Class 8 Maths | Sniper Series Part 1 | Equal Triangle | Easy Question | Exam Winner Class 8

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NMMS impotent Maths Question parayunna veediyo cheyyumo

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[@uchihaitachi5736]

Yes

[@vineethatg7803]

Yes. Meeto

[@shailan-xr7xj]

First comment❤🎉🎉🎉

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😂

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😅😅

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💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙💙

[@oppooppo1454]

< c=80 < Q=40 < R=60 By ASA

[@AdhilNajeeb-jv1kd]

three first comments nice

[@Niha.__346]

𝘍𝘪𝘳𝘴𝘵💗/𝘤𝘰𝘮𝘮𝘦𝘯𝘵/💗𝘵𝘦𝘢𝘤𝘩𝘦𝘳 𝘦𝘯𝘩 𝘭𝘪𝘷𝘦 𝘤𝘭𝘢𝘴𝘴 𝘦𝘭𝘦𝘦𝘺?

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First comment ❤

[@binoyjosephjoseph176]

[@dane7398]

< C = 80° < P = 80° < Q = 40° < R = 60° Correct aano??

[@binithavidyadharan5361]

∆C=80 degree (180-(40+60)=180-100=80 degree ∆p=80degree ∆Q=40degree ∆R=60degree (Opposite angle)

[@sujihari4530]

By SAS rule

[@nandanaa.s1261]

Opposite angle of AB =opposite angle of QR

[@MeMaMi0911]

By ASA

[@RejulaFathima-c4q]

Oru like thero 😢please

[@anushkam.b3369]

By ASA

[@shyjajose1219]

Miss asa principillil 40degreeyum 60degreeyum +cheythal 100kittille appoll 180ddegree yil ninne 100-cheythal 80degree kittile appoll two trianglesum equal alle matte triangleum ithupole cheythal nammuk answer kittile apoll two trianglesum equal alle

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😮

[@arathyhariharanr5125]

Angle c=80° Angle p=80° Angle Q=40° Angle R=60° Total ΔPQR = 180°

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Last comment

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[@indulekha6567]

By sss condition ∆ABC=∆PQR

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Good classes

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🎉🎉🎉

[@Sivadruma]

Thank you miss 🤩🤩🤩🔥🔥🔥

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Seventh comment 🎉

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[@ArdraSA-o4b]

IS THIS RIGHT 👇EVERYONE PLEASE CHECK FOR ME AB=QR[given] BC=RP[given] CA=PQ[given] Therefore, triangle ABC and triangle PQR are equal [SSS] Therefore,angle A=angle Q=40 angle C=angle P=180-[40+60]=180-100=80 angle B=angle R=60

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🎉

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Miss class okeyy super ahnuuu💗💗💗💗💗

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[@indulekha6567]

In∆PQR

[@rasnabinu2812]

32th comment😎😎

[@ummulfaseela129]

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[@dane7398]

< P = 80° alle??

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