Class 11 physics chapter 6 | Work,Energy and Power 07 | Chain Problems | Conservation of Energy 2 |

[@PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. class 11 physics chapter 6 | Work, Energy and Power 01 | Introduction | Formulae for Work IIT JEE kzbin.info/www/bejne/bGa8pZaoYrCqm7M Class 11 physics chapter 6 | Work,Energy and Power 02 | Conservative and Non Conservative Forces| kzbin.info/www/bejne/gKm0Xoljrc2UfJY Class 11 physics chapter 6 | Work,Energy and Power 03 | Work Energy Theorem IIT JEE NEET || kzbin.info/www/bejne/aIaxqKdqh9KpgNU Class 11 physics chapter 6 || Work,Energy and Power 04 | Potential Energy IIT JEE NEET kzbin.info/www/bejne/h2rRh6GbYsmniqc Class 11 physics chapter 6 | Work,Energy and Power 05 | Equilibrium - Stable , Unstable , Neutral | kzbin.info/www/bejne/Z4WmoIxmlteKjpo Class 11 physics chapter 6 | Work,Energy and Power 06 || Conservation Of Mechanical Energy 1 IIT JEE kzbin.info/www/bejne/aIvak3xqoNiVjZY Class 11 physics chapter 6 | Work,Energy and Power 07 | Chain Problems | Conservation of Energy 2 | kzbin.info/www/bejne/j2K4oYOKZpeKqZY

[@baqarriyaz]

Sir aap power nhi pdhaaoge?

[@shyammishra1028]

Collision

[@patelshubham6313]

Sir Apne power related video nahi Dali he

[@c.vamshi9097]

Mechanical properties of solids, fluids, sir please only one chapter remaining

[@AfreenKhan-wn2mx]

Physics Wallah - Alakh Pandey sir power Nd collision pdhadijiye plzzzzz🙏🙏🙏🙏🙏🙏🙏

[@HarshitaNITSXR23]

first, when I searched for science videos solutions I rejected his videos by seeing his video thumbnails but now I love him wholeheartedly now my mind never agrees to look for some other channel love u sir u are a miracle

[@seesshhhh2371]

Kyu bhai baaki sab ke thumbnail me kya chhand taare dekhne ko milte h 😂😂😂

[@dubeyarts8661]

@@seesshhhh2371 😂😂😂😂😂

[@dubeyarts8661]

Ha bro mai bhi nhi dekta tha pehle pehle but ab pura is pr hi depend hu

[@arpandavid1591]

Pucha Kisi ne?

[@dubeyarts8661]

@@arpandavid1591 tere se kaun pucha re ....

[@ashokkumarsaxena7867]

40:49 the answer will be - umgL/2(1+u)² Since integration of xdx is x²/2 and minus because friction is acts in opposite direction to movement of Chain so it's work done is negative Nice lecture anyway Thanks sir

[@keshavjha4090]

Yes 1/2 ,...... But not negative , see carefully the limits Sir has taken ; it's 0 to ( ) in the direction of friction. So sign is correct .

[@SaniyaIIT-BHU]

@@keshavjha4090 perfect!

[@rinkuvalmiki8870]

@@keshavjha4090 gaming hunter is correct! As the friction force makes angle of 180° with the displacement of chain. Also in dot product of vectors of frictional force and of displacement, cos(180°)=-1

[@Dr.anjaliverma1]

@@keshavjha4090 ooo i see....that's why he didn't take the negative sign!!

[@anjanibhatt9953]

The correction is.. We will intergrate eq d f=UMdxg/L The limits will be from 0 to (L/1+u) So after integration f=uMg/(1+u) Now W=f.s W=Mg/(1+u).(L/1+u) W=uMgL/ (1+u)^2 Answer will come in -ve if friction and displacement are in different directions

[@anonymousakj9056]

HC VERMA - The person who taught India Physics ALAKH SIR (Physics Wallah)- The person who made Physics simple😊 THANK YOU SIR

[@aman0977]

Fir g mara

[@truth_4]

Aur bhartiya Rishi muni who taught physics to world

[@waltersike]

​@@aman0977haha

[@A_N_S_H__007]

​@@hardykmahendru5379tere mae jada akal hai.... Ncert bn rhi hogi comment likhwalo en chuninda quality ke khacharo se

[@tryesports9482]

​@@truth_4Never heard of his name

[@anjaneyamohapatra9124]

the problem I was always confused and worried about... the chain-on-the-edge problem... how easy!

