Moment Distribution Method with sinking support: kzbin.info/www/bejne/hYmvo4OlmbeIfJI
@bhandariakshaykumar51422 жыл бұрын
It was crystal clear and explained very well... Very well executed the sum explanation.. We want this type of teacher in our country
@learncivilwithparam1702 жыл бұрын
kzbin.info/door/gSu05skHs7WxhTd3doO1eg
@premsaimarella56163 жыл бұрын
Bro I think you had made mistake in the step of 2/3+3/8 which is 25/24. Thus the value of EI(ib) is 14.4
@Civillearningonline3 жыл бұрын
You are right bro.
@mr.gubagub18992 жыл бұрын
Thanks bro I was confused because of this idiot
@aayushpathak6120 Жыл бұрын
Exactly
@aayushpathak6120 Жыл бұрын
He took deflection at c zero
@ankushchoudhary8086 Жыл бұрын
3/5 is the right value
@parveenantal31633 жыл бұрын
Mistakes are the sign of something good.. You are doing such a amazing work sir... Respect 💐 and keep it up.stay blessed.
@sahil86962 жыл бұрын
Wonderful✨😍
@faladeadetola62872 жыл бұрын
Summation of moment at point B ought to be equals to zero (MBA+MBC=0)
@Civillearningonline2 жыл бұрын
Yes. Right
@mohdwasim34383 жыл бұрын
Bro handwriting is superb 👍
@waseemofficial53342 жыл бұрын
Welldone
@tlnnarasimhamurthy15293 жыл бұрын
Wt about step 3 final that is 24/25 didn't get how 25 will come ?
@revanthl92763 жыл бұрын
I think he made mistake when we do the lcm it becomes 25/24 because (2/3+3/8)
@rahulrathee79992 жыл бұрын
Sir shouldn't it be 25/24 EI ib In last line of 3rd step
@gphanichetan2824 Жыл бұрын
bhai everything is perfect but agar question mein find the slope bole toh final answer kya likhna hai?
@Deekshith98443 жыл бұрын
Bro formula is wl/4 not wab/L
@Civillearningonline3 жыл бұрын
Yes you are correct. And i have used both the formulas at the end the result is same. So don't hesitate just prepare well. Thanks.
@rufusmatthew5664 Жыл бұрын
Superb
@fathimashinmiyal95903 жыл бұрын
Sir..pls confrm the value of EIib..it's not 125/8 ..correct value is 72/5
@fathimashinmiyal95903 жыл бұрын
Then only the final moments value will be same..
@Civillearningonline3 жыл бұрын
Yes you are correct. I am extremely sorry for this. It has happened because i have mistakenly written 25/24(EI.ib) =15 as 24/25 (EI. ib) =15. Thanks alot for letting me know. By the way i have another video in hindi on same topic. And i am sure you are going to find it very helpful. Have a nice day.
@Civillearningonline3 жыл бұрын
Slope deflection method in hindi: kzbin.info/www/bejne/p4KkonqYgJZsi6M
@alaganijagadeesh13683 жыл бұрын
Sir, for simply supported using formula 3EI/L... we get other valves of final moments and for simple supported using normal formula 2EI/2... Getting different values why?
@Civillearningonline3 жыл бұрын
The formula which you have asked for I myself have consulted to my teacher when i was in college. And they suggest me to use the formula which i have used in this video. No doubt the formula which you are showing is correct but it's actually not used when you have a look in some higher books.
@Jaydev-oj2hx2 жыл бұрын
Bro, u told that for midspan, moment is Wl/8 in the beginning, but 12:35 here u put Wl/8. Why?
@Civillearningonline2 жыл бұрын
Yes dear. While calculating fixed end moment we use WL/8. And at the time of drawing BMD we need to use wab/l for point load and wl^2/8 for udl. Hope you understood.
@Jaydev-oj2hx2 жыл бұрын
@@Civillearningonline yes sir. Thanks
@shashwatpoudel72732 жыл бұрын
Ramro sanga van na ehh
@Civillearningonline2 жыл бұрын
Playlist hera. Aru pani video xan. That will help you a lot.
