems are checked here nit signals
@Lifeslovers
@Lifeslovers 2 жыл бұрын
Thank you mam
@mandarpatil1930
@mandarpatil1930 4 жыл бұрын
Why impulse signal is unbounded signal?
@MuhammadZeeshan-yg3ky
@MuhammadZeeshan-yg3ky 4 жыл бұрын
Because it can be approximated by a rectangle with infinitesimally small width and infinite height. Dear, the point is that causality must be satisfied for all times. Due to this reason, the above system is non causal. If you like the answer, please watch the following video and subscribe our channel. kzbin.info/www/bejne/iKGkdGWdpZdpd8k
@enzxo7154
@enzxo7154 3 жыл бұрын
great tutorial
@lakshitasharma3072
@lakshitasharma3072 4 жыл бұрын
Thank you ma'am!
@ShamimHossain-xe1cw
@ShamimHossain-xe1cw 3 жыл бұрын
good job
@PankajSingh-dc2qp
@PankajSingh-dc2qp 5 жыл бұрын
Beautiful mam
@rk-zv1ol
@rk-zv1ol 2 жыл бұрын
143
@ajoymalakar
@ajoymalakar 3 жыл бұрын
xe(t)= 0.5[x(t)+x(-t)] xo(t)= 0.5[x(t)+x(-t)] need solution sir
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