[@glitched_matrix44]

Same. Sir makes it so easy..

[@ink_heart02]

Yaar koi batayega ki sir ne power ko kaha explain kiya hai

[@glitched_matrix44]

@@ink_heart02 nhi karwae hai shayad.... mujhe toh koi video mein nhi mila

[@ink_heart02]

@@glitched_matrix44 mere ko bhi

[@JetPen]

@@ink_heart02 nhi hai Power ka video. Arey yaar book se hi padhlo. Asaan hai

[@mahaveermarata1919]

Next HC Verma of India!!!!! Salute sir agar aaj sabhi jagah "education" aisi mil rahi hoti toh students ko koi fikr nahi hoti :D But God sent you for us, love u sir

[@satyam16]

Sahi Bola bhai

[@ravindraradder]

Sir plz teach maths for IIT also 😅

[@aakanshasingh1865]

True

[@rheareji9284]

He is the first Alakh Pandey not HC Verma....

[@dhruvchouhan6305]

Kya tatti h be ye, jee advanced se hota h IIT me selection ye toh board level se Ganda padha rha h

[@horizonr639]

40:14 sir o W(f)=-(uMgL/2×(1+u)^2) hona chahiya🙄

[@rajappajamadar5108]

Mai BHI vahi comment Karne aya tha👍

[@inderjeet363]

sir qestion2solve kar do last video ka

[@vinodjoshi8035]

Yes i agree with it

[@atharavathite2677]

ya broooo sir have might forgotten same

[@sumitarchives]

@@atharavathite2677 pata nahi sir mistake bahot karte hai

[@gunjeetbrar7229]

sir isn't work done by friction= uMgL/2(1+u)^2 Instead of uMgL/(1+u)^2

[@pratikdhembare5405]

Shubham Jha yes you are right

[@prachirastogi7255]

m b itni der se yhi sch rhi thi ki sir 2no ques m yhi likh rhe h

[@umesh83013]

Ji ji

[@prachirastogi7255]

@Aman Dhattarwal glti insaan se hi hoti h

[@sohail0506]

Yes u r right bro!!

[@thecalligraphist6457]

All I can say is 'THANK YOU so much' Sirrr!!!

[@shreyadeshpande1025]

Kehete hai ke baccho me bhagwan hota hai .. Toh sir करोडो bacche aapke liye hamesha achhi dua karte hai .. Hame गर्व hai ke aap hamare teacher hai❤️

[@arsquad]

Sirji Form Mei Hain 🙌

[@darshansharma3060]

hii bhaiya kese ho

[@SumitSharma0_0_7]

Bhai dono form mei ho bsss pyaar mohabbat se raho aur sir concept samjhaenge tum tricks.......................

[@ashuverma708]

Nice gesture AR sir

[@dehlanshandirkayr6182]

😊

[@PhysicsWallah]

Aayush Rathi Thanx Ayush Rathi , Aapka comment dekh kar Khushi Hui . Aap bhi Form me hi Rehna..students Love you!

[@frolictalks]

Sir please teach Power. This is also a part of JEE NEET syllabus. Please make video soon on POWER

[@shreyansh3956]

hn yrrrrr powr nhi pdhaya sir ne😭😭😭

[@ashishjoshi996]

Thanku so much mujhe yaad dila diya:>

[@Arpit_Maurya]

@@shreyansh3956 umeed series me padha rkha h 2nd video m

[@induja1687]

​@@Arpit_Mauryathanks

[@momskitchen9979]

​@@Arpit_Mauryapr alakh sir ne nhi padhaya vo

[@biologybyvg5255]

Never thought studying physics could be this fun 😋.... All credit goes to you

[@sciencelover3345]

Best chain related questions kzbin.info/www/bejne/j2fGaZ16a7Bohs0

[@fl4kesop]

chapter's name - work energy and power power karaya hi ni aur kehte kota ka education free me😂😂 UNACADEMY IS ALOT BETTER

[@kk6872]

Is this concept helpfull for neet..

