Class 11 chapter 6 || Thermodynamics 12 || Gibb's Free Energy IIT JEE MAINS /NEET | Spontaneity |

[@PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 Chapter 6 | Thermodynamics Introduction | Reversible and Irreversible Process IIT JEE /NEET kzbin.info/www/bejne/p2ami4ikqLyej7M Class 11 Chapter 6 | Thermodynamics 02 | Heat | Concept of Cp and Cv Of Gas | IIT JEE /NEET | kzbin.info/www/bejne/jGSmf6l8iMlnqJo Class 11 Chapter 6 | Thermodynamics 03 | Work Done by a Gas | Work Done on a Gs | IIT JEE / NEET kzbin.info/www/bejne/onPYXoaAfbOpm6M Class 11 Chapter 6 | Thermodynamics 04 | Work done in Isothermal and Adiabatic Expansion of Gas kzbin.info/www/bejne/mImxqXV8d8uqoNU Class 11 Chapter 6 || Thermodynamics 05 || First Law Of Thermodynamics IIT JEE /NEET kzbin.info/www/bejne/gWLTf52BfdJ7bqc Class 11|| Thermodynamics 06 || What is Enthalpy || Relation between Enthalpy and Internal Energy || kzbin.info/www/bejne/i6a3Yn-EpZqGgLs 11 chap 6 | Thermodynamics 07 || Heat of Reaction | Enthalpy Of Formation | Enthalpy Of Combustion kzbin.info/www/bejne/hamqdoxjrsmioM0 Class 11 Chapter 6 | Thermodynamics 08 || Hess's Law || Hess's Law Enthalpy Change IIT JEE / NEET | kzbin.info/www/bejne/rafRhJKuosuFkMU Class 11 chapter 6 | Thermodynamics 09 | Second Law Of Thermodynamics Introduction | IIT JEE /NEET kzbin.info/www/bejne/l2imqXp3a9aEhqc Class 11 chapter 6 | Thermodynamics 10 | What is ENTROPY ? | Spontaneity and Entropy JEE MAINS /NEET kzbin.info/www/bejne/hJelY5aeqbisY6s Class 11 chapter 6 |Thermodynamics 11 | Entropy of different process | How to find Entropy JEE MAINS kzbin.info/www/bejne/lau8k42PYsyNj9k Class 11 chapter 6 || Thermodynamics 12 || Gibb's Free Energy IIT JEE MAINS /NEET | Spontaneity kzbin.info/www/bejne/pqevnoqwaNmKsJo

[@Ronik_thakur]

Sir aap best hoo duniya mai apse bdkrr koi ni pdaa skta love uh sir

[@Ronik_thakur]

Sir plzz 12th class ka bii start krdo sir hmmm sbii baccho ka future apke hatth mai hai

[@sushilsarkar5865]

Sir organic chemistry kab start hoga?

[@dilkiawaaz2491]

Please make video on log table.

[@aryanjain4191]

Sir plz General Organic Chemistry class 11 shuru krwa dijiye na jldi se. Plzz

[@sijjumaddela8717]

Rxn is in equilibrium 38:44 As we know T>dH/dS (then reaction is in spontaneous) Here 40.63kJ/mol then it is =40630 J/mol dG= dH -T(dS) = 40630 - 108.8 × 373.4 = 40630 - 40625.92 = 4.08 Here dG > 0 Then reaction is non feasible

[@nehawankhede5205]

Thank you

[@015priyamvadakumari8]

40.63 - 40.62592 = 0.03 hence ∆G = 0.03 means ∆G greater then 0 ans is b

[@nikitakumari1804]

@@015priyamvadakumari8 approx lenge... reaction eqm pr hoga

[@015priyamvadakumari8]

@@nikitakumari1804 nhi toh

[@abdurrafiquemollah8867]

It should be-4.08

[@siddharthjadeja6991]

2 years old but still powerful content 🙏 4 Years now, Thanks for the likes xD

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Not powerful , it is Thanos 🔥

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Koi content purana ni hota h bhai

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Old is gold holds good in this case

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[@e08aditijalan3]

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[@ShivamShukla-xl7em]

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[@KhushiKumari-ef4cg]

Yes

[@poojasingla8039]

Same here

[@Krishasushh]

