Lecture 06: The clipping algorithm and the viewing pipeline.
Пікірлер: 10
@prajwolgyawali67704 жыл бұрын
Camera Transform: 0:35 - 13:00 Image Space & Screen Space: 13:00 Alternative equation of plane: 22:00 Convex Polygon: 41:40
@MendesTV2 жыл бұрын
Whoa first time I try to understand from a course, and I got it ! good explanation, good smiles
@ZeroZ30o5 жыл бұрын
20:40 Clipping starts 36:50 How to clip a 2d polygon with a plane (have to know how to clip a segment, seen just previously)
@Nevarek_3 жыл бұрын
Divide by W is the new multiply by zero
@ramanasubramanyam11104 жыл бұрын
Hi. I've a question . Are the matrices C and V the extrinsics and intrinsics equivalent in Computer Graphics? C transfers to an arbitrary coordinate system, V performs perspective projection? Also, isn't [x,y,z,w] a homogeneous matrix?
@hanzo20019 жыл бұрын
31:50 _[...] I'm going to subtract P from both sides_ Somehow I - P = Q1 + t(Q2 - Q1) - P is the same as I - P = (Q1-P) + t((Q1-P) - (Q2-P)) Does this have something to do with the fact that _I_ is a point and _I - P_ is a vector?
@brokenopcode83818 жыл бұрын
+hanzo2001 (Q2 - P) - (Q1 - P) = Q2 - P - Q1 + P = Q2 - Q1
@bbit-solutions70046 жыл бұрын
Instead of saying you subtract P from both sides, you could also describe this step as subtracting P from each point to get the vector from P to that point. It should become more clear at 43:54, when using the origin (0,0,0) as P