@SandeepYadav-bj1zl3 жыл бұрын
You played many gemics in this video not yet clear
@Civillearningonline3 жыл бұрын
You can check for some other videos. I have created a seperate playlist on this method with extra examples.
@powerstar763 жыл бұрын
Bro u told that upwards direction is - it's downwards means +
@Civillearningonline3 жыл бұрын
It's sign convention for find shear force.
@abhishekpatil63803 жыл бұрын
Sir can we get still more problems
@Civillearningonline3 жыл бұрын
There more such problems i have discussed you can check out the playlist or description.
@paruvumanoj81673 жыл бұрын
Sir the value of Mcb is zero right then why haven't you substituted while drawing in diagram?
@Civillearningonline3 жыл бұрын
Support C is simply supported but span CD is overhanging so the moment due load on CD is transferred to support C.
@paruvumanoj81673 жыл бұрын
@@Civillearningonline ok sir thank you
@PavanKumar-xp9ik3 жыл бұрын
Sir in slope deflection eqn how at Mbc taking hinge Plz reply anyone why can't we do same procedure as we did
@Civillearningonline3 жыл бұрын
Here is your answer. We need to use that equation when our hinged support is at the end of the beam. If we use the same equation then we will have one variable more than the number of equation.
@Civillearningonline3 жыл бұрын
And to prevent the solution getting lengthy we use that equation. And it is easy to recognize whether the support is hinged or fixed just by observation.
@Civillearningonline3 жыл бұрын
Here is my another video on slope deflection method here i have provided all the reason of using that equation , recognizing the fixed and hinged support as well as the problem that we face if we use general equation of slope and deflection. If yuo still face any kind of difficulty then let me know. Fell free to ask. kzbin.info/www/bejne/p4KkonqYgJZsi6M
@alaganijagadeesh13683 жыл бұрын
Sir, for simply supported using formula 3EI/L... we get other valves of final moments and for simple supported using normal formula 2EI/2... Getting different values why?
@shreyashsaxena25683 жыл бұрын
Sir why was the expression for Mbc different that the other expressions
@Civillearningonline3 жыл бұрын
It's because our support C is hinged and lies at end. Do follow the step shown in the video whenever this case arises. It reduces one unknown and the solution becomes easy.
@gururajln2823 жыл бұрын
What about joint "C"
@Civillearningonline3 жыл бұрын
Here in this numerical joint C is hinged support. And always remember that we apply the condition "equilibrium of joint" only at intermediate supports. Here in the figure you can see that only joint B is intermediate and the joint A and D are lying at ends. And if there were given one more intermediate joint(D assumed) after joint C then we would have applied one more consideration taking the equilibrium of joint C. I hope i am able to clear your doubts.
@Adi-dl9vu3 жыл бұрын
@@Civillearningonline Is joint d is continuous...if not then we taken as joint na..
@gururajln2823 жыл бұрын
@@Civillearningonline send me your Email ID I have lot of doubts, in this topic, I will share that to you........ Plz 🙏🙏
@Civillearningonline3 жыл бұрын
civillearningon@gmail.com
@king.kundansahani23463 жыл бұрын
Nice
@Civillearningonline3 жыл бұрын
Thanks alot
@lakshmybiju85323 жыл бұрын
How did you find that the end C is hinged
@Civillearningonline3 жыл бұрын
It's clear from the diagram.
@Civillearningonline3 жыл бұрын
As you can see that the hinged support is represented by arrow.
@lakshmybiju85323 жыл бұрын
@@Civillearningonline then end B is also hinged am i right
@Civillearningonline3 жыл бұрын
Yes
@paruvumanoj81673 жыл бұрын
Sir how do you identified point B is roller and point c is hinged
@Civillearningonline3 жыл бұрын
If the support is represented as arrow then it's hinged and if it has a circle then it's roller support.