4 years ago, but still no one can beat his explanation 🫡

[@darksoul6995]

stilll bro

[@Zerya-f1n]

Hey are these lectures enough for jee adv

[@shubhamsarkar6694]

Yess , for concept, but aapko question solving ability develop karna padega😊​@@Zerya-f1n

[@Rohan-sj8kn]

Still broo

[@madhushreesarkar8013]

Sir, I am a graduate enrolled in MSc now....and as the video is progressing....my regret is also growing... remembering the time when I used to struggle so much during my high school days with these topics and finally sat for my 12 boards leaving these topics. It would had been so good if I would have watched your videos then. You are excellent sir.... these topics are almost of no use to me now, as my subject is life science; but still I am watching each and every video on the topics that I once left in class 11 and 12 and those concepts remained boxed until now. I am watching these just for my own satisfaction. Once again sir....You are the best , best teacher I have come across till date.😊

[@sagargaur4203]

absolutely correct yrr mai bhi

[@velum6370]

@@vaishaligoel2321 english mein bakwas krne se yaha koi impress nhi hone vala. faltu ki baate kahi aur kre. uski marzi vo padhe na padhe. kaha kaha ke log aa jate hai negativity failana. jaake padai kro ms goel. you def need more knowledge and much growing up to do.

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OMG I cant imagine. So many grammatical mistakes. I mean , thanks for making me realize how much of English I actually know(LOL).

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You are ugly

[@bb-gb7jv]

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Try thermo mcqkzbin.info/door/F5ie8yBPVZxVAhx8jKWxtg

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Puri series dekha Kya 🙄

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Thermo me bas formule bahut hai, baaki kaafi asaan chapter hai

[@CristicMesper]

Yaa bro...... I want to say same thing also

[@CristicMesper]

@@doggee09 puri series hi dekhenge na

[@vineetapal8399]

22:14 , pada daadi wale aadmi time kam h 😂😂. Great teacher I have ever seen on KZbin. Thanks ALAkh sir for teaching us 🙏🙏🙏

[@parveenvij1830]

Mcqkzbin.info/door/F5ie8yBPVZxVAhx8jKWxtg

[@aim_mbbs_only]

Aapke jaisa koi nhi sir ksm se apke jaisa koi nhi... Ho skta h baki teachers ko apse jyada gyan ho pr uss gyan ko baatna sbse ache tarike se apko ata h... Aisa ek bacha nhi hoga jo bol skta h ki alakh sir ka pdhaya smjh nhi ata.... U r the best 👍💯

[@haroonshaikh369]

Answer at 39:03 •ΔG=40630-[(373.7)*(108.0) •ΔG= 4.08 = +ve •Therefore reaction will non feasible but if small amount of temperature of 4.08K is provided then it can be feasible.😀

[@arpitadeodikar5177]

same answer

[@riddhishete6563]

But the ratio delta H/delta S is coming equal to T then how is it non-spontaneous/ non feasible? Please tell..

[@YouTubeking-qe2yy]

​@@riddhishete6563fisible = possible = -∆G

[@abhikkumarjha8945]

No one can think that What he told in last 7 minute- "carbon reduction" ......is asked 2 times in JEE main 2020 in 2 different shifts...... ❤️❤️❤️❤️❤️❤️ A question from direct Notes

[@saatwikreddy9497]

Oh that's great

[@positiveperson789]

Jyadatar que .. Sir ke notes se aate hai agr dhyan se pura syllabus padho

[@naitikupadhyay9438]

Thanq Mai ignore kr diya thq

[@ms-wy6fu]

Video is of 3 years old ... according to that sir has said...but u are also correct

[@carl2226]

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Bruh

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Literally😂

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Pls tell me what is meaning of *_Lmfao_*

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@@shinchan4656 laughing my freaking ass off

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3 saal phle sir ne jo content diya Vo abhi bhi powerful content h Thank you ALAKH sir for this content

[@ishwaris.3689]

Sir....you are the BEST!!! A lot of respect for you!!!🙏

[@AnandKumar-ze2xn]

yaaa

[@varsharani5697]

U r right

[@vinod4672]

Madaer cheodh u are right

[@Thisuserlovescatssomuch]

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[@samarthsingh4453]

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[@praveensumanpraveensuman1792]

How

[@aatahumai7778]

​@@praveensumanpraveensuman1792 maybe boards?

