Class 9 Maths | Chapter 8 | Circle Measures | Xylem Class 9

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Maths Cristhumass examnte thalenn kanunnorndooo😌!

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AB=16Cm OB²=BC²+OB² OB²=8²+6² =64+36 OB²=100 =√100=10 (d=10 , r=5) P=10π A=πr² =π×5² =25πcm²

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Radius is 10 and diameter is 20

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P=20 cm aan...n A =100pie cm²

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Ans:Perimeter =20π Area=100π Thankyou sir for your wonderful class❤❤💚💚💚🥳🥳🥳

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29 _6 8.6

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Area =10π cm 100root 10 akum

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10π A 25πcm²

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It's wrong

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Ans: p= π*d =d=oc²= 8² + 6² =64 + 36 =√100 = 10 D = 10 R= (half of 10) = 5 P= π*10 = 10 π A= π*r²= π*5² = 25π cm² ❤

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Yes it is right. Vere palavarum p= 20π A=100π ennum aan parayunnath

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Ans: p=OB²= OC² +BC² =6²+8² =36+64 =√100 =10π A=πr² =π×5² =25cm2

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Superb ❤❤❤❤

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8:39 🔥🔥

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Perimeter = 20 pie cm Area= 100 pie cm² Thank you sir for a good class 👏 😊🎉

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Sir cls super👍 P=20π A=100π

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22:51 👍🏻

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P=20πcm A=100πcm²

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❤❤ A=52π cm² P=4×root13×π cm Very usefull ❤

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Ans perimeter = 10×2=20πcm Area =100π cm2🎉🎉

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Perimeter =20π cm Area =100π cm2 Thanku fufu sir☺️🎉🎉🎉🎉

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P= 20π cm A= 100π cm² Waiting for the next maths class

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P=20π. A=100π Superb class🎉❤🎉 Class enik nannayi manasilayi thnx fufu sir🥳🥳

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Perimeter = 20π cm Area = 100π cm² SUPER CLASS .😊 THANK YOU SIR

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A=100π P=20π

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P=20πCM A=100πCM²

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Perimeter 20π Area 100π

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Maths class 9(uumfiya avastha🥲👍🏻)

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സൂപ്പർക്ലാസ് ❤

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,,,,,,,,,🔥🔥🔥

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❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

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❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

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Pandavas🔥💥

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Perimeter=20πcm Area=100πcm² Adipoli class❤

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Kollam ❤