Codeforces Round 979 (Div. 2) || Editorial for Problem A,B,C,D

A. A Gift From Orangutan || B. Minimise Oneness || C. A TRUE Battle || D. QED's Favorite Permutation
contest URL: codeforces.com...
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Codeforces contest 2030, A Gift From Orangutan, Minimise Oneness, A TRUE Battle, QED's Favorite Permutation, Competitive programming solutions, C++ coding tutorial, Algorithm explanations, Problem-solving strategies, Educational Codeforces, Div2 contest analysis, Coding challenges walkthrough, Tips for Codeforces contests, Competitive programming techniques, Learn C++ programming, Coding skills development, Programming community insights, Contest preparation strategies

[@মোঃদুলালহোসেন-ট৫র]

Thank you brother

[@nicspyy]

@@মোঃদুলালহোসেন-ট৫র ✨✨ welcome

[@shashankvashishtha4454]

In problem A, the gift from some person 😁, it is not a person its orangutan (a smart species of monkey i think)

[@LDR_Crafts]

Solution of A - maxx = maximum value in a minn = minimum value in a ans = (n-1)*(maxx-minn) print (ans) 🥴🙌🏻

[@nicspyy]

@@LDR_Crafts 😱😱🥲👍

[@shashankvashishtha4454]

code explanation part should be very less, explain maximum things in dry runs and examples only.

[@mahfuzurrahman9307]

brother your explanation is good, please improve the sound quality

[@nicspyy]

A solution: void solve(){ int n; cin>>n; vi a(n); forn(i,0,n) cin>>a[i]; sort(a.begin(), a.end()); a.insert(a.begin(), a[n-1]); a.pop_back(); // for(auto i: a) cout