@paruvumanoj81673 жыл бұрын
@@Civillearningonline sir even though the point B is hinged we shouldn't use that equation...we should use that equation only for the 2 ndor 3rd span right??
@tlnnarasimhamurthy15293 жыл бұрын
How it will get 125? In step3
@akarshben49822 жыл бұрын
For point load..... WL²/8 ryt..... Or just WL/8...
@Civillearningonline2 жыл бұрын
WL/8
@hymavathi.v182 жыл бұрын
Sir was it only one hinge support at c?
@Civillearningonline2 жыл бұрын
Yes
@hymavathi.v182 жыл бұрын
Then at B was it simply supported beam
@Civillearningonline2 жыл бұрын
Simply supported beam are actually the beam having hinged support.
@Civillearningonline2 жыл бұрын
You will find this when you will practice some some numericals. It need practice and once you practice it's gonna be fun. Believe me😁
@victory_bestie45933 жыл бұрын
Sir iam not understand because your talking letters at below. So background are totally dark exact step are not visible to eye
@Civillearningonline3 жыл бұрын
Please check playlist you will find some other examples on this method. And i am sure they are going to help you alot.
@Civillearningonline3 жыл бұрын
Here you go. kzbin.info/aero/PL513Y7_xBTnAprzGbIpMFzGm-ju1ZiCuS
@powerstar763 жыл бұрын
Bro explain clockwise and anticlockwise direction
@Civillearningonline3 жыл бұрын
Clockwise means the movement which is similar to the movement of ⏰ like _ 1, 2, 3 and so on. While anti clock wise is movement opposite to the direction of movement of ⏰. Eg. 12, 11,10,9 and so on.
@powerstar763 жыл бұрын
@@Civillearningonline I mean in the problem Clockwise means +or -
@Civillearningonline3 жыл бұрын
Clockwise +ve and anticlock wise -ve if we are taking moment about RHS and ( clockwise will be -ve and anticlock will be +ve if we are taking moment about LHS.)
@akhilpp0093 жыл бұрын
What is diff between slope defln and kanis mthd
@Civillearningonline3 жыл бұрын
Kani's method: It is suitable for multi storey building. As there is no need of deriving equation and solving it. So it's time saving. While, Slope deflection: It is used to analyse both statically determinate and indeterminate structure. Considering deformation due to bending only.
@isolemayian61812 жыл бұрын
What if the other end was also fixed
@Civillearningonline2 жыл бұрын
Check playlist you will find an example related to that concept.
@paruvumanoj81673 жыл бұрын
Sir why you haven't find Mcb?
@Civillearningonline3 жыл бұрын
Moment at hinged support is zero.
@paruvumanoj81673 жыл бұрын
@@Civillearningonline sir point B also hinged then why we haven't kept zero sir?
@Civillearningonline3 жыл бұрын
But support B is at intermediate position.
@Civillearningonline3 жыл бұрын
Dear paruvu, I have created a seperate playlist on my channel for slope Deflection Method you should check out some other examples also. Then I am sure you will be able to clear all your doubts.
@powerstar763 жыл бұрын
CtoD not there? Lot of confused how it will get 125/8 &
@Civillearningonline3 жыл бұрын
I hoe you understand Hindi check out the playlist you will find some other examples of this method and they are going to help you alot.
@powerstar763 жыл бұрын
@@Civillearningonline no sir can't understand in hindhi only kannada and english but
@powerstar763 жыл бұрын
How it's came not understand
@Civillearningonline3 жыл бұрын
I will reply you shortly.
@srujanatenneti48273 жыл бұрын
How to do it when there is no simple support at C? Thank you sir
@Civillearningonline3 жыл бұрын
If there is no simple support at c or if there is fixed support at c then use the usual slope deflection formula and and there will be no need of providing free moment.
@srujanatenneti48273 жыл бұрын
@@Civillearningonline ok thank you sir
@Civillearningonline3 жыл бұрын
@@srujanatenneti4827 if you understand Hindi then you can watch my another video on same method and i am quite sure the these videos are going to be very helpful to you. Do check out the description section. Best of luck for your exam.