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@@samarthsingh4453 in class 11th or 12th

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Hard work done by teachers for students always make us postive🤗because they supply energy by -🙏motivation, guide, provide education etc🙏🤗

[@namandhuaan5042]

At 38:42 , option b) non-feasible .Since, ΔG>0, ~4.08

[@HINDIMOVIEEXPLANATION-24]

wrong bro it is in equilibrium first you have to convert it in joules

[@namandhuaan5042]

@HINDIMOVIEEXPLANATION-24 bro i gave the answer in joules only ,... also bcoz it is in equilibrium , we know, T>△H/△S (then reaction is in spontaneous) Here 40.63kJ/mol then it is =40630 J/mol △G= △H -T(△S) = 40630-108.8 × 373.4 =40630-40625.92 = 4.08 Here △G > 0 Then reaction is non feasible

[@kyrafromhere]

​@HINDIMOVIEEXPLANATION-24 how will it be equilibrium if ∆G>0

[@yashpatidar654]

Alakh Sir is one of the best teacher That I have seen in my life Like for this beautiful teaching Always like his video It is only way that we can give him a respect Well done sir Bright future ahead Shine bright 🌞✨💛

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Sir ji aaj toh ek heart or reply banta hai

[@hamnekiya]

Chemistry wala

[@priyanshuraj7834]

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[@devansh6593]

@@Gayatrisinghkaushik chemistry

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[@pawanramnani8300]

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[@dev-lord]

alakh sir is only teacher that didn t ever said to like and suscribe his challen ITS SHOWS HIS GREATNESS AND IMPORTANCE OF US FOR HIM

[@adityaroy1317]

Answer is Non feasible means Non spontaneous..... Thank you so much for the amazing lecture ☺️☺️☺️☺️😌

[@bowtomepsi6302]

at equilibrium no?

[@AayushSinha-er1sj]

It should be equilibrium mann

[@thedamndoor45]

@@AayushSinha-er1sj ∆G≠0

[@dinkarpadghan6480]

@@bowtomepsi6302 40630 Is Delta H and T Delta s is 40626 There's 4J difference So not Feasible

[@vineetgaming5730]

Non spontaneous he is absolutely right

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[@Wtf_Ahmad]

More bro

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We are now at 1/2mil

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Rohit Mishra jee likne wale 15 lakhs hai na bhai

[@santokhsingh4734]

Thanks sir

[@nabajyotibora001]

38:45 Delta G=+4.08 hence the reaction will be non-spontaneous.

[@Im47_letscrackneet]

Bhai mera 400 ara hai

[@Sachinkumar30952]

👍

[@amancomputer4868]

​@@Im47_letscrackneetkilo joule ko joule me kR ke kro

[@daewanshbansal6173]

The reaction is non-feasible as deltaG is +ve.

[@Mr.noperfectionist]

I got the same answer is it +31.28

[@akashsahu7121]

I got +4.08

[@Mr.noperfectionist]

@@akashsahu7121 lol but being +ve matters

[@akashsahu7121]

@@Mr.noperfectionist hw bhai ji.

[@umesh22]

@@Mr.noperfectionist it's +5.

[@Innovativor_me]

Guys for all those who are confused between option C and B, the correct answer is C- equilibrium.. Try it, putting T=373.4 K And ∆H/∆S=40.63×10^3/108.8 You'll get it. Also in question itself it shows reversible

[@HoraceGudum]

Yes approximation se bhi equilibrium aarha

[@chhavimalhotra9774]

Answer of the question given at 38:45 is (B) : non-feasible. Also, I wanted to thank you Sir. Because of you, I am now confident while solving Thermodynamics questions. The way you make us understand the concepts is on another level. I don't know anyone else who can match that level of explanation. I am deeply indebted to you. May God bless you with all the happiness that you deserve in life!

[@Krishnash1355]

Yes

[@shivasai303]

Kya answer positive 5 aaya kya

[@shivasai303]

It is in equilibrium

[@yashwardhanmalviya9195]

@@shivasai303 no

[@yashwardhanmalviya9195]

Temperature is less than the required so non spontaneous i.e no feasible

[@rajkumarmukherjee9588]

Answer is 4.08. So, delta G >0 that implies reaction is non feasible. Correct option will be b.

