Class 11 Physics | Fluid Dynamics | #19 Solved Example-9 on Fluid Dynamics | For JEE & NEET

[@satyamsingh9492]

Thank you sir these videos really helped me a lot

[@physicsgalaxyworld]

Thanks for your appreciation Satyam, please subscribe and tell your friends.

[@satyamsingh9492]

@@physicsgalaxyworld sure sir😄

[@vasunith9682]

@@satyamsingh9492 this is not sir himself...you know...

[@satyamsingh9492]

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[@SoumilSahu]

I don't understand the procedure. On one hand, you have used Toricelli's equation, which considers the value of v1 to be 0, but on the other hand, you've not neglected v1 in order to find dy/dt. Why?

[@physicsgalaxyworld]

Here we are considering the area of hole to be very small compared to the base area of container...

[@anirudhvarma1815]

Sir if the area of the hole is negligible, why do we consider the velocity v1? Isn't v1 also negligible?

[@SheryanKumar]

​@@anirudhvarma1815 Since in the question they have given area of efflux as 'a', we will have to consider that the hole's area and top's area doesn't have much difference, therefore efflux velocity has to be taken into account here Hope this helps

[@TheVatane]

​@@anirudhvarma1815 Kucch bhi

[@Vishwa__222]

respected sir , The final answer should come as ...............( A/a)*[(H/g)^0.5](root2-0.5)..... maybe your final answer is wrong......... pls do reply if i am correct ......

[@kshitijvispute6792]

Yes

[@HarshvardhanNigam11]

sir thank you so much. really helped

[@tanishq9694]

How did you take the velocity of efflex to be root of 2gy, is it not true only when area of hole is

[@vanshmishra7119]

yeah its considered

[@kamisama7970]

Apply Bernoulli equation and then you will get v=√2gh

[@nareshsir1974]

YEAH YOU ARE RIGHT BUT WHEN WE NEGLECTED AREA IT IS FOR VELOCITY RELATION WHERE WE DID SQUARING SO SMALL BECAME MUCH SMALL,,HERE IT IS JUST ONE UNIT SO WE CAN CONSIDER THIS MUCH.RIP M Y ENGLISH

[@anirudhvarma1815]

First of all should it not be root of 2g(H-y), am I right?

[@satvik_srivastav]

@@anirudhvarma1815 no

[@anirudhvarma1815]

Sir , why is the velocity of efflux root(2gy) , is it not root(2g[H-y])?

[@seemachatterjee4389]

Becoz the free surface is at a height of y from the hole

[@SaurabhKumar-us3ty]

Here can we use v^2 - v1^2 = 2gH/2??

[@SumanDas-qs1qh]

Why -dy/dt y is also decreasing in downward direction

[@VARUN-pk7xq]

Look only dy/dx is decreasing becoz of the the water is getting out from the small hole so to show that it is decreasing we put "-" negative sign ,

[@tuhinanshuchatterjee4716]

Sir isn't the derivative of 1/√y = 1/2y√y? Sir you took 2√y as derivative of 1/√y., is that a mistake or ami I missing something?

[@mehak-rg9dz]

integration of x^3 is (x^4)/4 not (x^4)4, as -1/2+1=+1/2 it will come to be 2√y only.

[@skm5779]

why cannot root 2g(H-y) instead of root 2gy

[@osaidfirozkhan3505]

No because we are taking the height "y" above the cross sectional area and we know That H-y is the height above the ground and is b/W the surface of ground and cross sectional area (H-y) is the reference point in Bernoulli's theorem

[@skm5779]

@@osaidfirozkhan3505 😂 I have not expected answer after so much time. Thank You 😂 because physics is timeless.

[@someone-wp8dj]

@@skm5779 which college are you in now?

[@sonuarorafoamstore9778]

Sir From which book you take question.

[@stardustjr6898]

Thanks sir 😄

[@MacNDroidSolutions]

This is true when a

[@deependragaur4991]

Amazing🤩🤩🤩

[@suchitramaurya7457]

it is root2 only

[@physicsgalaxyworld]

it is √2 and it is already account and the final result is correct...

[@ayushsaxena1164]

Dear sir how v=2gy^1/2 , because sir here area of hole

[@physicsgalaxyworld]

v = √2gy is valid only when area of hole is very small and thats valid here... watch the previous videos in proper sequence for the derivation...

[@ayushsaxena1164]

@@physicsgalaxyworld alright sir😄🙂

[@hellobrother3173]

Sir suggest a method without intigration n diff.. Little bit confused sir please

[@vijayvyas5075]

i dont think there exists any.

[@Shivam-wg2dt]

Try to learn integration and differentiation.. You can't run from them if you want to learn physics.

[@benkenobi007]

Sir, isnt v1= (-dy/dt) dimensionally incorrect? shouldn't it be v1=A*(-dy/dt)??? thanks sir!

[@physicsgalaxyworld]

+KTiwari998 Here we are taking v1 as the velocity of the surface not the volume rate so this is correct...

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