My alternative, neither as elegant nor fast, was to use GRASS r.to.vect, calculate areas and delete below a threshold, then delete holes (with threshold) before simplifying and filtering (with buffering thrown in for good measure). Thanks for the clear, and now obviously very useful, explanation.
@nicohockley Жыл бұрын
Amazing! Thank you.
@kortexfino3 жыл бұрын
hi dude, you said that radius = 2 is equal to a moving windows of 5x5. So, which is the size of the windows when radius is 3 or 4? thank you so much!