[@ShivamThakur-fp1uj]

bro..since reaction is not feasible nd it is in equilibrium..means it remains in equilibrium..so option (c) is correct..

[@guddishaw3991]

The reaction is in equilibrium

[@pikachugirl2216]

But my answer is equilibrium

[@guddishaw3991]

@@pikachugirl2216 yes your and my answer is correct ✌️

[@krishthakkar6292]

Yes

[@kailash4551]

32:20 isko bolte h feel😈, great sir, mere coaching wale to ese relate hi nhi kr pate.

[@kommuravindra1752]

sahi kaha bro

[@Cosmoscuper]

6 years old but the concepts and way of teaching made this video alive for 100 years

[@RohitKumar.870]

Ans will be equilibrium. ∆H/∆S= (40.63×10³)/(108.8) i.e 0.3734×10³ = 373.4 Which is equal to given Temperature. i.e 373.4 K.

[@abhay.rijwani]

The correct answer is the process remains in equilibrium option c as the exact temperature for equation is 373.4375K and it is rounded off as 373.4 so just put the value of T as 373.4375 ....... it is for those people who got +4.08 as delta G ....

[@baijayantisahoo9603]

Yes & it's reversible also

[@hardjoshi2916]

you are best teacher in the world......... I study only by watching your vedio

[@ggboi1297]

Fail hona hai

[@hardjoshi2916]

Tere baap ki aukat nahi ki fail kar sake

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Me too

[@vaibhavchaudhary5715]

I think you have to work on our English Check out our video spelling, idiot

[@gyanp28]

@@hardjoshi2916 nice reply

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4 years old but no less than live interactive classes for students till date....Thank you so much sir for implanting in me a huge interest for this chapter....

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People who are watching in 2024 🗿🗿🗿

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Chad🧠🧠

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✋✋

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Me on 22 April 😢😢😢😢

[@TECH_TANTRA_GAMING]

1may

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3 rd may , preparing for neet 2024 😂😂

[@shivamsingh-ek8rl]

At 38:48, ΔG comes out to be +ve i.e., ΔG>0 which means the given reaction is non-feasible. G=+4.05 Joules. :)

[@niladribaksi6236]

Yup

[@helium3983]

No ∆G=-ve As 40630-10880×3734 =-40585290 Which means it is feasible!!

[@kkookkkoo2719]

@@helium3983 nope y'all..it's 108.8 J look properly and it's 40630 J Ans comes to be G is equilibrium

[@PhoenixPlays2]

@@kkookkkoo2719 bro it's non feasible* G =+ve as 4.08

[@kkookkkoo2719]

@@PhoenixPlays2 I don't remember it now lol

[@asifikbal2587]

Ans :(c) remains at equilibrium If {∆G∆H/∆S }then the reaction will be spontaneous but the T (temperature) is 373.4K , so that is why the reaction will be at equilibrium 👍🏻

[@bepassionate2026]

How

[@dreammaker2107]

Ur right bro

[@dipanshupandey7064]

no it's correct answer is non feasible

[@prakashroy9772]

Thanks bro your are right,I was confused

[@keyadas6322]

Correct answer c. For reversible reaction delta G=0 so T=∆h/∆s=373.4k

[@Rohtajjeeaspirant2946]

#38:45 Q(ans): (c) होगा, क्योकि T=∆H/∆G है ( feasibility ke liye ∆G

[@vsjasprayagraj9241]

38:46 Non-feasible

[@ranjeetkasana3535]

Mera answer h Delta G =+4.08 J/mole.. Hence, non feasible... 😊😊

[@souravsharma5465]

Mera ni aya..