[@vijayathota8512]

@@kk6872 yup if you solve HC Verma then it is helpful (it is basically to make your base strong)

[@SunilKumar-le1ju]

Sir, you haven't included the topic - Power !!

[@Prateeeeeksha]

A lakh sir on youtube can't teach like alakh sir...much respect🙌🙌

[@aiimsaspirant6200]

Kya ye neet ke liye sufficient hai?

[@Prateeeeeksha]

@@aiimsaspirant6200 isi concept ki questions practice karna..sufficient hai

[@ghost..-659]

What the concept ar given!!!! Most of 90% question of HC VERMA & D MUKHERJEE have solved. Thank you sir ji..🙏🙏🙏

[@Nothingeverything192]

In which class u are?

[@lifestough2546]

Yeh failure hai bancho 😂😂😂

[@aaliyaquiyum4801]

@@lifestough2546 🤨🙄

[@lifestough2546]

@@aaliyaquiyum4801 kya huya ?

[@kaizen3876]

most of 90% is less than 90%

[@abhaykaushal6707]

Sir you are great really aap hamare liye free me itna kuch kar rahi hai aur Humse fees nahi le rahi hai Yeh Baat Mujhe aap ki bahut inspire karti hai Aap apna kitna time Hamare laga rahe jo aap ki video baache apna future Bright kar re hai uski Keemat KZbin nahi de sakta It is priceless

[@Indaweer]

really guys sir really helped me a lot to clear my backlog, now really i can solve these type of questions confidently thank u sir, we love u

[@Medico890.]

Sir plzz Values liya kijiye plzz usee ziyada ache se smjh ata hai

[@aptryx685]

sir in the question at 40:00, integration of xdx is x2/2 so the denominator will include 2 as well no sir? But the concept was , is and will be as clear as it can ever get, thank you sir, for paving a path to many students like myself. Your old videos provide just as much content as there exists.

[@crimsonitegaming8072]

I was thinking about it as well

[@zoyaafroz8018]

Yes even I got the same answer as yours. But my other doubt's that why didn't we put a negative sign in the formula work done by friction, since force of friction and displacement are opposite of each other.

[@hamzaansari811]

@@zoyaafroz8018 big brain time

[@zoyaafroz8018]

@@hamzaansari811 What?

[@hamzaansari811]

@@zoyaafroz8018 nothing....

[@pirateflexpool6395]

39:47 work done by friction is (mgl)/ 2(1+u)^2 . thank u sir

[@arpankumar4090]

Work done by friction is also negative which sir has left

[@lakshmikushwaha123]

@@arpankumar4090 👍

[@asifiqubal7923]

Sir I like you more than my resonance faculty I and about all my classmates are watching your videos. We are big fannn of you Sir I request you that sir you give examples to solve us and teach how to solve numericals but please add a answer page with examples.......Please

[@aadyasingh7246]

Same I am also from Resonance

[@xlr8_bs514]

For anyone wondering, in 40:00, the answer will be -μMgL / 2(1+μ)^2

[@prostylegamer]

Me also confused 😂

[@aboombalakaka2045]

Thanks dude

[@phoenix.nix4]

28:50 Option d. Sir, maine thoda sa hint liya thaa ki table ke oopar maas kitna hoga aur table ke neeche mass kitna hoga ☺

[@inspiroygg]

the answer will be - umgL/2(1+u)² Since integration of xdx is x²/2 and minus because friction is acts in opposite direction to movement of Chain so it's work done is negative

[@ZXSAMOP]

is this really correct please tell.. because other comments are telling something else this is so confusing help :(

[@tryesports9482]

​@@ZXSAMOPcorrect bro you find it now right?

[@epikherolol8189]

Are Bhai sir khud kehte hai na "agar calculation mistake huyi toh maaf karna concept yahi hai" Hes here to teach us concepts...

[@SanaAli-jm1bg]

Sir Dil se Dua nikalti h apke lye...un bacho ki trf se..Jo coaching fee afford Ni kr skte...