@srujanatenneti48273 жыл бұрын
@@Civillearningonline thank you sir. I do understand hindi.
@sabirsayyad81822 жыл бұрын
How to find support reaction in this problem can anyone tell me plz
@sabirsayyad81822 жыл бұрын
For last cantilever span only
@Civillearningonline2 жыл бұрын
If we consider only last cantilever portion of this beam, then it's reaction will be -6KN.
@michaelib70932 жыл бұрын
Sir, why is Mab negative
@lukmanopeyemi876111 ай бұрын
Anti clockwise moment
@shaanchutoori3 жыл бұрын
how do we know that “c” is hinged
@Civillearningonline3 жыл бұрын
Hi ged support are represented by arrow headed upward or triangular shape. Go through some problems which will help you to distinguish different types of supports.
@tiamiyuhamed93333 жыл бұрын
B is also hinged then
@Civillearningonline3 жыл бұрын
@@tiamiyuhamed9333 B is hinged in this question. We need to check whether the support at the farther end is hinged or not. That's it.
@haroonrasheed76974 жыл бұрын
In 14:32 how do u get 18
@Civillearningonline4 жыл бұрын
Hello dear, First of all thanks for your comment. Here is your answer, It has happened because of overhanging portion at support C. Your question is we take moment 18 at C. You will find your answer at 8:59 - 9:30. Do watch that step you will find your answer. Have a nice day....
@haroonrasheed76974 жыл бұрын
@@Civillearningonline tq so much 👍
@revanthl92763 жыл бұрын
How come it's 24/25 it must be 25/24 right?
@Civillearningonline3 жыл бұрын
Yes. You are right. Sorry for it.
@revanthl92763 жыл бұрын
@@Civillearningonline it's ok
@aktrending21363 жыл бұрын
Can you please explain step 3 I'm not understand how u get values EI (ib) 🙄
@Civillearningonline2 жыл бұрын
Simply solve the equation using calculator or manually by elimination method.
@rohitsukale94733 жыл бұрын
👍👍😊
@samiullahkhursheed81403 жыл бұрын
Sir how to get Deta A and Deta B in Casio
@Civillearningonline3 жыл бұрын
I am unable to understand your question. Please clearfy.
@Civillearningonline3 жыл бұрын
While solve equation we do not need to enter Deta in casio. There is another way of solving the equation in calculator. 1.Press mode 2. Press 5 Now Select the type of equation you want to solve. Now enter the constants.(i.e.numbers) Hope you got your answer.
@kavikavi47444 жыл бұрын
Mba +Mbc= 0 so how that 34.41 and 33.14 came. must be both same.
@Civillearningonline4 жыл бұрын
Hello dear, First of all thanks to you for your comment. You might have noticed that we have got (EI/ib) in all three equations. And we have calculated the value of (El/ib) using the portion AB of the beam. Also, I have not used Mba + Mbc = O here in this numerical. And that's why we have got that answer. And believe me it won't create any kind of problem. And one more suggestion to you to solve problems related to slope deflection method. Try to use both the equation i.e. equation for fixed end and hinged support whenever you have such questions. Because incase if u are using the same equation through out the the Numerical gets trouble some i myself have faced that. This was my first video on this topic. I will soon be adding more examples to clear ur all doubts so stay connected by subscribing @civillearningonline. And i will show the application of Mba + Mbc =O in some other example soon. Thanks alot for ur comment. Have a nice day.
@Civillearningonline4 жыл бұрын
I hope this video is going to help u alot. kzbin.info/www/bejne/p4KkonqYgJZsi6M
@Civillearningonline4 жыл бұрын
I have no idea whether you are familiar with Hindi language or not. Let me know by replying this. I am ready to help you out with all your confusion.
@kavikavi47444 жыл бұрын
im from srilanka . can you make moment distribution method little hard question in english. before 15th . i will share your video with my friends. thank you .