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Mera bhi aya

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Sir , literally batata hoon class 10th tak physics bilkul bhi pasand nahi thi 😅😅 ....... ek friend ne apki channel recommend ki 11th me ab sach me physics se pyaar ho gaya hai ❤❤ thankyou sir 😍🙏🏻🙏🏻

[@armlink8354]

1:57 himanshi reagent 😇😇🤪🤪

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How lucky you are . Wow

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Khush hoja😂

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[@Rahul_razz13]

28:45 very sweet voice hogayyaaa❤❤❤

[@tiredcat6653]

The reversible sign doesn't mean equilibrium. We have not been provided the information whether ∆H has been given for forward reaction or the backward reaction, so if you solve for forward reaction and assume ∆H is +40.63, ∆S is 108.8 then you would get G as +4.08. But if you do it the other way round,means you take Ag2O as product you would get G= -4.08. Since we don't know in accordance of which reaction (forward/backward) the data has been provided,the ans, according to me, would be (4)

[@instinct4844]

Itna dimag kese laga lete ho

[@rahulsinghrollno50ee64]

Forward ke liye Diya hai backward me oxidation ho rha hai heat given by system -ve hota lekin positive Diya hai

[@tiredcat6653]

@@rahulsinghrollno50ee64 Yes, forward ke liye hi diya hai. Now that I have practiced a lot more questions ab mujhe smjh aa rha. G=4.08

[@tiredcat6653]

@@rahulsinghrollno50ee64 Btw oxidation is not always spontaneous toh aise assumption hme use nhi krne chahiye. Data is given according to this *Ag2O--> 2Ag+ 0.5O2* so we should solve according to the given data

[@Mahi_757]

​@@tiredcat6653😮

[@mohammadaunaisbhat1944]

Dad: kya kar rahe ho??? Me : padhai kar raha hu dad !!! Meanwhile Sir : Tuu hai ki nahiii .... Dad : haramkhor Ye padhai kar raha hai tu.!

[@anovie127ys]

😂😂😂

[@UNKNOWN_16]

Relatable 😂😂

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This video is helpful for everyone ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️👍

[@8c.riteshgope.329]

38:49 : it remains at equilibrium

[@exziteplays0001]

17:31 no sir. Your writing is kickass.we can understand easily

[@kumarsanu4191]

Answer is:Non-feasible(∆G=+4.08) Given in Q.:∆H=40.63kJ=40.63×1000J ∆S=108.8&T=373.4K By applying this formula:∆G=∆H-T∆S We get,∆G=+4.08 #∆G is +ve therefore this reaction is non-feasible/non-spontaneous.

[@aaryan2137]

Delta H / delta S =40630/108.8 =373.4 ( which is equal to T) Which mean (T=dlta H/ dlta S) That is the condition for equilibrium

[@teamblueocean6975]

At 38:46 G= +4.08j/mol Reaction-(b)non - feasible

[@allisarmishta4942]

correct

[@teamblueocean6975]

@@allisarmishta4942 thanks

[@SachinSinghpw]

Who still loves to watch alakh sir old videos ❤️❤️🔥🔥 👍👍👍👍

[@vinitabhardwaj]

Bro do u know me?

[@manaspremi37]

Meeh

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@@vinitabhardwaj yes

[@vinitabhardwaj]

@@SachinSinghpw hehe hi

[@TrainMania_12]

Are you from Aligarh

[@rishabhjha4304]

38:55 answer- (b)

[@buddy8998]

equilibrium Condition bro

[@deadcindrella1296]

It's equilibrium

[@rashwonsingkai7955]

It is at equilibrium.... See{ delH/delS} = 373.4

[@goutamdawar1m736]

Option 'C' equilibrium 38:45

[@thebradlad6215]

How plz update me...

[@goutamdawar1m736]

@@thebradlad6215 H/S is to temperature

[@anirudhmsomeshwara]

sorry but the correct option is (b)... because ∆G=0.004 not 0 therefore the reaction is non feasible👍

[@Future_iitian_]

38:47 c remains at equilibrium

[@Technicalsameerji]

Nice sir you are world best teacher😊😊😊😊

[@Technicalsameerji]

Right

[@izzatamin5997]

for the question at 39:00 delta G = +ve so reaction is non feasible.