[@heartlessboy5772]

World best teacher award goes to pw urf alakh pandey

[@imsumitbhade]

That feeling after you complete all physics lecture by him😍 Thanks a lot sir❤

[@kishujaiswal8603]

have you cracked neet and are u able to solve all que of phy and pls guide how to study phy its sucks for me'

[@theanalyzer2390]

39:08 X ke integration ka upon 2 reh gya Aur work done negative hona chahiye na sir coz friction is acting in opposite direction

[@rohitfaujdar7199]

but limit of the intergration is towards friction ... perhaps

[@ayushigupta1402]

@@rohitfaujdar7199 Plz tell me mujhe samaj nahi Aaya Tumne Kya kaha plz plz explain this

[@ayushigupta1402]

Ye Mera bhi doubt hai

[@theanalyzer2390]

@@ayushigupta1402 MERA DBT CLEAR HOGYA... SEE WE HAVE TO FIND THE WORK DONE BY THE FRICTION ON THE CHAIN WHICH IS CAUSING IT TO SLIP AND NOT OF THAT ACTING ON THE GROUND IN THE OPPOSITE DIRECTION OF THE CHAIN...I THINK.

[@whitetiger9351]

Yes work done by friction is negative

[@abidmalla7883]

at 39:12 the work done by friction =mgul/2(1+u)sq as sir accidentally wrote xsq istead of xsq/2 during integration

[@Satnam7275]

At 46.56 integration of X = x^2/2. Sir u forgot to divide by 2. Just an observation. But I love the way u explain the concept.

[@AshishYadav-zb4xv]

Focus on concept not in calculation

[@Satnam7275]

@@AshishYadav-zb4xv Yes Boss. I have agree to what my boss says.

[@siddhanth9596]

Guys, are the limits of integration wrong. Do we get different answers for last 2 questions?

[@halwapuri9179]

Bhai minus bhi hoga na wf toh ulta hai displacement

[@MSGaming_1234]

Yes i also noticed that just divide the answer by 2

[@shivamrana4633]

U r doing well sir.aap bahuto ke future savar rahe ho.god bless u sir

[@The5amclub345]

The moment when you solve the last question damn easily...... What a moment.. All because of this amazing human being.. 💜💜💜💜💜💜💜 사랑해요 sir

[@sam-12145]

Are u watching ummeed series?

[@The5amclub345]

@@sam-12145 no

[@sam-12145]

@@The5amclub345 . Ok but why.?

[@wanie4540]

💯 Right

[@elite7585]

are you a korean?

[@rhythmsaini4972]

Sir ur lectures are just superb..... firstly chain questions were most difficult questions for me but now they have become the easiest one

[@aspirant7585]

Finally done with work power and energy .......... Loved this series and Excellant explaination by you

[@mamtagoel4812]

43:35 After calculating and simplifying V= root ( gL/1+u)

[@mahipriya2267]

Ya I got the same

[@funnygyan4967]

@@mahipriya2267 apane work done by friction ki value -ve le h kya

[@atharvbangale7776]

in this whole chapter videos sir has taken 50 question of different variety hats off to you sir

[@manabsaha2733]

Nice...but "hands off" 😂 😂😂

[@sleepyfella]

Chakke 😂😂😂👌👌

[@AryanKashyap-12]

Finally I watched all videos, of this series

[@vivekpatel7452]

28:45 ans is option (d ) ✍️ Thank you sir ☺️☺️☺️☺️ Kaun is video ko 2023 me dekh rahe hai ☺️

[@thekidmagician7920]

Homework Answer - μL/1+μ (Option D) Thank You very much Sir.

[@mritunjay2624]

Small mistake @ 39:17 it should be uMgL/2(1+u)^2 i guess...btw thanks sir !

[@LearnEverythingPlus]

yes

[@anujnanda9440]

Yes

[@everythingreal6780]

Shi h bhai integration m mistake h sir ki

[@mritunjay2624]

its been 2 years since i commented this so idk

[@raghibumar4488]

@@mritunjay2624 why square in denominator

[@jeeinfo5489]

Sir, m a fiitjee south delhi student and i must appericiate ur work, this is the best lecture on chain problems, yes better than fiitjee, salute to your teaching way....love u alot.. Fiitjee me abhi online classes chal rhi h zoom pr usme sir pdhate h, yes pattern of study, study package,and time table is best in this period..but teachers r not very determined...they r not clearing each concept.. But ur lecture is great and one of the best..thanku for this

[@rahulk1370]

Sir Love You A lot ❤️ I don't know who else teach with free cost at this top quality of physics and easy method of solving! I really able to solve problems easily sir ! Tq a lot Even though I don't know hindi I understand you concepts sir Love From Tamilnadu ❤️