@Civillearningonline4 жыл бұрын
Of course I will. On each and every type soon.
@maniaanayak89193 жыл бұрын
Mcd=-6*2 kese hua thora bataiye
@Civillearningonline3 жыл бұрын
Because humar end c hinded he and support c k right pe overhanging portion bhi he so jab overhanging portion right side rahe ga then hum us k karan jo moment aaye ga usko -ve lenge and agar humara overhanging left side hota to hum moment +ve lete. I hope aap ko samajh aaya hoga. Best of luck for your exam. Description me aap ko 2nd example ka link mil jaye ga. Dekhlo wo bhi. Once again best of luck.
@kingsman58133 жыл бұрын
Yr sahi sahi likh ta kite thirty likhi jnda kite thirty nine
@Civillearningonline3 жыл бұрын
Bhai playlist check karlo ek video hindi me bhi he. Hope Ap ko achha lagega.
@Civillearningonline3 жыл бұрын
kzbin.info/www/bejne/p4KkonqYgJZsi6M Slope deflection method in Hindi.
@nijanthanperumal75162 жыл бұрын
talk loudly
@vedantauti2213 жыл бұрын
Vedant Auti 🦋 Roll number 26
@Civillearningonline3 жыл бұрын
#binod 😁😁
@Civillearningonline3 жыл бұрын
@Pratik Aute pratik auto😂😂
@Civillearningonline3 жыл бұрын
@Pratik Aute it's not so hard. You just need some practice. Prepare well. Best of luck.
@Civillearningonline3 жыл бұрын
@Pratik Aute well done 👍👍
@devanshipandya3372 жыл бұрын
👍👍
@byniritheshkumar90533 жыл бұрын
where is Mdc bro?
@Civillearningonline3 жыл бұрын
Span DC is overhanging portion and there is no support at D so there will no moment (Mdc).
@rohitdongare76233 жыл бұрын
Dongare Rohit
@Civillearningonline3 жыл бұрын
#binod 😂😂
@shaistakhan64764 жыл бұрын
Mcb/2=15 OR AAP NE 18 LIYA HAI...18/2....DON'T UNDERSTAND .......PLZ REPLAY
@shaistakhan64764 жыл бұрын
Or aap n 18 likha hai diffrence
@shaistakhan64764 жыл бұрын
formula mai aap n mcb/2 hai ....mcb ki value 30 h.... 30/2 lena hai to 18/2 kiyu liya hai....
@Civillearningonline4 жыл бұрын
Hello dear, Aap ka question he ki Mcb/2 ko 18/2 q liya gaya he? Ans: Humara jo support c he waha pe 2 moments aa raha he ek to point load jo span BC pe he and dursra overhanging portion CD. To aisa case me kya hota he ki hum total moment at C ko lenge ge. And is k liye C pe lag raha sara moments ko hum add karenge. And humne to fixed end moment at CB +30 calculate kiya he. And overhanging portion ka load 6KN , negative moment generat karta he at C and jab hum add karenge (+30-12) at C pe to wo humra total moment at C hota he . So Mcb/ 2 = +18/2 le te he.
@Civillearningonline4 жыл бұрын
Maine isi liye such type question kiya tah ta ki koi confusion na ho and yaad rakhna aap jab bhi overhanging portion aaye to us k karan jo moment generat hoga us ko hum include karenge.
@Civillearningonline4 жыл бұрын
Agar samajh me aagaya to reply ko like kardo aap ta ki muje pata chaljaye ki aap ko samjh aaya. And aap ko ek aur video mile ga same method pe hindi me aap us ko bhi dekh sakte ho.
@K1M012 жыл бұрын
Shhlurrppp ..........
@asifshaikrc27863 жыл бұрын
English aya tho baat kar bhai ni tho hindi may hi bol plz🙏
@Civillearningonline3 жыл бұрын
Ye lo bhai hindi bhi he kzbin.info/www/bejne/p4KkonqYgJZsi6M