[@mohitsangwan2430]

No Bro it is at equilibrium ∆G comes out zero and equilibrium sign is also there in the reaction😊😊

[@god-xm7th]

@@mohitsangwan2430 yes

[@positiveperson789]

@@mohitsangwan2430 yes

[@cosmichorizon405]

3, years previous lecture but the vibes is always exclusive❤️❤️ 💓Alak sir 🇧🇩

[@shakiibbbb]

Yaaa

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Sir, you are better than best,☺️☺️☺️☺️☺️😊😊😊👍👍👍👌👌👌

[@VaibhavKhatri-lv5wq]

Excellent explanation sirrrr 🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉

[@PankajYadav-kq7zo]

Mitar de has a separate fanbase❤️❤️❤️

[@plazmachazer8023]

Thank. You sir for your amazing work i am in my drop year and i cant explain that how much i needed this thermodynamics lecture Because aaj tak hum kahi se samaj nahi paaye the entropy, gibbs energy etc... Love from west bengal :) Thank you sir

[@sonuGupta-ju5ek]

I'm also bro. Isiliye to har din wait karta hu ki lacture uplode ho wo bhi thermodynamics ke upar.

[@marvelseries5457]

plazma CHAZER

[@plazmachazer8023]

@@sonuGupta-ju5ek yep brother ...

[@shreyagowdaabuddingdoctor7898]

All the best bro for your neet exam as a 12th studying student i know how challenging the situation will be while studying for neet and u have to prove yourself

[@tiredcat6653]

I literally commented the same thing. Very few people have the knowledge of this chapter and Alakh Sir is one of them.

[@AniketYadav-nr8tn]

38:50 rxn remains at equilibrium

[@Innovativor_me]

5:37 you solved my doubt ❤🎉

[@vaishnavirathore5266]

Not a celebraty not a player u are the person who is loved every where .... ❤

[@harisindhu704]

(c) at equilibrium is correct as if we check the value of ratio of delta H to delta S , it is equal to the given temperature value=373.4.

[@nancysingh174]

No bro the ratio comes out to be,555.42. so T is smaller than delta h/delta s, means non spontaneous

[@ashokaggarwal8727]

The correct answer of numerical is: b) non feasible Hit👍 like who got same answer Comment who got different

[@alipbhaumik6242]

It would stay in equilibrium

[@random_2016]

c.) remains at equilibrium ∆H/∆S = 373.43K

[@shivamtalokar272]

@@alipbhaumik6242 भाई कैसे रहेगा क्युकी del G examining 4.08 Bach Raha hai Del G = del H - T del S = 40.63*1000- 373.4*108.8 = 40630-40625.92 = 4.92

[@alipbhaumik6242]

@@shivamtalokar272 see...ur i have taken it out by the ratio process and the the value of the ratio del H/del S came 373.4375...thus i took the first digit without rounding off and del T came equal to del H/del S...if u also multiply 373.4375 with the entropy 108.8 the value Del G would be zero..so it was just a confusion based numbers after the decimal

[@pawan93133]

5 years now but quality just❤

[@prajyot2021]

At 39:00 option a is correct It is feasible as G

[@studywallah9642]

Re calcute bro

[@madhavmishra8951]

40630-40582

[@ayanbhunia4200]

sahi hai bro G= -40.58529 i.e G

[@AnkitKumar-zh4ou]

Mera b yhi aya h -40.5829 so it is spontaneous 👍🏼

[@shekharsuman3274]

At 38:46 Required temp. for spontaneity is 373.4375 and the given temp. is 373.4 which is less than the given temp, so its a non-spontanious reaction.

[@chakradityaa9748]

but nearly equal right!?

[@trishasarkar3053]

@@chakradityaa9748 i found the value of delta G, which is coming positive, so it should be non spontaneous

[@abhishekthenua6436]

I understood full concept of thermodyanamics

[@pwkasafar8147]

Alakh sir great ❣️❣️❣️🥺🥺🥺

[@gaganreddy5002]

39:00 Answer is C). Remains at equilibrium

[@rohan_n_out]

@Om Patil nope ....he is correct

[@ajaygojiyadadubhai755]

It is non feasible reaction... Delta G = +4.08

[@pavansai5513]

@Om Patil no bro check your calculations

[@ndalover_hindustanjindawaa3226]

Wrong

[@ndalover_hindustanjindawaa3226]

Ans is Non Feasible

[@ZeeshanKhan-qd1sd]

38:47 ans is (C) at equilibrium apply t

[@skull17377]

Its B

[@ZeeshanKhan-qd1sd]

@@skull17377 can u explain

[@skull17377]

@@ZeeshanKhan-qd1sd delta H is given in Kilojoule so 1)First convert kilojoule to joule 2)then apply T > delta H / Delta S u will see that T is less than Delta H / Delta S