[@Arya-fr4sn]

Great sir thank you so much love from bottom of my heart

[@bilalbhat8600]

Sir.. you have done very much hardwork for us.. May God bless you and wishing you a very happy life forever ❤️

[@devgupta8137]

Apne to advance level tk k bhi padha diya sukriya apka

[@arindammandal6110]

congratulations on your completing the chapter

[@spider-man6932]

@꧁Kashi♥The ༒badmaash girl༒꧂ it's easy topic tho , there is Rohit Sir's video on this channel on power , pace series

[@parthsrivastava570]

15:28 sir ne jo derive kiye wo sir ne potential energy jab padhaya tha tab v kiye tha, who saw 😀😀😀😀

[@killuazoldyck5864]

Yaa I also saw that video of p.e

[@subhranshujena2743]

Waha par chain k length pir/4 tha yaha pir/2 h par value same hai,,, amazing😴

[@arcanesage2531]

05:52 Conservation of mechanical energy and its application in problem solving 11:44 Discussion on potential energy errors 17:36 Applying conservation of energy to solve for speed and potential energy 23:28 Deriving the mass and potential energy of a chain in a semicircle. 41:04 Finding work done by friction when chain slips off completely. 46:56 Chain slips off the table - finding velocity and work done by friction

[@deadshot8371]

sir in the last few questions Work done by friction is actually uMgl/2(1+u)^2... and thanks alot sir for this amazing video

[@GOOGLE.Earth1]

39:06 mai x²/2 hai na integration toh woh 2 kaha gaya[mewMgL/2(1+mew) ²] hoga na koi batao

[@Anonymou247]

Stay blessed, sir!

[@anupmogaveera3833]

40:14 work done should have been negative right? Friction force and displacement were opposite in directions.

[@cn-uy7yv]

Sir Kya dhasu samjhaya 1st question mein hi ... Maine to chain wale problems dekh kr chorr hi Diya tha ki kabhi solve bhi hogi 😒 par aab Crystal clear sir😄

[@chitra2965]

28:35 Anwer is option 'D'

[@anuradhadeka8446]

28:56 Option (D)

[@deepanshu4694]

Wah sir ak din me 2-2 vidio 🤩🤩

[@nareshsir1974]

Woo bhi kya din the

[@noxusfumes3628]

@@nareshsir1974 ha bhai ab toh 1-2 weeks mei ek video aata hai😅

[@daksheshgupta4192]

Acha h 2 video h Beasause syllabus early complete Rivision time jayada hoga na phir 🙏🙏🙏

[@-normal_guy.]

Sir maybe on 39:22 in denominator of answer there will be 2 It should be uMgL/2(1+u)^2

[@pankajkumar-vz1ti]

28:51 Answer. Option D. Thankuu sir ji. 😇🙏 .

[@smrtghosh5072]

At the end of the video , just realized that the whole video was set up in such a way that the last question doesn't seem hard. I mean all the concept required in the last question was slowly slowly discussed in previous questions. At first how much length should hang , then friction was introduced and at last this.

[@epikherolol8189]

Yes to create confidence for students like me!!

[@vipinkumarsingh8965]

Sir you are god of physics

[@shashikant8491]

is power left?????

[@rubikscuber1114]

Virat Singh power is rate of doing work P=dw/dt=F.dx/ft =F.v SI unit: j/s or watt Just use this formula u can get all questions asked from power there is not much part of power in WPE

[@aarfeenanees9147]

@@rubikscuber1114 thank you!

[@rubikscuber1114]

@@aarfeenanees9147 ur welcome

[@asmitabhujel3697]

Also note: Power of human heart=(Blood pressure×Volume of blood)÷ time taken 😊

[@priyanshugiri19]

@@asmitabhujel3697 Thanks 😊

[@satendrayadavyadav2076]

You are the god of physics thanks sir mere concept kiliyar ho gaye

[@otaku_5627]

RIP spelling 😔

[@eswarawakasimonsahith]

At 39:00 there should be a 2 in the denominator for the formula of work done.... Okk we can make it sir

[@yakeenian-nf3zz]

Yes ...there should be 2 in the denominator....

