Circuit Analysis using Laplace Transform | Network Analysis

[@ALLABOUTELECTRONICS]

For other useful videos related to Laplace Transform, check this playlist: kzbin.info/aero/PLwjK_iyK4LLD8Cdj0SKiMZFoK2d3eE6v2&si=zPi5_EwlASecoTIR

[@saurabhbaidya5304]

Sir coordinate system and transformation stady this chapter please

[@Stevensmith30247]

Just now I searched for the same topic and came the notification of yours.

[@jaseemajasmin5296]

Thankyou so much for this wonderful classs❤🎉

[@NshimiyimanaNorbert-bu8rg]

We really thank you you are helping us understand more than we would imagine if its possible call tell us On sit transistor

[@mayurshah9131]

Very informative 🎉🎉

[@SophiaNguyen-be5yk]

amazing video, pls keep going

[@rsii1322]

Have you also made lecture videos on Three phase circuits?? And I really appreciate your hardwork..

[@itzz.arushi]

Thank you so much sir

[@1InAll.]

Sir my dought is that in first question final answer was written without u(t) But second Question final answer was written in terms of u(t), why?

[@ALLABOUTELECTRONICS]

In the first example, I forgot to write it. But while writing the output, one should always write it.

[@1InAll.]

@@ALLABOUTELECTRONICS Thanks

[@ani.281]

At 10:57 in the first question why did u write u(t)=1/s i mean how😅

[@GlobalGrooveTrends]

In the first example, why do we introduce root 2 squared?

[@punnabratachatterjee5681]

Sir did you explained convolution theorem in this video series

[@abhi3456-j2u]

no

[@David_94]

5:01 thanks for the video, what does it mean that the inductor has an initial current I(0-)? Is it like there's an initial magnetic field on the coil without being connected to anything or what does it mean?

[@ALLABOUTELECTRONICS]

It means that, the initially inductor was connected to some other circuit. And because of that, there is some flow of current through the inductor. Now, as you know, the inductor opposes the instantaneous change in the current. That means even after disconnecting it from the previous circuit, and connecting it to the new circuit, immediately the same current will continue to flow through the inductor. So, in the newly connected circuit of the inductor, that current will be the initial current through the inductor. I hope, it will clear your doubt. For more info, you may check this video, which I have made some time back. kzbin.info/www/bejne/aYrMn6CYoLpjeqcsi=RzjcX-HDj1lVEQ5e

[@David_94]

@@ALLABOUTELECTRONICS thank you, as always excellent explanations 🙏

[@fyz3rr]

sir what is the frequency shifting property?

[@ALLABOUTELECTRONICS]

I have covered it in this video. Please check the link : kzbin.info/www/bejne/aaC3pI2tlrGde5osi=KIo3zJHOcglOoNEH

[@rudrakshjain8492]

While writing the s domail equivalence of inductor, when we get the term v(s) = Lsi(s) + Li(0-), why does that translate to an inductor of ls inductance? Wouldn't that have a different voltage?

[@ALLABOUTELECTRONICS]

This is S-domain circuit. In the S-domain circuit I(s) is the current in S-domain. So, Ls represents the equivalent inductance in S-domain.

[@abinroy7800]

in example 2 how does v0(s) become 4*i(s) where does 4 come from

[@ALLABOUTELECTRONICS]

It is as per the ohm's law. V = I x R. And here, R is 4 ohm. So, Vo (s) = 4 x I(s). I hope, it will clear your doubt.

[@achalchoudhari8276]

why did you multiply 3s on both side ? 13:34

[@ALLABOUTELECTRONICS]

On the right hand side, after simplification, in the denominator you will get 3s. So, that is why both sides have been multiplied by 3s.

[@urnoob5528]

can i solve ac circuit this way instead of the phasor domain? man i really hate dealing with complex numbers a quick look and i cant seem to find how to solve the phase in s domain seems only for transient analysis so im stuck with phasor? will it actually be harder to solve ac using s domain than phasor domain?

[@ALLABOUTELECTRONICS]

Yes, for sinusoidal analysis, it is better to solve it using the phasors. If you deal it in the s-domain, then it involves a little more mathematics. (Finding the Inverse Laplace Transform is additional step). Moreover, if you deal it in the s-domain, then the response of the circuit contains both transient and steady state response. If you just want to consider steady state response, then first you need to remove the transient response. (The terms which contains decaying exponential terms) On the channel, through different videos and different solved examples, the ac analysis of the circuit using the phasors have been already covered. If you required, you can check the playlist of network analysis. kzbin.info/aero/PLwjK_iyK4LLBN9RIDQfl9YB4caBYyD_uo&si=RnvwjOP3Cc03xiZp

[@sudipbiswas4718]

16:05 sir how it is time shifting?

[@ALLABOUTELECTRONICS]

It is a frequency shifting property.

[@قيامةعثمانالموسمالرابع]

ممكن تفعيل الترجمه لو تسمح

[@ALLABOUTELECTRONICS]

Just wait for some time. It will be available after some time.

[@قيامةعثمانالموسمالرابع]

شكراً شكراً ❤

[@kamalmcplover723]

Sir can you perform this in programming for better explanation