[@ZeeshanKhan-qd1sd]

@@skull17377 got it thnks

[@gauravbhagat2506]

@@ZeeshanKhan-qd1sd because for equilibrium condition is T=∆H/∆T

[@kapillakhera6080]

1:40 Agar Suresh aaj itni padhai kar leta to Gibb's Free nahi Suresh Free Energy hoti😂😂😂😂🤣🤣🤣🤣😂😂😂😂

[@anant_gpt]

wow!!!! you r great sirji ........................ 1st viewer

[@reetasharma168]

Congratulations...................... Now study

[@pravartanshinde991]

sirji aap toh jadugar ho👌🏼apke wajese he chemistry me pass ho paya hu wo bhi sirf pass nahi aache marks bhi mile he You are great sir 🙏

[@Sahil-gb1jh]

Sir answer of homework question is Option B - non feasible As change in G is + 4.08 J / mole ( approx )

[@BaljeetKaur-ks3hu]

Exactly

[@satviksai1738]

delta g ki value kuch aur aa rahi hai +346 approx

[@Sahil-gb1jh]

@@satviksai1738 meri yahi aa rahi hai bhai

[@satviksai1738]

@@Sahil-gb1jh bro process likh sakta hai kya....plz!

[@Sahil-gb1jh]

@@satviksai1738 Non spontaneous

[@mukesh.Sharma7489]

38:40 change in G is positive so rxñ is non feasible 💖💖

[@122manishasahare2]

Perfect example of A perfect TEACHER 💯🔥🙌😇

[@parveenvij1830]

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[@m.sadikshaikh7687]

East or west Alakh Pandey sir is the best 😀😀😀😀😀

[@manojsharma215]

Best

[@poojaroutray2699]

Sir u are great....

[@narvadachauhan9500]

Y east y west he is one of the best

[@divyanshsharma4635]

Yes that's the fact. He is legend.

[@suraksharawat7542]

He is not one of the best...he is the only best🌼

[@arifamushtaq3931]

Thanks sir Bchu ka dard vohe smjta h jisne apni life mai b bht suffer kiya ho Love from kashmir due to strikes in previous years and now lockdown I was not able to study properly at home and tuition fee is too high but u helped in this harsh time thanks ❤️

[@iubaidkhan]

yes uh are absolutely right we had face a harsh time in our kashmir. this wil affect our studies a lot.

[@Omshashiranjan]

4 years old but still best content you can get ever

[@usharaothotakura7557]

∆G=∆T-∆S ∆G=40.63-(0.1088)(373.4) =40.63-40.62 =0.1 =0>0.1 So the reaction is not spontaneous or not feasible (Convert 108.8 J into KJ)

[@ThanksFor3Ksubscribe]

Hii If T=dh/ds Then this process will be at equilibrium See now T=373.4 Which is equal to dh/ds=40630/108.8=373.4375=373.4 So finally answer is a Option C Process 😊remains at equilibrium

[@Kanchan-s-q7s]

Your ,answer is not correct watch point you had given to your equation properly

[@soyaa5817]

@@ThanksFor3Ksubscribe WRONG .....

[@niharika5602]

You made things simpler and easier great🙏

[@shauryahindustanigamerz7445]

Remains at equilibrium

[@Us1489]

This channel deserves 10M subscribers. Sir aapke wajah se coaching walo ki waat lagne wali h

[@adiivibes9766]

Soon..

[@ViShNu_16]

bro predicted the future lolzzzz xD

[@kajalchakraborty6189]

The greatest example of randomness is to wake up in the morning and started eating 'chuhaa', 'hati', 🤣

[@nitinswami5538]

Unlogical

[@binay3347]

At 32:20 sir if T∆S > ∆H then it would be non spontaneous because non favourable condition is greater than favourable.

[@firefree9526]

Yes u are right

[@rai-here9090]

When T∆S is small

[@binay3347]

Hello friends I think you can also understand it like, in this case sir remark ∆H as a favourable so for spontaneous process it must be Exothermic so temperature must be lower than ∆H/∆S. Not greater than ∆H/∆S. What's your idea about it.