[@yakeenian-nf3zz]

We are thankful to you PW SIR...for making us that capable to knw whats missing...❣💖

[@detectiveonline2008]

Correcting the last question, First off all the work done by friction is negative, the upper limit is 0 and the lower limit is L/1+μ , and later because of integration of xdx , we get x^2/2, so the problems lead answer should be like -μMGL/2(1+μ)^2 = (1/2MV^2 +MG(L/2)) - ( 0 - (μM/1+μ)g(μM/2(1+μ)) hope this helped anyone looking for the correct answer for the last q Have a great day l3

[@AkashKumarGautam-ib6uf]

u are correct 😊 dost

[@AkashKumarGautam-ib6uf]

lekin height Mitra ye hogi........μl/2(1+μ)

[@harshvaidya3787]

Q1 3:40 Q2 10:00 Q3 20:20 Q4 26:40

[@cj-nv6en]

You made my concepts clear sir .Thank you very much✌️✌️

[@shaikmahammadyaseen3823]

At 39:47 Even Friction is variable I got answer by applying formula of work done by constant force

[@AarrtiManocha]

bro I also got the same ans just by muliplying f and s

[@avi-ka2193]

Sir At 39:52 W (friction) should have to be mu MgL/2(1+mu)² as the integration of x is x²/2

[@kaizen3876]

39:10 Integration of x is x^2/2 . I think he forgot divide by 2

[@aashuroy441]

Yes ...may be sir forgot about to devide by 2.... By the way the lecture was just awesome 🎉🎉🔥🔥🔥

[@srishtigupta535]

Sir, your teaching is awesome. We all love your style. But sir, please make a video on 'Power' topic also. We really need this.

[@sciencelover3345]

kzbin.info/www/bejne/j2fGaZ16a7Bohs0

[@pinkkitty6553]

39:48 sir aapne x the integration x² likha hai x² divide by 2 ayega. Answer mai divide by 2 laga lena friends.

[@Chillfully24]

Right

[@bhanumaggie1170]

40:14 instead of the integration, can we use w=f.s=u.mgs, by substituting m and l obtained in the previous problems. Is it wrong?

[@maharshinahar2794]

sir at 39:15 you should divide it by 2 because integration of x is x2/2 so you didnt divided 2...

[@kashish3809]

Was very confused . But now not that much confused . Thanks sir , for teaching us so clearly. Par abhi bhi physics hamesha upar se nikal jaati hai .😅😅😅😅😅😅

[@nareshbhaiswar9502]

Sir sorry for pointing out mistake but in 40:15 you mistakenly have taken integration of x dx as x ^2 it should be x^2 ÷2 ans should be ÷2 I try myself and got that answer please don't take it in other way I just comment to verify and thank you I am in class 9 and preparing for nsep and your lecture are awesome and helping me lot please continue and once again thanks

[@itditdvditdd4286]

Einstein= Alakh sir 🥰🥰🥰🥰

[@harshmaurya5884]

Bro don't compare anyone just study hard and don't let his hardwork be waste

[@shaikmahammadyaseen3823]

At 39:47 in denominator there should be 2

[@anjanibhatt9953]

I have a verified correction at 40:00 We will intergrate eq d f=UMdxg/L The limits will be from 0 to (L/1+u) So after integration f=uMg/(1+u) Now W=f.s W=Mg/(1+u).(L/1+u) W=uMgL/ (1+u)^2 Answer will come in -ve if friction and displacement are in different directions. Sir ne dw=f.x likha jabki f.dx hota hai.... Vahi se mujhe laga kuch galat hai Ye correction sir k padhaye hue sahi concepts se hi ho paya hai🙏🙏🙏🙏thanks a lot sirji

[@senpai2799]

han bhai muje bhu lga neeche 2 nhi likha sir ne

[@_her_diary28]

Thank you sir for such an amazing explanation!

[@madysaint8298]

sir you are savior for all JEE aspirants

[@308Manvithakur]

Sir plz make complete shot of work power energy.

[@parveenpatel5759]

at 39:14 is mistake of intigration of x dx limit 0 to L by 1+u

[@nanakchand5217]

Sir book gyan ka bhandar hai bus koi aap jaisa chaheye samjhane ke liye

[@harshbharate3255]

39:20 yaha pe xdx ka integration x²/2 he aur work done umgl/2(1+u)²

[@sameergupta6017]

Whi toh 2 kaha gya???

