Class 9 CBSE Maths | Chapter - 2 Polynomials Part - 2 | Xylem Class 9 Cbse

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CUBIC (x+1) (x+2) (x+10) Mibsam Thank you sir for teaching us❤

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33:15 That Motivation ❤️‍🔥❤️‍🔥❤️‍🔥🔥🔥🔥🔥

[@JeslynGigi-e3i]

Cubic (x+1) (x+2) (x+10) Jeslyn

[@Jopangaming09]

2)(3x-2)(2x+3) 54:09

[@landwivilasco]

Homework questions ; Anonymous :) P(x) = x^3 - 4x^2 + x + 6 g(x) = x - 3 P(3) = (3)^3 - 4 (3)^2 + 3+ 6 = 27 - 36 + 3 +6 = 27 - 36 + 9 = 36 - 36 = 0 Yes, g (x) is a factor of the given polynomial. Splitting the middle term 6x^2 + 5x - 6 Sum = 5 Product = - 36 6x^2 + 9x - 4x - 6 3x ( 2x + 3 ) -2 ( 2x + 3) (3x- 2) (2x+3) are factors of the given polynomial

[@SprootMemeGod]

if (2x+3) comes first as in (2x+3)(3x-2) is it still correct

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???

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😅

[@jobinjose2620]

1:06:59 -> cubic polynomial factorisation

[@naseelahamad5220]

Motivation 😂34:44

[@remya9020]

Cubic (x+1) (x+2) (x+10) Vedha sree

[@baabubeena8933]

Hw ans P(x)=p(3) 3³-4×3²+3+6 27-36+9 =0 X-3 is the factor of x³-4x²+x+6 Thank you 😊

[@AbhinavPillai-j1c]

Cubic (x+1)(x+10)(x+2) Ayana

[@Jopangaming09]

🔥🔥 17:05

[@shamnaareekkal4799]

Thank you so much sir 😊

[@Jopangaming09]

❤❤ 26:42

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Proud to be in Ninja Batch

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Cubic (x+1)(x+2)(x+10)

[@Jopangaming09]

15:43 15:45

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[@AmbiliRenjith-nh5te]

Thank you sir🔥🔥

[@abhirami.anamika1015]

(x+1) (x+2) (x+2)

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Lub you siirr , 💝😊

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[@AdarshOG_]

answer 0 of that h.w

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Sir cubic (x+2) (x+1) (x+10)

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1:06:59

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26:33 ❤❤

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🔥

[@AbhinavPillai-j1c]

Splitting the middle term question answer is (2x+3)(3x-2) Ayana

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Ichiri pathikeee para 31:51

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CUBIC (X+1) (X+2) (X+10).. 💚💚Proud to be a ninja batch student 💚💚

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Athrelum ondallo🔥🔥

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Yes

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Home work answer - 0

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1:18

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1:02

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[@zidan.in4k]

Homework answer kitti g(x)=x-3=0 X=0+3=3 p(x)=27-36+9 =36-36 =0 Hence proved that (x-3) is the factor of (x3-4x2+x+6)

[@Abhinavpkxd]

Cubic (x+1) (x+10) (x+2)

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1:18

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Cubic(x+1) (x+10) (x+2)

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