[@ubaidinamdar9535]

@@binay3347 for spontanity the overall value of dG should be -Ve So TdS must be greater than dH i.e T should be greater than dH/dS

[@binay3347]

@@ubaidinamdar9535 but for that particular condition sir given that ∆s itself negative.means unfavourable. Therefore for the spontaneity |∆H|>|T∆S|

[@keertiswarnakar1790]

38:38 Here, ∆G=∆H-T∆S ∆G=40.63 x 10³ - 373.4 x 108.8 = 40.63 x 10³ - 40.62592 x 10³ ∆G = 0.00408 We know, If ∆G > O Process is non spontaneous/ feasible. Hence, the given reaction is *non- feasible*.

[@neha-ps7wl]

But ∆H/∆S=40.63x10°3/108.8 =373.4 which is equal to Temperature then the rxn is in equilibrium

[@rabiyahassan513]

​@@neha-ps7wlsame

[@WASUQUOTES]

Feasible

[@skg2763]

😂😂​@@neha-ps7wl

[@asmityadav000]

Doubt

[@shubhangichaudhari8672]

Sir I'm really your great fan. Your teaching techniques are fabulous.

[@rahuldeo2487]

0:00 -10:38 ...kahani ab tak

[@bilalurrehman4796]

🙂

[@Joyboy.753]

Lol right

[@DivyaKaushik-jx9ic]

Crystal clear sir 🥰🥰🥰🥰🥰🥰🥰

[@SeemaSingh-oi6ry]

38:45 answer is option B) Non-Feasible with 4.08

[@thousandminusseven3889]

@PICASO ENTERTAINER but 40630 divided by 108.8 is coming 373.4375 so shouldn't the reaction be equilibrium

[@karunikja3339]

3 year ago.. Still best content. Jai hind alakh sir.. 🙏🙏

[@paritawanjari658]

Sir I m B.pharmacy student and preparing for GPAT entrance exam for PG ....your videos help me a lot in my preparation.I was sure that anything which I don't get by reading the book it will surely clear by your videos....In coming Months their will be my gpat exam....plz🙏bless me so that I qualify entrance exam...

[@paritawanjari658]

@Tanishq Saini yes

[@paritawanjari658]

@Tanishq Saini Thankyou

[@tinklebell233]

Thank u sirr aaj bhi utna he powerful hai ❤❤❤❤

[@aaryangarg1938]

38:45 Answer is (A), The value of G = -27 j/mole, Thank u Sir

[@nandurajiv1243]

B is correct.u r wrong

[@aaryangarg1938]

@@nandurajiv1243 How

[@nandurajiv1243]

@@aaryangarg1938 delta G will be +4.08j/mole.. so B is the answer

[@aaryangarg1938]

@@nandurajiv1243 show me your calculation, plz

[@spreadlovepeace1998]

Sir aj maine pure 13 lectures complete kiye ..3rd law ki video kab aayegi sir????

[@teqarine5752]

A chuki hai

[@statuslaga3944]

@@teqarine5752 kha hai bhai

[@Aspirantslifestyle1]

am also searching for that

[@poorvigupta2230]

Nice bro ek hie baar mae

[@YashSharma-bg4ys]

@@teqarine5752 kha h bhai

[@rishavmazumdar5651]

Sir thank you sirr.... ap great hoo...koi jabab nehi hai sir... god just

[@AdityaDixit-ck7dk]

All 2024 Aspirants

[@entertainmentenjoyfunny6770]

*Thank you so much sir this topic is very important for class 11 and 12 also*

[@sonuGupta-ju5ek]

Bhai 12th me kaise. Because mai bhi abhi 12th me hu

[@entertainmentenjoyfunny6770]

sonu Gupta Bhai chemistry me Chapter Electrochemistry and Polymersaur bhi kahi organic ke chapters me ye theory ka kafhi use Hai

[@sonuGupta-ju5ek]

Okk & thanks....

[@snsingh7528]

Entertainment enjoy funny sszz

[@heksqer1022]

@@sonuGupta-ju5ek In metallurgy and metal extraction, there is this part called Ellingham diagram, that part needs some prior knowledge of thermodynamics GIbb's constant. And Electrochemistry and Kinetics use the equation G = -RT ln(K)

[@meenaksahoo9462]

Thank you sir ☺️ for this wonderful explaination !!!