[@nishthadubey7800]

Sir please make a video on power also.. Its an important topic and my concepts are quite weak. Thank you :)

[@amar-theimmortal7994]

Sir in the last two questions I have doubt that the total work done by the friction should be -ve na. Because friction force and displacement is in opposite direction na. Although I know that it should be divided by 2 . Please clear my doubt sir.......

[@RaviKumar-zh3nb]

this I'm also thinking the same syd sir se chut gya ho maybe

[@mohdsaadkhan2936]

Yes I am also getting work done by friction = -uMgL/2(1+u^2)

[@jayshree6408]

Yes brother

[@RECIPE_BOOK.]

39:47 when we integrate 1/2comes out so 2 goes to the denominator so the ans was suppose to be umgl/2(1+u)^2

[@JeeStudy-j6t]

Yes u are right sir jldi m nhi likh paaye honge 😊

[@milan7130]

sir answer of the quarter chain at 24:12 is v= underroot rg[8+pie^2]/2pie

[@ukvanshop551]

In the second last question Integration of xdx is x²/2 but sir you missed to put 2 in denominator but sir this video's was amzing

[@zaidhassan1318]

Sir xdx ka integration x²/2 hoga na. To work done by friction [umgl/2(1+u)²] hona chahea na

[@sukamalshil2180]

In last 2year sir's nd our future changed alot ❤️❤️

[@nabanitakundu6761]

39:29 mein x^2/2 hoga THANK YOU GURUJI FOR CLEARING ALL MY DOUBTS

[@ipsitasarkar5176]

Hlw integration me hai nah friction k work done me right ???? Say plz 2 chut Gaya hai naj

[@nabanitakundu6761]

@@ipsitasarkar5176 haa wahapar x^2/2 hoga as integrate karna par raha hain

[@chamandeepkaur4014]

i can clear all my doubts through physics wallah

[@shaikmahaboobsubhani2784]

Arey Army Haiii yaar

[@chamandeepkaur4014]

@@shaikmahaboobsubhani2784 yes I am also a army

[@sarahwilliams7767]

@@chamandeepkaur4014 can you please tell me what youre getting for the last question?

[@rishabhkumar-mh9di]

sir u r the best,all concepts r cleared....love u sir just waiting for fluid mechanics......love u sir

[@krishnamurarisinha381]

W=uMgL/2(1+u)^2 At 39:04

[@s-_-r009]

YAHA PE (-) KA SIGN BHI TO AANA CHAHIYE NA

[@hiteshdave6122]

Online study for JEE and NEET k liye KZbin channel Suggestions??

[@harshitapandey2054]

Hitesh Dave Physics wallah for physics and chemistry is really the best choice.

[@kaustuvbaidya121]

Hitesh Dave , this is the best channel to sort out concepts

[@latakumari8571]

For organic chemistry and maths(basically calculas part) "THE ORGANIC CHEMISTRY " is the best channel ....

[@tatikshachaudhary374]

Bagal me chora shehar me dhindora... PHYSICS WALLAH ,,,ALAKH SIR....he is the one😺

[@swatik2509]

Physics wallah or unacademy.

[@rudherkamra3767]

40:00 there is also 2 in denominator

[@aniketkalra4352]

Yes sir

[@tanujgoyat1412]

I agree with you 😊😊😊

[@varun5086]

39:27 in denominator it should be 2(neu+1)^2

[@prathamgupta7730]

i think work done by friction should come with a minus sign in the expression where sir forgot to write 1/2 am i right ???????

[@maheshgoswami5420]

Ya

[@tannudahiya149]

Minus sign won't come here as we compensated it in integral limits...we took limits from 0 to (starting point).. which is already minus of displacement x from starting point

[@mazenahmad8658]

@@tannudahiya149 but we didn't put -ve in the limit

[@mazenahmad8658]

It will simply give us the work done and also analyse it logically. Acc. to COE Losses=Gains. The -ve potential energy is the energy it initially has, so it is lost. It gains KE, -ve PE as the chain goes down and heat is released as friction which is +ve when taken on the other side.

[@omdave1008]

@@tannudahiya149 Negative sign should come irrespective of putting limits