Clipping

Lecture 06: The clipping algorithm and the viewing pipeline.

[@prajwolgyawali6770]

Camera Transform: 0:35 - 13:00 Image Space & Screen Space: 13:00 Alternative equation of plane: 22:00 Convex Polygon: 41:40

[@MendesTV]

Whoa first time I try to understand from a course, and I got it ! good explanation, good smiles

[@ZeroZ30o]

20:40 Clipping starts 36:50 How to clip a 2d polygon with a plane (have to know how to clip a segment, seen just previously)

[@Nevarek_]

Divide by W is the new multiply by zero

[@ramanasubramanyam1110]

Hi. I've a question . Are the matrices C and V the extrinsics and intrinsics equivalent in Computer Graphics? C transfers to an arbitrary coordinate system, V performs perspective projection? Also, isn't [x,y,z,w] a homogeneous matrix?

[@hanzo2001]

31:50 _[...] I'm going to subtract P from both sides_ Somehow I - P = Q1 + t(Q2 - Q1) - P is the same as I - P = (Q1-P) + t((Q1-P) - (Q2-P)) Does this have something to do with the fact that _I_ is a point and _I - P_ is a vector?

[@brokenopcode8381]

+hanzo2001 (Q2 - P) - (Q1 - P) = Q2 - P - Q1 + P = Q2 - Q1

[@bbit-solutions7004]

Instead of saying you subtract P from both sides, you could also describe this step as subtracting P from each point to get the vector from P to that point. It should become more clear at 43:54, when using the origin (0,0,0) as P

[@joepeters8746]

pls listen 43:15 in 25% speed, it killed me.